   Chapter 13, Problem 61QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
6 views

# Suppose a 24 . 3 − mL sample of helium gas at 25  ° C and 1 .0 1 atm is heated to :math> 5 0.   ° C and compressed to a volume of 15 . 2 mL . What will be the pressure of the sample?

Interpretation Introduction

Interpretation:

Pressure of the sample should be calculated if sample of helium gas is heated and compressed.

Concept Introduction:

According to ideal gas equation:

PV=nRT

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature.

The value of Universal gas constant can be taken as 0.082 L atm K1 mol1.

Explanation

Calculation:

P1V1T1=P2V2T2

Convert the temperature from K to C as follows:

0 C=273.15 K

Thus,

25 C=(25+273.15) K=298.15 K

And

50 C=(50+273.15) K=323.15 K

Putting the values,

(1

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