Concept explainers
(a)
The position, height, and orientation of the image as formed by the lens.
To identify: Whether the image is real or virtual.
(a)
Answer to Problem 79A
The position of the image is
The height of the image is
The image is a real image and is inverted compared to the object.
Explanation of Solution
Given:
The position of the telescope is
The height of the telescope is
The focal length is
Formula used:
The expression for the mirror equation is,
Here,
The expression for the magnification equation is,
Here,
Calculation:
The position of the image is,
The height of the image is,
Since height is negative, image is inverted compared to the object but it is real.
Conclusion:
Thus, the position of the image is
The image is a real image and is inverted compared to the object.
(b)
The position, height, and orientation of the image that people sees when looking into the telescope.
To identify: Whether the image is real or virtual.
(b)
Answer to Problem 79A
The position of the image is
The height of the image is
The image is a virtual image and is inverted compared to the object.
Explanation of Solution
Given:
The position of the telescope is
The height of the telescope is
The focal length is
The focal length of eye piece is
Formula used:
The expression for the mirror equation is
Here,
The expression for the magnification equation is
Here,
Calculation:
From part (a), the position of the image is
The new position of the object is,
The new height of the object is,
The position of the image is,
The height of the image is,
Hence, the image is a virtual image and is inverted compared to the object.
Conclusion:
Thus, the position of the image is
The image is a virtual image and is inverted compared to the object.
(c)
The magnification of the telescope.
(c)
Answer to Problem 79A
The magnification of the telescope is
Explanation of Solution
Given:
The position of the telescope is
The height of the telescope is
The focal length is
The focal length of eye piece is
Formula used:
The expression for the magnification equation is,
Here,
Calculation:
From part (b), the new height of the image is
The magnification of the telescope is,
Conclusion:
Thus, the magnification of the telescope is
Chapter 18 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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