EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 27, Problem 27.66AP
Interpretation Introduction
Interpretation:
The explanation for how the two aspartic acid residue of the enzyme reacts with the hydroxyl group which increases the binding efficiency of inhibitor is to be stated.
Concept introduction:
The amino acid is made of two
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The activity of an enzyme requires a glutamic acid to display its -COOH
functional group in the protonated state. Suppose the pK, of the -COOH
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(b) What fraction of the enzymes will be active at pH = 4.07? Explain.
(c) At what pH will the enzyme show 78% of maximal activity?
How can the Michaelis constant (Km) be identified and used to represent the affinity between the enzyme and the substrate?
Ethyleneimine reacts with cysteine side chains in proteins to form S - aminoethyl derivatives. The peptide bonds on the carboxyl side of these modified cysteine residues are susceptible to hydrolysis by trypsin . Why?
Chapter 27 Solutions
EBK ORGANIC CHEMISTRY
Ch. 27 - Prob. 27.1PCh. 27 - Prob. 27.2PCh. 27 - Prob. 27.3PCh. 27 - Prob. 27.4PCh. 27 - Prob. 27.5PCh. 27 - Prob. 27.6PCh. 27 - Prob. 27.8PCh. 27 - Prob. 27.9PCh. 27 - Prob. 27.10PCh. 27 - Prob. 27.11P
Ch. 27 - Prob. 27.12PCh. 27 - Prob. 27.13PCh. 27 - Prob. 27.14PCh. 27 - Prob. 27.15PCh. 27 - Prob. 27.16PCh. 27 - Prob. 27.17PCh. 27 - Prob. 27.18PCh. 27 - Prob. 27.19PCh. 27 - Prob. 27.20PCh. 27 - Prob. 27.21PCh. 27 - Prob. 27.22PCh. 27 - Prob. 27.23PCh. 27 - Prob. 27.24PCh. 27 - Prob. 27.25PCh. 27 - Prob. 27.26PCh. 27 - Prob. 27.27PCh. 27 - Prob. 27.28PCh. 27 - Prob. 27.29PCh. 27 - Prob. 27.30PCh. 27 - Prob. 27.31PCh. 27 - Prob. 27.32PCh. 27 - Prob. 27.33PCh. 27 - Prob. 27.34PCh. 27 - Prob. 27.35PCh. 27 - Prob. 27.36PCh. 27 - Prob. 27.37PCh. 27 - Prob. 27.38PCh. 27 - Prob. 27.39PCh. 27 - Prob. 27.40PCh. 27 - Prob. 27.41PCh. 27 - Prob. 27.42PCh. 27 - Prob. 27.43APCh. 27 - Prob. 27.44APCh. 27 - Prob. 27.45APCh. 27 - Prob. 27.46APCh. 27 - Prob. 27.47APCh. 27 - Prob. 27.48APCh. 27 - Prob. 27.49APCh. 27 - Prob. 27.50APCh. 27 - Prob. 27.51APCh. 27 - Prob. 27.52APCh. 27 - Prob. 27.53APCh. 27 - Prob. 27.54APCh. 27 - Prob. 27.55APCh. 27 - Prob. 27.56APCh. 27 - Prob. 27.57APCh. 27 - Prob. 27.58APCh. 27 - Prob. 27.59APCh. 27 - Prob. 27.60APCh. 27 - Prob. 27.61APCh. 27 - Prob. 27.62APCh. 27 - Prob. 27.63APCh. 27 - Prob. 27.64APCh. 27 - Prob. 27.65APCh. 27 - Prob. 27.66APCh. 27 - Prob. 27.67APCh. 27 - Prob. 27.68APCh. 27 - Prob. 27.69APCh. 27 - Prob. 27.70APCh. 27 - Prob. 27.71APCh. 27 - Prob. 27.72APCh. 27 - Prob. 27.73APCh. 27 - Prob. 27.74APCh. 27 - Prob. 27.75APCh. 27 - Prob. 27.76APCh. 27 - Prob. 27.77APCh. 27 - Prob. 27.78APCh. 27 - Prob. 27.79APCh. 27 - Prob. 27.80APCh. 27 - Prob. 27.81APCh. 27 - Prob. 27.82APCh. 27 - Prob. 27.83AP
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- Hemoglobin A has a pI value of 5.6 whereas the variant hemoglobin M has an aspartate residue in place of the normal valine at position 85 of the alpha chain. What effect will this substitution have on the electrophoretic behavior of the protein at pH 7.0. (explain clearly the reason for your answer)arrow_forwardResearchers analysed a glycopeptide (a peptide carrying one or several oligosaccharide groups) and determined both the sequence of the peptide and the sequence of the sugar molecule. The latter was identified as a diholoside coupled to the peptide by an osidic bond. The systematic name of this sugar is: B-D-glucopyranosyl-(1→4)-ß-D-galactopyranose. : Represent the chemical formula of this diholoside in a way that all oses are Question 1 represented according to the Haworth convention. Apart from the furane and/or pyrane cycles all atoms of this molecule must be given.arrow_forwardSome proteases are cysteine proteases and threonine proteases as opposed to serine proteases. What properties of these amino acids residues allow them to be in a similar catalytic process? Cysteine: R=-CH2SH Threonine: R= -CH(CH3)OHarrow_forward
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