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Concept explainers
(a)
Interpretation:
For the given molecule, whether cis‑trans isomerism is possible has to be indicated.
Concept Introduction:
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
(b)
Interpretation:
For the given molecule, whether cis‑trans isomerism is possible has to be indicated.
Concept Introduction:
Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
(c)
Interpretation:
For the given molecule, whether cis‑trans isomerism is possible has to be indicated.
Concept Introduction:
Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
(d)
Interpretation:
For the given molecule, whether cis‑trans isomerism is possible has to be indicated.
Concept Introduction:
Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
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Chapter 13 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- IDENTIFY THE FUNCTIONAL GROUP PRESENT IN THESE COMPOUNDS. A = ? B = ? C = ?arrow_forwardClassify each of the following sugar pairs as enantiomers, diastereomers, epimers, or an aldose–ketose pair. a. D-erythrose and D-threose b. D-glucose and D-mannose c. D-ribose and L-ribose d. D-allose and D-galactose e. D-glyceraldehyde and dihydroxyacetonearrow_forwardPropose a scheme to separate and isolate a mixture containing 4-aminobenzoate, 1,2,4,5-tetrachlorobenzene, and napthalene. Isolate two of the three solids by extraction. (please explain what solvents to use and the process step by step)arrow_forward
- Define the following terms: a. ganglioside b. sphingolipidoses c. isoprenoid d. terpene e. mixed terpenoidarrow_forwardIdentify the chiral carbon in each of the following compounds: a. citronellol; one enantiomer has the odor of geranium b. alanine, an amino acidarrow_forwardDefine the following terms: a. alkylating agents b. base analogue c. nonalkylating agent d. intercalating agent e. ethidium bromidearrow_forward
- Give the reagent or chemical test that would differentiate the following pairs of compounds. Write chemical equations for the reactions. List of Chemical Tests (choose here)I. Halogenation: Bromination with and without lightII. Oxidation: Reaction with Baeyer’s reagent III. Reaction with Ammoniacal Silver Nitrate (AgNO3) or simply Tollen’s reagent a. benzene and ethylbenzeneb. 1-butyne and 2-butynec. 2-methylpentane and 2-methyl-2-pentened. toluene and 1-methylcyclohexenearrow_forwardDraw the following compounds: a. α- and β-anomers of D-galactose b. aldonic acid, uronic acid, and aldaric acid derivatives of galactose c. galactitol d. δ-lactone of galactonic acidarrow_forwardDraw the structure of: a. 1-palmitoleyl-2-linolenyl-3-stearyltriglyceride. b. 1-linolenyl-2-arachidyl-3-phosphatidylserine.arrow_forward
- Isobutylene, CH2=C(CH3)2, is used to prepare cold-flow rubber. Draw a structure for the addition polymer formed from this alkene.arrow_forwardThe reaction of methoxy benzene with hydrogen iodide will yield a phenol and an alkyl halide. Which of following choices is the correct combination of the products?arrow_forwardDraw a structure for the compound, C3H5Br, that fits the following 1H NMR data: δ 2.32 (3H, singlet) δ 5.35 (1H, broad singlet) δ 5.54 (1H, broad singlet)arrow_forward
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