Genetic Analysis: An Integrated Approach (3rd Edition)
Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 8, Problem 25P

The accompanying illustration shows a portion of a gene undergoing transcription. The template and coding strands for the gene are labeled, and a segment of DNA sequence is given. For this gene segment:

a. Superimpose a drawing of RNA polymerase as it nears the end of transcription of the DNA sequence.

b. Indicate the direction in which RNA polymerase moves as it transcribes this gene.

c. Write the polarity and sequence of the RNA transcript from the DNA sequence given.

d. Identify the direction in which the promoter for this gene is located.

Chapter 8, Problem 25P, The accompanying illustration shows a portion of a gene undergoing transcription. The template and

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Given the template DNA sequence:  3’ - TAC - CAG - GTT - ACC - ATC - 5’    A.) What will be the mRNA requence corresponding to the template DNA sequence? B.) What is the amino acid sequence in letter A? ( e.g. Arg, Phe, etc.)  C.) If the coding sequence of the dsDNA will "serve" as the template for transcription, what is the corresponding mRNA sequence? D.) With the mRNA transcript in letter C, what will be the amino acid sequence?  ( e.g. Arg, Phe, etc.)
f you made a change in the promoter sequence in the DNA that inactivates the promoter, what would happen at the RNA level? A-Nothing, because the RNA would be made as usual B-Transcription factors would be unable to bind and the RNA polymerase would not be recruited to the DNA, so no RNA would be made. C-The mutation of the DNA would be carried through to the RNA sequence. D-The DNA helicase would not be able to recognize and bind the DNA, so the RNA would not be made.   EXPLAIN WHY THE ANSWER YOU CHOOSE IS CORRECT
Complete the table below 6. Below are several DNA sequences that are mutated compared with the wild-type sequence: 3’-T A C T G A C T GA C G A T C-5’. Envision that each is a section of a DNA molecule that has separated in preparation for transcription, so you are only seeing the template strand. Construct the complementary DNA sequences (indicating 5’ and 3’ ends) for each mutated DNA sequence, then transcribe (indicating 5’ and 3’ ends) the template strands, and translate the mRNA molecules using the genetic code, recording the resulting amino acid sequence (indicating the N and C termini). What type of mutation is each?6.a. Mutated DNA Template Strand #1: 3’-T A C T G T C T G A C G A T C-5’Complementary DNA sequence:mRNA sequence transcribed from template:Amino acid sequence of peptide:Type of mutation: 6.b. Mutated DNA Template Strand #2: 3’-T A C G G A C T G A C G A T C-5’Complementary DNA sequence:mRNA sequence transcribed from template:Amino acid sequence of peptide:Type of…

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Genetic Analysis: An Integrated Approach (3rd Edition)

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