Interpretation: The complete mechanism that includes the intermediate and most likely product of given reactants with
Concept introduction:
The product formed is governed by Markovnikov’s Rule. Rule suggests that negative part of halo acid HX must go to the carbon that has more alkyl substituents or less
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- Alkynes do not react directly with aqueous acid as do alkenes, but will do so in the presence of mercury(II) sulfate as a Lewis acid catalyst. The reaction occurs with Markovnikov regiochemistry, so the OH group adds to the more highly substituted carbon and the H adds to the less highly substituted carbon. The initial product of the reaction is a vinyl alcohol, also called an enol. The enol immediately rearranges to a more stable ketone via tautomerization. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions -X티 Hö: H-O -CH3 -CH3 H30*arrow_forwardDraw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without rearrangement give 2-methyl-2-butanol as the MAJOR product. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. If more than one structure fits the description, draw them all. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu.arrow_forwardDraw an approximate reaction-energy diagram showing the curves for the two possible pathways for ionic addition of HBr to 1-methylcyclohexene. (a) Formation of the major product, 1-bromo-1-methylcyclohexane, and (b) formation of the minor product, 1-bromo-2-methylcyclohexane. Point out how these curves show that 1-bromo-1-methylcyclohexane should be formed fasterarrow_forward
- Explain the different products of the following two reactions by considering the mechanism by which each reaction proceeds. As part of your explanation, use the curved arrow formalism to draw a mechanism for each reaction. CH,OH CH2=CH-CH-CH, + Na*¯OCH, CH;=CH-CH-CH3 Br OCH, CH,=CH-CH-CH, + CH,OH – CH,=CH–CH–CH, + CH,CH=CHCH, Br OCH, OCH,arrow_forwardDraw the major organic product formed by reaction of 2-hexyne with the following reagent: H2/ Lindlar catalyst. Consider E/Z stereochemistry of alkenes. In cases where there is more than one answer, just draw one. If no reaction occurs, draw the organic starting material.arrow_forwardCCH H20, H2SO4 H9SO4 CH3 Alkynes do not react directly with aqueous acid as do alkenes, but will do so in the presence of mercury(II) sulfate as a Lewis acid catalyst. The reaction occurs with Markovnikov regiochemistry, so the OH group adds to the more highly substituted carbon and the H adds to the less highly substituted carbon. The initial product of the reaction is a vinyl alcohol, also called an enol. The enol immediately rearranges to a more stable ketone via tautomerization. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Hjö: -CH3 -CH3 H3O*arrow_forward
- pls helparrow_forwardPlease Show reaekson and don't use hend raitingarrow_forwardDraw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without rearrangement give 1-methylcyclohexanol as the major product. You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. ● If more than one structure fits the description, draw them all. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. ● ● ✓ ? ChemDoodleⓇ n [ ]#arrow_forward
- reaction of this alkene to the different reagents written above and below the arrowsarrow_forwardNitesharrow_forwardCH3 CH3 Br- Br2 .CH3 CH2Cl2 CH3 H3C H3C Br Electrophilic addition of bromine, Brɔ, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl,. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 CH3 CH3 H3C H3C :Br: :Br:arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning