Chapter 18, Problem 8STP

To determine

To Choose: The correct option.

Answer to Problem 8STP

Option D

Explanation of Solution

Given:

Refractive index of glass, ${\mu }_g=1.52$

Refractive index of water, ${\mu }_w=1.33$

Formula used:

Critical angle $\left(C\right)$ can be obtained by:

  $\frac{1}{\sin C}=\frac{{\mu }_1}{{\mu }_2}$

Here, ${\mu }_1$ is the refractive index of the denser medium and ${\mu }_2$ is the refractive index of the rarer medium.

Calculations:

Substitute the values and solve:

  $\begin{array}{l}\frac{1}{\sin C}=\frac{1.52}{1.33}\\ \sin C=0.875\\ C={\sin }^{-1}\left(0.875\right)\\ C=61.0°\end{array}$

Conclusion:

Thus, the option D is correct.