Concept explainers
(a)
The focal length of the lens.
(a)
Answer to Problem 66A
The focal length of the lens is
Explanation of Solution
Given:
The height of the object is
The position of the object is
The position of the image is
Formula used:
The expression for the mirror equation is,
Here,
Calculation:
The focal length is,
Conclusion:
Thus, the focal length of the lens is
(b)
The location, size, and orientation of the image for the given changes in lens.
(b)
Answer to Problem 66A
The location of the image is
The size of the image is
The image is real and inverted.
Explanation of Solution
Given:
The height of the object is
The position of the object is
The position of the image is
Focal length of lens is doubled.
Formula used:
The expression for the mirror equation is,
Here,
The expression for the magnification equation as follows:
Here,
Calculation:
From part (a), the focal length of the lens is
The new focal length of the lens as follows:
The new location of the image is,
The new height of the image is calculated using magnification formula.
Hence, the image is real and inverted.
Conclusion:
Thus, the location of the image is
Chapter 18 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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