Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
Question
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Chapter 22.2, Problem 11SSC
Interpretation Introduction

(a)

Interpretation:

The structure of 1-propanol needs to be drawn.

Concept introduction:

The organic compounds generally contain carbon atoms. The naming of organic compounds is done by considering three main terms which are prefix, suffix and the root name. The longest chain in the compound is first identified and named that will be the root name for the compound. For example, if there are 3 carbon atoms in the longest chain, the root name will be “prop”. To determine the suffix, functional group should be identified. For example, alcohol group will have suffix −ol, aldehyde will have suffix −al. If there is no functional group the suffix will be −ane. In the last step, side groups are identified and named. Prefix is used to give number of side groups and substituent’s present on the main carbon chain.

Expert Solution
Check Mark

Answer to Problem 11SSC

Chemistry: Matter and Change, Chapter 22.2, Problem 11SSC , additional homework tip  1

Explanation of Solution

The given name of the compound is 1-propanol.

The root name is “prop” thus, there are 3 carbon atoms in the main chain. Suffix −ol represents the presence of hydroxyl group or −OH group and prefix 1- represents the position of hydroxyl group.

Thus, the structure of compound will be:

Chemistry: Matter and Change, Chapter 22.2, Problem 11SSC , additional homework tip  2

Interpretation Introduction

(b)

Interpretation:

The structure of 1, 3-cyclopentanediol needs to be drawn.

Concept introduction:

The organic compounds generally contain carbon atoms. The naming of organic compounds is done by considering three main terms which are prefix, suffix and the root name. The longest chain in the compound is first identified and named that will be the root name for the compound. For example, if there are 3 carbon atoms in the longest chain, the root name will be “prop”. To determine the suffix, functional group should be identified. For example, alcohol group will have suffix −ol, aldehyde will have suffix −al. If there is no functional group the suffix will be −ane. In the last step, side groups are identified and named. Prefix is used to give number of side groups and substituent’s present on the main carbon chain. Also, in case of cyclic molecules prefix cyclo- is used.

Expert Solution
Check Mark

Answer to Problem 11SSC

Chemistry: Matter and Change, Chapter 22.2, Problem 11SSC , additional homework tip  3

Explanation of Solution

The given name of the compound is 1, 3-cyclopentanediol.

The root name is “pent” thus, there are 5carbon atoms in the main chain. Suffix −diol represents the presence of two hydroxyl groups and prefix 1, 3- shows the position of hydroxyl groups.

Thus, the structure of compound will be:

Chemistry: Matter and Change, Chapter 22.2, Problem 11SSC , additional homework tip  4

Interpretation Introduction

(c)

Interpretation:

The structure of propyl ether needs to be drawn.

Concept introduction:

The organic compounds generally contain carbon atoms. The naming of organic compounds is done by considering three main terms which are prefix, suffix and the root name. The longest chain in the compound is first identified and named that will be the root name for the compound. For example, if there are 3 carbon atoms in the longest chain, the root name will be “prop”. To determine the suffix, functional group should be identified. For example, alcohol group will have suffix −ol, aldehyde will have suffix −al. If there is no functional group the suffix will be −ane. In the last step, side groups are identified and named. Prefix is used to give number of side groups and substituent’s present on the main carbon chain.

Expert Solution
Check Mark

Answer to Problem 11SSC

Chemistry: Matter and Change, Chapter 22.2, Problem 11SSC , additional homework tip  5

Explanation of Solution

The given name of the compound is propyl ether.

The root name is “prop” thus, there are 3 carbon atoms. But there is ether group present which shows the oxygen atom between two propyl groups.

Thus, the structure of compound will be:

Chemistry: Matter and Change, Chapter 22.2, Problem 11SSC , additional homework tip  6

Interpretation Introduction

(d)

Interpretation:

The structure of 1, 2-propanediamine needs to be drawn.

Concept introduction:

The organic compounds generally contain carbon atoms. The naming of organic compounds is done by considering three main terms which are prefix, suffix and the root name. The longest chain in the compound is first identified and named that will be the root name for the compound. For example, if there are 3 carbon atoms in the longest chain, the root name will be “prop”. To determine the suffix, functional group should be identified. For example, alcohol group will have suffix −ol, aldehyde will have suffix −al. If there is no functional group the suffix will be −ane. In the last step, side groups are identified and named. Prefix is used to give number of side groups and substituent’s present on the main carbon chain.

Expert Solution
Check Mark

Answer to Problem 11SSC

Chemistry: Matter and Change, Chapter 22.2, Problem 11SSC , additional homework tip  7

Explanation of Solution

The given name of the compound is 1, 2-propanediamine.

The root name is “prop” thus, there are 3 carbon atoms. Suffix −diamine represents presence of two amino groups and prefix 1, 2- represents the position of two amino groups.

Thus, the structure of compound will be:

Chemistry: Matter and Change, Chapter 22.2, Problem 11SSC , additional homework tip  8

Chapter 22 Solutions

Chemistry: Matter and Change

Ch. 22.2 - Prob. 11SSCCh. 22.2 - Prob. 12SSCCh. 22.2 - Prob. 13SSCCh. 22.3 - Prob. 14SSCCh. 22.3 - Prob. 15SSCCh. 22.3 - Prob. 16SSCCh. 22.3 - Prob. 17SSCCh. 22.4 - Prob. 18SSCCh. 22.4 - Prob. 19SSCCh. 22.4 - Prob. 20SSCCh. 22.4 - Prob. 21SSCCh. 22.5 - Prob. 22SSCCh. 22.5 - Prob. 23SSCCh. 22.5 - Prob. 24SSCCh. 22.5 - Prob. 25SSCCh. 22 - Prob. 26ACh. 22 - Prob. 27ACh. 22 - Prob. 28ACh. 22 - Prob. 29ACh. 22 - Prob. 30ACh. 22 - Prob. 31ACh. 22 - Prob. 32ACh. 22 - Prob. 33ACh. 22 - Prob. 34ACh. 22 - Prob. 35ACh. 22 - Prob. 36ACh. 22 - Prob. 37ACh. 22 - Prob. 38ACh. 22 - Prob. 39ACh. 22 - Prob. 40ACh. 22 - Prob. 41ACh. 22 - Prob. 42ACh. 22 - Prob. 43ACh. 22 - Prob. 44ACh. 22 - Prob. 45ACh. 22 - Prob. 46ACh. 22 - Prob. 47ACh. 22 - Prob. 48ACh. 22 - Prob. 49ACh. 22 - Prob. 50ACh. 22 - Prob. 51ACh. 22 - Prob. 52ACh. 22 - Prob. 53ACh. 22 - Prob. 54ACh. 22 - Prob. 55ACh. 22 - Prob. 56ACh. 22 - Prob. 57ACh. 22 - Prob. 58ACh. 22 - Prob. 59ACh. 22 - Prob. 60ACh. 22 - Prob. 61ACh. 22 - Prob. 62ACh. 22 - Prob. 63ACh. 22 - Prob. 64ACh. 22 - Prob. 65ACh. 22 - Prob. 66ACh. 22 - Prob. 67ACh. 22 - Prob. 68ACh. 22 - Prob. 69ACh. 22 - Prob. 70ACh. 22 - Prob. 71ACh. 22 - Prob. 72ACh. 22 - Prob. 73ACh. 22 - Prob. 74ACh. 22 - Prob. 75ACh. 22 - Prob. 76ACh. 22 - Prob. 77ACh. 22 - Prob. 78ACh. 22 - Prob. 79ACh. 22 - Prob. 80ACh. 22 - Prob. 81ACh. 22 - Prob. 82ACh. 22 - Prob. 83ACh. 22 - Prob. 84ACh. 22 - Prob. 85ACh. 22 - Prob. 1STPCh. 22 - Prob. 2STPCh. 22 - Prob. 3STPCh. 22 - Prob. 4STPCh. 22 - Prob. 5STPCh. 22 - Prob. 6STPCh. 22 - Prob. 7STPCh. 22 - Prob. 8STPCh. 22 - Prob. 9STPCh. 22 - Prob. 10STPCh. 22 - Prob. 11STPCh. 22 - Prob. 12STPCh. 22 - Prob. 13STPCh. 22 - Prob. 14STPCh. 22 - Prob. 15STPCh. 22 - Prob. 16STPCh. 22 - Prob. 17STPCh. 22 - Prob. 18STP
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