   Chapter 30, Problem 26PE

Chapter
Section
Textbook Problem

A color television tube also generates some x rays when its electron beam strikes the screen. What is the shortest wavelength of these x rays, if a 30.0-kV potential is used to accelerate the electrons? (Note that TVs have shielding to prevent these x rays from exposing viewers.)

To determine

The shortest wavelength of these x-rays, if a30.0kV potential is used to accelerate the electrons.

Explanation

Given Data:

A color television tube generates some x rays when its electron beam strikes the screen.

30.0kV potential is used to accelerate the electrons.

Formula Used:

The expression for energy is as follows:

E=hcλ

Whereλ= Wavelength

E= Energy of the x-ray photons

h= Planck's constant

c= Speed of light

Also, the energy and voltage is related as follows:

E=qV

Whereq= Charge

V= Voltage applied

Calculation:

We haveE=hcλ

AndE=qV

Equating above two equations for Energy, we get

qV=hcλ

λ=hcqV

We haveh=6.626×1034J

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