EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 27, Problem 27.33P
Interpretation Introduction
Interpretation:
The structure of
Concept Introduction:
Proteins get attached with oligosaccharide to form glycoproteins. The reaction which involves the attachment of saccharide to a protein is known as glycosylation. There are two types of glycosylation,
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Net charge and isoelectric point of an amino acid with an ionizable side group.Consider the net charge and isoelectric point of an amino acid with ionizable side (R-) group.(a) Identify the acidic amino acid(s) capable of having a negatively charged carboxyl side group.(b) Identify the basic amino acid(s) capable of having a positively charged amino side group.(c) For an amino acid with a side (R-) chain that can ionize to a negative charge, derive a general expression in terms of measured pH and known pKa values of α-carboxyla-amino (pKca), α-amino(pKaa),and side group (pKRa), respectively, for the net charge of an amino acid Consider the net charge and isoelectric point of an amino acid with ionizable side (R-) group.(d) For an amino acid with a side (R-) chain that can ionize to a positive charge, derive a general expression in terms of measured pH and known pKa values ofα-carboxyl (pKca), α-amino (pKaa), and side group (pKRa), respectively, for the net charge of the amino acid.(e)…
Another method to form a peptide bond involves a two-step process
Reaction of the p-nitrophenyl ester with an amino acid ester.
Why does a p-nitrophenyl ester “activate” the carboxy group of thefirst amino acid to amide formation?
Draw the stereoisomers of the following amino acids. Indicate pairs of enantiomers and pairs of diastereomers.
Chapter 27 Solutions
EBK ORGANIC CHEMISTRY
Ch. 27 - Prob. 27.1PCh. 27 - Prob. 27.2PCh. 27 - Prob. 27.3PCh. 27 - Prob. 27.4PCh. 27 - Prob. 27.5PCh. 27 - Prob. 27.6PCh. 27 - Prob. 27.8PCh. 27 - Prob. 27.9PCh. 27 - Prob. 27.10PCh. 27 - Prob. 27.11P
Ch. 27 - Prob. 27.12PCh. 27 - Prob. 27.13PCh. 27 - Prob. 27.14PCh. 27 - Prob. 27.15PCh. 27 - Prob. 27.16PCh. 27 - Prob. 27.17PCh. 27 - Prob. 27.18PCh. 27 - Prob. 27.19PCh. 27 - Prob. 27.20PCh. 27 - Prob. 27.21PCh. 27 - Prob. 27.22PCh. 27 - Prob. 27.23PCh. 27 - Prob. 27.24PCh. 27 - Prob. 27.25PCh. 27 - Prob. 27.26PCh. 27 - Prob. 27.27PCh. 27 - Prob. 27.28PCh. 27 - Prob. 27.29PCh. 27 - Prob. 27.30PCh. 27 - Prob. 27.31PCh. 27 - Prob. 27.32PCh. 27 - Prob. 27.33PCh. 27 - Prob. 27.34PCh. 27 - Prob. 27.35PCh. 27 - Prob. 27.36PCh. 27 - Prob. 27.37PCh. 27 - Prob. 27.38PCh. 27 - Prob. 27.39PCh. 27 - Prob. 27.40PCh. 27 - Prob. 27.41PCh. 27 - Prob. 27.42PCh. 27 - Prob. 27.43APCh. 27 - Prob. 27.44APCh. 27 - Prob. 27.45APCh. 27 - Prob. 27.46APCh. 27 - Prob. 27.47APCh. 27 - Prob. 27.48APCh. 27 - Prob. 27.49APCh. 27 - Prob. 27.50APCh. 27 - Prob. 27.51APCh. 27 - Prob. 27.52APCh. 27 - Prob. 27.53APCh. 27 - Prob. 27.54APCh. 27 - Prob. 27.55APCh. 27 - Prob. 27.56APCh. 27 - Prob. 27.57APCh. 27 - Prob. 27.58APCh. 27 - Prob. 27.59APCh. 27 - Prob. 27.60APCh. 27 - Prob. 27.61APCh. 27 - Prob. 27.62APCh. 27 - Prob. 27.63APCh. 27 - Prob. 27.64APCh. 27 - Prob. 27.65APCh. 27 - Prob. 27.66APCh. 27 - Prob. 27.67APCh. 27 - Prob. 27.68APCh. 27 - Prob. 27.69APCh. 27 - Prob. 27.70APCh. 27 - Prob. 27.71APCh. 27 - Prob. 27.72APCh. 27 - Prob. 27.73APCh. 27 - Prob. 27.74APCh. 27 - Prob. 27.75APCh. 27 - Prob. 27.76APCh. 27 - Prob. 27.77APCh. 27 - Prob. 27.78APCh. 27 - Prob. 27.79APCh. 27 - Prob. 27.80APCh. 27 - Prob. 27.81APCh. 27 - Prob. 27.82APCh. 27 - Prob. 27.83AP
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- Which of the attached amines can be used to resolve a racemic mixture of amino acids?arrow_forwardAnother method to form a peptide bond involves a two-step process Conversion of a Boc-protected amino acid to a p-nitrophenyl ester. Why does a p-nitrophenyl ester “activate” the carboxy group of thefirst amino acid to amide formation?arrow_forwardWhich of the following reagents can be used to cleave a tert-butoxycarbonyl (Boc) protecting group from a peptide? H₂/Pd CF3CO₂H Na₂CO3, H₂O LiAlH4 Barrow_forward
- A globular protein in aqueous surroundings contains the following amino acid residues: phenylalanine, methionine, glutamate, lysine, and alanine. Which amino acid side chains would be directed toward the inside of the protein and which would be directed toward the aqueous surroundings?arrow_forwardWhich of the following amines can be used to resolve a racemic mixture of amino acids?arrow_forwardIf a protein were subjected to an acidic solution, which interactions will be disrupted?arrow_forward
- Researchers analysed a glycopeptide (a peptide carrying one or several oligosaccharide groups) and determined both the sequence of the peptide and the sequence of the sugar molecule. The latter was identified as a diholoside coupled to the peptide by an osidic bond. The systematic name of this sugar is: B-D-glucopyranosyl-(1→4)-ß-D-galactopyranose. : Represent the chemical formula of this diholoside in a way that all oses are Question 1 represented according to the Haworth convention. Apart from the furane and/or pyrane cycles all atoms of this molecule must be given.arrow_forwardDraw the structure of the phenylthiohydantoin derivatives of(a) alanine.arrow_forwardh) Specify the absolute (R/S) configuration of the amino group in structure IV. (i) If the substituents in structures I, IV and V were identical (all OH or all NH2), which structure would result in a meso compound? (j) If each hydroxy group for structures I, II and VI were replaced with another amino group, which compound would be made optically inactive?arrow_forward
- A peptide has the sequence Glu–His–Trp–Ser–Gly–Leu–Arg–Pro–GlyGlu–His–Trp–Ser–Gly–Leu–Arg–Pro–Gly The p?a values for the peptide’s side chains, terminal amino groups, and carboxyl groups are provided in the table. Amino acid Amino pKa Carboxyl pKa Side‑chain pKa glutamate 9.609.60 2.342.34 4.254.25 histidine 9.179.17 1.821.82 6.006.00 tryptophan 9.399.39 2.382.38 serine 9.159.15 2.212.21 glycine 9.609.60 2.342.34 leucine 9.609.60 2.362.36 arginine 9.049.04 2.172.17 12.4812.48 proline 10.9610.96 1.991.99 Calculate the net charge of the molecule at pH 8arrow_forwardAlthough the bond energy for the hydrogen bond in a vacuum is estimated to be about 20 kJ/mol, we find that each hydrogen bond in a folded protein contributes much less--probably less that 5 kJ/mol--to the enthalpy of protein stabilization. Suggest an explanation for this difference. Explain briefly.arrow_forwardLysine and tryptophan are two amino acids that contain an additional N atom in the R group bonded to the a carbon. While lysine is classified as a basic amino acid because it contains an additional basic N atom, tryptophan is classified as a neutral amino acid. Explain why this difference in classification occurs.arrow_forward
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