   Chapter 13, Problem 86QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# Consider the following reaction:msp;  C ( s ) + O 2 ( g )   CO 2 ( g ) at volume of oxygen gas at 25 °C and 1 .0 2 atm would be required to react completely with 1 . 25 g of carbon?

Interpretation Introduction

Interpretation:

The volume of oxygen gas should be calculated.

Concept Introduction:

According to ideal gas equation:

PV=nRT

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature.

The value of Universal gas constant can be taken as 0.082 L atm K1 mol1.

Mass of gas can be calculated from number of moles and molar mass as follows:

m=n×M

Here, n is number of moles, m is mass and M is molar mass.

Explanation

Given Information:

The mass of carbon is 1.25 g, temperature is 25 C and pressure is 1.02 atm.

Calculation:

The balanced chemical reaction is as follows:

C(s)+O2(g)CO2(g)

From the balanced chemical reaction, 1 mol of C reacts with 1 mol of O2. To calculate the volume of O2, first calculate the number of moles of both C and O2.

n=mM

Molar mass of C is 12.01 g/mol thus,

n=1.25 g12.01 g/mol=0.1040 mol

Since, 1 mol of C reacts with 1 mol of O2 thus, 0.1040 mol of C will react with 0.1040 mol of O2

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