Skip to main content
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN: 9781305079373
Author: William L. Masterton, Cecile N. Hurley
Publisher: Cengage Learning
Not helpful? See similar books
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Gaseous Chemical Equilibrium. 10QAP

(a) Interpretation: A balanced chemical equation for the given description and the equilibrium constant for the expression should be determined. Concept introduction: For a general equilibrium reaction as follows: a A + b B ⇌ c C + d D The expression for equilibrium constant of a reaction can be calculated as follows: K = [ C ] c [ D ] d [ A ] a [ B ] b Here, A and B are reactants with stoichiometric coefficient a and b respectively. Similarly, C and D are products with stoichiometric coefficient c and d respectively In the expression for equilibrium constant, the species in pure solid and liquid state are not written as equilibrium constant does not depend on them.

Question
Chapter 12, Problem 10QAP
Interpretation Introduction

(a)

Interpretation:

A balanced chemical equation for the given description and the equilibrium constant for the expression should be determined.

Concept introduction:

For a general equilibrium reaction as follows:

aA+bBcC+dD

The expression for equilibrium constant of a reaction can be calculated as follows:

K=[C]c[D]d[A]a[B]b

Here, A and B are reactants with stoichiometric coefficient a and b respectively. Similarly, C and D are products with stoichiometric coefficient c and d respectively

In the expression for equilibrium constant, the species in pure solid and liquid state are not written as equilibrium constant does not depend on them.

Expert Solution

Answer to Problem 10QAP

K=PC3H6O(g)

Explanation of Solution

According to the given description, the liquid acetone, C3H6O(l) is in equilibrium with its vapor state.

The reaction can be written as follows:

C3H6O(l)C3H6O(g)

The above reaction is already balanced.

The expression for equilibrium constant will be as follows:

K=PC3H6O(g)

Interpretation Introduction

(b)

Interpretation:

A balanced chemical equation for the given description and the equilibrium constant for the expression should be determined.

Concept introduction:

For a general equilibrium reaction as follows:

aA+bBcC+dD

The expression for equilibrium constant of a reaction can be calculated as follows:

K=[C]c[D]d[A]a[B]b

Here, A and B are reactants with stoichiometric coefficient a and b respectively. Similarly, C and D are products with stoichiometric coefficient c and d respectively

In the expression for equilibrium constant, the species in pure solid and liquid state are not written as equilibrium constant does not depend on them.

Expert Solution

Answer to Problem 10QAP

K=(PNH3(g))2(PH2O(g))4(PH2(g))7(PNO2(g))2

Explanation of Solution

According to the given description, the reaction of hydrogen gas H2(g) with nitrogen dioxide gas NO2(g) results in the production of ammonia NH3(g) and steam H2O(g).

The reaction can be written as follows:

H2(g)+NO2(g)NH3(g)+H2O(g)

To balance the number of oxygen atoms, give coefficient 2 to H2O(g).

H2(g)+NO2(g)NH3(g)+2H2O(g)

Give coefficient 7/2 to H2(g) to balance the number of hydrogen atoms.

7/2H2(g)+NO2(g)NH3(g)+2H2O(g)

Or,

7H2(g)+2NO2(g)2NH3(g)+4H2O(g)

The expression for equilibrium constant will be as follows:

K=(PNH3(g))2(PH2O(g))4(PH2(g))7(PNO2(g))2

Interpretation Introduction

(c)

Interpretation:

A balanced chemical equation for the given description and the equilibrium constant for the expression should be determined.

Concept introduction:

For a general equilibrium reaction as follows:

aA+bBcC+dD

The expression for equilibrium constant of a reaction can be calculated as follows:

K=[C]c[D]d[A]a[B]b

Here, A and B are reactants with stoichiometric coefficient a and b respectively. Similarly, C and D are products with stoichiometric coefficient c and d respectively

In the expression for equilibrium constant, the species in pure solid and liquid state are not written as equilibrium constant does not depend on them.

Expert Solution

Answer to Problem 10QAP

K=[H+(aq)]2PH2S(g)[Pb2+(aq)]

Explanation of Solution

According to the given description, the reaction of hydrogen sulfide gas H2S(g) and aqueous solution of lead (II) ion Pb2+(aq) results in the formation of lead sulfide precipitate PbS(s) and hydrogen ions H+(aq).

Thus, the reaction is as follows:

H2S(g)+Pb2+(aq)PbS(s)+H+(aq)

Give coefficient 2 to H+(aq) to balance the number of hydrogen atoms.

H2S(g)+Pb2+(aq)PbS(s)+2H+(aq)

The expression for the equilibrium constant will be:

K=[H+(aq)]2PH2S(g)[Pb2+(aq)]

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN: 9781305079373
Author: William L. Masterton, Cecile N. Hurley
Publisher: Cengage Learning
Not helpful? See similar books
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Gaseous Chemical Equilibrium. 10QAP
More videos on
Chemical Equilibrium
marketing sidebar icon
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts.

Chapter 12 Solutions

Chemistry: Principles and Reactions

Ch. 12 - Prob. 11QAPCh. 12 - Prob. 12QAPCh. 12 - Prob. 13QAPCh. 12 - Prob. 14QAPCh. 12 - Prob. 15QAPCh. 12 - Prob. 16QAPCh. 12 - Prob. 17QAPCh. 12 - Prob. 18QAPCh. 12 - Prob. 19QAPCh. 12 - Prob. 20QAPCh. 12 - Prob. 21QAPCh. 12 - Prob. 22QAPCh. 12 - Prob. 23QAPCh. 12 - Prob. 24QAPCh. 12 - Prob. 25QAPCh. 12 - Prob. 26QAPCh. 12 - Prob. 27QAPCh. 12 - Prob. 28QAPCh. 12 - Prob. 29QAPCh. 12 - Prob. 30QAPCh. 12 - Prob. 31QAPCh. 12 - Prob. 32QAPCh. 12 - Prob. 33QAPCh. 12 - Prob. 34QAPCh. 12 - Prob. 35QAPCh. 12 - Prob. 36QAPCh. 12 - Prob. 37QAPCh. 12 - Prob. 38QAPCh. 12 - Prob. 39QAPCh. 12 - Prob. 40QAPCh. 12 - Prob. 41QAPCh. 12 - Prob. 42QAPCh. 12 - Prob. 43QAPCh. 12 - Prob. 44QAPCh. 12 - Prob. 45QAPCh. 12 - Prob. 46QAPCh. 12 - Prob. 47QAPCh. 12 - Prob. 48QAPCh. 12 - Prob. 49QAPCh. 12 - Prob. 50QAPCh. 12 - Prob. 51QAPCh. 12 - Prob. 52QAPCh. 12 - Prob. 53QAPCh. 12 - Prob. 54QAPCh. 12 - Prob. 55QAPCh. 12 - Prob. 56QAPCh. 12 - Prob. 57QAPCh. 12 - Prob. 58QAPCh. 12 - Prob. 59QAPCh. 12 - Prob. 60QAPCh. 12 - Prob. 61QAPCh. 12 - Prob. 62QAPCh. 12 - Prob. 63QAPCh. 12 - Prob. 64QAPCh. 12 - Prob. 65QAPCh. 12 - Prob. 66QAPCh. 12 - Prob. 67QAPCh. 12 - Prob. 68QAPCh. 12 - Prob. 69QAPCh. 12 - Prob. 70QAPCh. 12 - Prob. 71QAPCh. 12 - Prob. 72QAPCh. 12 - Prob. 73QAPCh. 12 - Prob. 74QAPCh. 12 - Prob. 75QAPCh. 12 - Prob. 76QAPCh. 12 - Prob. 77QAPCh. 12 - Prob. 78QAPCh. 12 - Prob. 79QAPCh. 12 - Prob. 80QAPCh. 12 - Prob. 81QAPCh. 12 - Prob. 82QAPCh. 12 - Prob. 83QAPCh. 12 - Prob. 84QAPCh. 12 - Prob. 85QAPCh. 12 - Prob. 86QAP
Knowledge Booster
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Related Youtube Videos
Need a deep-dive on the concept behind this application? Watch these videos for an in-depth look
Chemical Equilibria and Reaction Quotients
Professor Dave Explains
Recommended textbooks for you
  • Chemistry: Principles and Reactions
    Chemistry
    ISBN:9781305079373
    Author:William L. Masterton, Cecile N. Hurley
    Publisher:Cengage Learning
    Chemistry & Chemical Reactivity
    Chemistry
    ISBN:9781133949640
    Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
    Publisher:Cengage Learning
    Chemistry: The Molecular Science
    Chemistry
    ISBN:9781285199047
    Author:John W. Moore, Conrad L. Stanitski
    Publisher:Cengage Learning
  • Chemistry: An Atoms First Approach
    Chemistry
    ISBN:9781305079243
    Author:Steven S. Zumdahl, Susan A. Zumdahl
    Publisher:Cengage Learning
    Chemistry
    Chemistry
    ISBN:9781305957404
    Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
    Chemistry
    Chemistry
    ISBN:9781133611097
    Author:Steven S. Zumdahl
    Publisher:Cengage Learning
  • Chemistry: Principles and Reactions
    Chemistry
    ISBN:9781305079373
    Author:William L. Masterton, Cecile N. Hurley
    Publisher:Cengage Learning
    Chemistry & Chemical Reactivity
    Chemistry
    ISBN:9781133949640
    Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
    Publisher:Cengage Learning
    Chemistry: The Molecular Science
    Chemistry
    ISBN:9781285199047
    Author:John W. Moore, Conrad L. Stanitski
    Publisher:Cengage Learning
    Chemistry: An Atoms First Approach
    Chemistry
    ISBN:9781305079243
    Author:Steven S. Zumdahl, Susan A. Zumdahl
    Publisher:Cengage Learning
    Chemistry
    Chemistry
    ISBN:9781305957404
    Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
    Chemistry
    Chemistry
    ISBN:9781133611097
    Author:Steven S. Zumdahl
    Publisher:Cengage Learning
    Chemical Equilibria and Reaction Quotients; Author: Professor Dave Explains;https://www.youtube.com/watch?v=1GiZzCzmO5Q;License: Standard YouTube License, CC-BY