Pd (11), Au (III) methiomeprazine (C19 H24 N2S2) with the complex. A mixture of their complexes is being analyzed. Pd (II) complex at 480 nm, The measurement results for Au (III) with max peakat 635 nm are as follows.of the mixture What is the concentration?(b=1) Pd(II) Au(III) Mixture 480 nm 3,55x10 2,96x10 0,533 635 nm 5,641x0 1,45x10 0,590

Pd (11), Au (III) methiomeprazine (C19 H24 N2S2) with the complex. A mixture of their complexes is being analyzed. Pd (II) complex at 480 nm, The measurement results for Au (III) with max peakat 635 nm are as follows.of the mixture What is the concentration?(b=1) Pd(II) Au(III) Mixture 480 nm 3,55x10 2,96x10 0,533 635 nm 5,641x0 1,45x10 0,590

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter26: Molecular Absorption Spectrometry

Section: Chapter Questions

Problem 26.29QAP

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The acid-base indicator HIn undergoes the following reaction in dilute aqueous solution: HIncolor1H++Incolor2 The following absorbance data were obtained for a 5.00 I0-4 M solution of HIn in 0.1 M NaOH and 0.1 M HC1. Measurements were made at wavelengths of 485 nm and 625 nm with 1.00-cm cells. 0.1 M NaOH A485 = 0.075 A625 = 0.904 0.1 M HC1 A485 = 0.487 A625 = 0.181 In the NaOH solution, essentially all of the indicator is present as In-; in the acidic solution, it is essentially all in the form of HIn. (a) Calculate molar absorptivities for In- and HIn at 485 and 625 nm. (b) Calculate the acid dissociation constant for the indicator ¡fa pH 5.00 buffer containing a small amount of the indicator exhibits an absorbance of 0.567 at 485 nm and 0.395 at 625 nm (1.00-cm cells). (c) What is the pH of a solution containing a small amount of the indicator that exhibits an absorbance of0.492 at 485 nm and 0.245 at 635 nm (1.00-cm cells)? (d) A 25.00-mL aliquot of a solution of purified weak organic acid HX required exactly 24.20 mL of a standard solution of a strong base to reach a phenolphthalein end point. When exactly 12.10 mL of the base was added to a second 25.00-mL aliquot of the acid, which contained a small amount of the Indicator under consideration, the absorbance was found to be 0.333 at 485 nm and 0.655 at 625 nm (1.00-cmcells). Calculate the pH of the solution and Ka for the weak acid. (e) What would be the absorbance of a solution at 485 and 625 nm (1.50-cm cells) that was 2.00 10-4 M in the indicator and was buffered to a pH of 6.000?
The accompanying data (1.00-cm cells) were obtained for the spectrophotometric titration 10.00 mL of Pd(II) with 2.44 10-4 M Nitroso R(O. W Rollins and M. M. Oldham, Anal. chem .,1971, 43, 262, DOI: 10.1021/ac60297a026). Calculate the concentration of the Pd(II) solution, given that the ligand-to-cation ratio in the colored product is 2:1
Please help me fill the remaining spaces. The spaces marked with NA don't need to be calculate. Name Molecular Weight Amounts used mmol Equivalents M.P or BP (C) Density (g/mL) Indene 116.16 .5mL MP=-2 BP=181-182 .996 Borane-tetrahydrofuran Complex 85.94 2.8mL 1 MP= -108 BP=66 NA 30% Hydrogen Peroxide 34.01 1mL MP= -33 BP=108 NA 3 M NaOH(aq) 40 .7mL MP=318 BP=1390 NA Diethyl Ether 74.12 NA NA NA BP=75-78 .902 Hexanes 86.17 NA NA NA BP=65.5-68.3 .659 Potassium Permanganate 158.03 NA NA NA BP=100 1.0 1-Indanol (Product) 134.13 NA MP=50-54 NA 2-Indanol (Product) Same as Above Same as Above Same as Above NA MP=68-71 NA
The following calibration data were obtained by an atomic absorption spectrophotometric (AAS) method for the determination of mercury in an herbal product. (show complete solution) 1. What is the detection limit for the method? 2. What is the limit of quantitation for the method?
10-mL aliquots of an environmental water sample were pipetted into five 50.00-mL volumetric flasks. Exactly 0.00, 5.00, 10.00, 15.00, and 20.00-mL of a standard solution containing 11.1 ppm Fe3+ were added to each, followed by an excess of thiocyanate ion to give the red complex Fe(SCN)2+. After dilution to volume, the instrumental response for each of the five solutions measured with a colorimeter was found to be 0.240, 0.437, 0.621, 0.809, 1.809, respectively. Using Excel and the LINEST function, what was the concentration in the water sample (including error)? [HINT: consider the type of calibration scheme used.]
will addition of 300ml 0.005M agno3 to 200ml of 0.004M Al2(SO4)3 result in oreciptation of Ag2SO4 if Ksp of Ag2SO4 is 6.65x10^8?
The calibration curve y=0.0218x - 0.0001 for Fe2+ in buffer at 450 nm in a 0.5 cm cuvette. Is Beer's Law obeyed? Explain. and What is the molar extinction coefficient for the Fe2+ complex at 450 nm?
CATION CONFIRMATORY TESTS ADDED REAGENT(S) OBSERVATIONS KSCN Blood red complex K4Fe(CN)6 Prussian blue ppt K3Fe(CN)6 NVR Na2C2O4 NVR NaOH (in evaporating dish) NVR ANION CONFIRMATORY TESTS ADDED REAGENT(S) OBSERVATIONS (to the ppt) CH3COOH NVR MgCl2 NVR 6M H2SO4, FeSO4, 18M H2SO4 Brown ring POSSIBLE ION(S) PRESENT? Select one or more: Fe3+ SO42- I- Zn2+ Cu2+ PO43- Ca2+ CO32- SCN- Br- NO3- NH4+
0 The acid-base indicator HIn undergoes the following reaction in dilute aqueous solution:HIn color1 m H1 1 In2color2The following absorbance data were obtained for a 5.00 3 1024M solution of HIn in 0.1 M NaOH and0.1 M HCl. Measurements were made at wavelengths of 485 nm and 625 nm with 1.00-cm cells.0.1 M NaOH A485 5 0.075 A625 5 0.9040.1 M HCl A485 5 0.487 A625 5 0.181In the NaOH solution, essentially all of the indicator is present as In2; in the acidic solution, it is essentiallyall in the form of HIn.(a) Calculate molar absorptivities for In2 and HIn at 485 and 625 nm.(b) Calculate the acid dissociation constant for the indicator if a pH 5.00 buffer containing a small amountof the indicator exhibits an absorbance of 0.567 at 485 nm and 0.395 at 625 nm (1.00-cm cells).(c) What is the pH of a solution containing a small amount of the indicator that exhibits an absorbance of0.492 at 485 nm and 0.245 at 635 nm (1.00-cm cells)?(d) A 25.00-mL aliquot of a solution of purified weak…
The molar absorptivity (ε) of the FeSCN2+ complex ion is 4700 M-1 · cm-1 at a wavelength of 450 nm. Using a 1-cm sample tube, you measure the absorbance as (2.0x10-1). What is the concentration of FeSCN2+?
A standard solution was put through appropriate dilutions to give the concentrations of iron shown in the table that follows. The iron(II)-1,10-phenanthroline complex was then formed in 25.0-mL aliquots of these solutions, following which each was diluted to 50.0 mL. The following absorbances (1.00-cm cells) were recorded at 510 nm: Calculate the concentration, in ppm, of a sample with an abosrbance of 0.829. Fe(II) concentration (ppm) A510 4.00 0.160 10.0 0.390 16.0 0.630 24.0 0.950 32.0 1.260 40.0 1.580
A 5.00-mL sample of blood was treated with trichloroacetic acid to precipitate proteins. After centrifugation, the resulting solution was brought to pH 3 and extracted with two 5-mL portions of methyl isobutyl ketone containing the lead-complexing agent APCD. The extract was aspirated directly into an air/acetylene flame and yielded an absorbance of 0.527 at 283.3 nm. Five-milliliter aliquots of standard solutions containing 0.400 and 0.600 ppm of lead were treated in the same way and yielded absorbances of 0.396 and 0.599. Find the concentration of lead in the sample in ppm assuming that Beer’s law is followed.