(a)
Interpretation:
The structure of the major product obtained from
Concept introduction:
In Hoffman’s elimination reaction, the less substituted alkene as the more favourable product, whereas according to Zaitsev rule more substituted
(b)
Interpretation:
The formation of the Zaitsev product using stereochemical drawings of the transition states are to be shown.
Concept introduction:
In Hoffman’s elimination reaction, the less substituted alkene as the more favourable product, whereas according to Zaitsev rule more substituted alkenes are considered as more favourable product. The notations
Trending nowThis is a popular solution!
Chapter 19 Solutions
Organic Chemistry Plus Masteringchemistry With Pearson Etext, Global Edition
- What is the main reaction mechanism for this reductive amination?arrow_forwardWhy do you wash the dichloromethane solution of your reductive amination product with sodium bicarbonate, rather than dilute aqueous HCl? a) Sodium bicarbonate is a good method of removing aldehydes from organic solvent.b) The amine product will be protonated by acid and remain in the aqueous layer as a salt.c) Sodium bicarbonate transfers the amine starting material into the aqueous layer.d) Sodium bicarbonate reacts with leftover NaBH(OAc)3 and removes it from the mixture.arrow_forwardWhat kinds of halides cannot be used to alkylate an amine? Why not? a.Tertiary halides form alkenes on elimination. b.Aryl halides unless activated by electron-withdrawing groups c.Halides with beta-alkyl groups are sterically hindered. d. all of the abovearrow_forward
- Just one quick follow-up question. Would this reaction be considered an imine formation?arrow_forwardUse E1, sn1 or E2, sn2 Synthesisarrow_forwardAn alternative procedure for preparing the amine of Step 3 is reductive amination of the corresponding ketone. What is reductive amination? Why might this two-step route for formation of the amine be preferred over the one-step reductive amination?arrow_forward
- Draw the major product of this reaction. Ignore inorganic byproducts and the amine side product.arrow_forwardDraw the possible stereoisomers of 2-methylocta-4,6-dien-1-amine. Note that E-, Z- isomers of each stereoisomer are also possible and would not be accounted for by the formula above; draw any E- or Z- isomers.arrow_forwardWhich of these amine will react fastest in a reductive amination reaction?arrow_forward
- Amides are weak nucleophiles but their conjugate bases are string nucleophiles. The amide drawn below can be deprotonated in four possible locations, labeled A-D but two are considerably more acidic than the others. Draw the two different Bronsted Lowery acid/base reactions (using HO- as the BL base) showing the deprotonation at these two locations. Draw all RS with arrows for both conjugate bases but no hybrids. Based on your resonance analysis which location is the most acidic in the molecule? Why is it most acidic? Amides can also be protonated by a strong acid in two different locations. Draw two different conjugate acids for the amide above as well as RS with arrows for each. Based on your resonance analysis which atom is the most basic in an amide?arrow_forwardShow any working means to show the Strecker pathway stepwise and link the products listed to the starting materials that you get to. No mechanisms are required.arrow_forwardExplain why the nitrogen in an amide is not a good nucleophile. Use a picture to show whyarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning