Chemistry: Principles and Reactions
8th Edition
ISBN: 9781305079373
Author: William L. Masterton, Cecile N. Hurley
Publisher: Cengage Learning
Chemistry: Principles and Reactions
Gaseous Chemical Equilibrium. 10QAP

(a) Interpretation: A balanced chemical equation for the given description and the equilibrium constant for the expression should be determined. Concept introduction: For a general equilibrium reaction as follows: a A + b B ⇌ c C + d D The expression for equilibrium constant of a reaction can be calculated as follows: K = [ C ] c [ D ] d [ A ] a [ B ] b Here, A and B are reactants with stoichiometric coefficient a and b respectively. Similarly, C and D are products with stoichiometric coefficient c and d respectively In the expression for equilibrium constant, the species in pure solid and liquid state are not written as equilibrium constant does not depend on them.

Question
Chapter 12, Problem 10QAP
Interpretation Introduction

(a)Interpretation:A balanced chemical equation for the given description and the equilibrium constant for the expression should be determined.Concept introduction:For a general equilibrium reaction as follows:aA+bB⇌cC+dDThe expression for equilibrium constant of a reaction can be calculated as follows:K=[C]c[D]d[A]a[B]bHere, A and B are reactants with stoichiometric coefficient a and b respectively. Similarly, C and D are products with stoichiometric coefficient c and d respectivelyIn the expression for equilibrium constant, the species in pure solid and liquid state are not written as equilibrium constant does not depend on them.

Expert Solution

K=PC3H6O(g)

Explanation of Solution

According to the given description, the liquid acetone, C3H6O(l) is in equilibrium with its vapor state.

The reaction can be written as follows:

C3H6O(l)C3H6O(g)

The above reaction is already balanced.

The expression for equilibrium constant will be as follows:

K=PC3H6O(g)

Interpretation Introduction

(b)Interpretation:A balanced chemical equation for the given description and the equilibrium constant for the expression should be determined.Concept introduction:For a general equilibrium reaction as follows:aA+bB⇌cC+dDThe expression for equilibrium constant of a reaction can be calculated as follows:K=[C]c[D]d[A]a[B]bHere, A and B are reactants with stoichiometric coefficient a and b respectively. Similarly, C and D are products with stoichiometric coefficient c and d respectivelyIn the expression for equilibrium constant, the species in pure solid and liquid state are not written as equilibrium constant does not depend on them.

Expert Solution

K=(PNH3(g))2(PH2O(g))4(PH2(g))7(PNO2(g))2

Explanation of Solution

According to the given description, the reaction of hydrogen gas H2(g) with nitrogen dioxide gas NO2(g) results in the production of ammonia NH3(g) and steam H2O(g).

The reaction can be written as follows:

H2(g)+NO2(g)NH3(g)+H2O(g)

To balance the number of oxygen atoms, give coefficient 2 to H2O(g).

H2(g)+NO2(g)NH3(g)+2H2O(g)

Give coefficient 7/2 to H2(g) to balance the number of hydrogen atoms.

7/2H2(g)+NO2(g)NH3(g)+2H2O(g)

Or,

7H2(g)+2NO2(g)2NH3(g)+4H2O(g)

The expression for equilibrium constant will be as follows:

K=(PNH3(g))2(PH2O(g))4(PH2(g))7(PNO2(g))2

Interpretation Introduction

(c)Interpretation:A balanced chemical equation for the given description and the equilibrium constant for the expression should be determined.Concept introduction:For a general equilibrium reaction as follows:aA+bB⇌cC+dDThe expression for equilibrium constant of a reaction can be calculated as follows:K=[C]c[D]d[A]a[B]bHere, A and B are reactants with stoichiometric coefficient a and b respectively. Similarly, C and D are products with stoichiometric coefficient c and d respectivelyIn the expression for equilibrium constant, the species in pure solid and liquid state are not written as equilibrium constant does not depend on them.

Expert Solution

K=[H+(aq)]2PH2S(g)[Pb2+(aq)]

Explanation of Solution

According to the given description, the reaction of hydrogen sulfide gas H2S(g) and aqueous solution of lead (II) ion Pb2+(aq) results in the formation of lead sulfide precipitate PbS(s) and hydrogen ions H+(aq).

Thus, the reaction is as follows:

H2S(g)+Pb2+(aq)PbS(s)+H+(aq)

Give coefficient 2 to H+(aq) to balance the number of hydrogen atoms.

H2S(g)+Pb2+(aq)PbS(s)+2H+(aq)

The expression for the equilibrium constant will be:

K=[H+(aq)]2PH2S(g)[Pb2+(aq)]

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Chemistry: Principles and Reactions
8th Edition
ISBN: 9781305079373
Author: William L. Masterton, Cecile N. Hurley
Publisher: Cengage Learning
Chemistry: Principles and Reactions
Gaseous Chemical Equilibrium. 10QAP
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