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CalculusCalculus (MindTap Course List)8th Edition

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Chapter 3.1, Problem 65E
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Calculus (MindTap Course List)

8th Edition
James Stewart
ISBN: 9781285740621

Solutions

Chapter
Section
Problem 1E
Problem 2E
Problem 3E
Problem 4E
Problem 5E
Problem 6E
Problem 7E
Problem 8E
Problem 9E
Problem 10E
Problem 11E
Problem 12E
Problem 13E
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Problem 15E
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Problem 17E
Problem 18E
Problem 19E
Problem 20E
Problem 21E
Problem 22E
Problem 23E
Problem 24E
Problem 25E
Problem 26E
Problem 27E
Problem 28E
Problem 29E
Problem 30E
Problem 31E
Problem 32E
Problem 33E
Problem 34E
Problem 35E
Problem 36E
Problem 37E
Problem 38E
Problem 39E
Problem 40E
Problem 41E
Problem 42E
Problem 43E
Problem 44E
Problem 45E
Problem 46E
Problem 47E
Problem 48E
Problem 49E
Problem 50E
Problem 51E
Problem 52E
Problem 53E
Problem 54E
Problem 55E
Problem 56E
Problem 57E
Problem 58E
Problem 59E
Problem 60E
Problem 61E
Problem 62E
Problem 63E
Problem 64E
Problem 65E
Problem 66E
Problem 67E
Problem 68E
Problem 69E
Problem 70E
Problem 71E
Problem 72E
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Calculus (MindTap Course List)

8th Edition
James Stewart
ISBN: 9781285740621
Textbook Problem

The water level, measured in feet above mean sea level, of Lake Lanier in Georgia, USA, during 2012 can be modeled by the function

L ( t )   = 0.0144 t 3 −   0.4177 t 2 +   2.703 t   +   1060.1

where t is measured in months since January 1, 2012. Estimate when the water level was highest during 2012.

To determine

To estimate:

When the water level was the highest during 2012.

Explanation

1) Concept:

Use the Closed Interval Method to estimate when the water level was the highest during 2012.

The Closed Interval Method:

To find the absolute maximum and minimum values of a continuous function f on a closed interval a, b:

i. Find the values of f at the critical numbers of f in a, b

ii. Find the values of f at the end points of the interval

iii. The largest of the values from step (i) and (ii) is the absolute maximum value; the smallest of these values is the absolute minimum value.

2) Given:

Lt=0.01441t3-0.4177t2+2.703t1+1060.1

t is measured in months

3) Calculation:

Since t is measured in months, use the interval as 0, 12.

Differentiate Lt with respect to t by using the power rule of derivative.

L'(t)=0.04323t2-0.8354t+2.703

Now set L'(t)=0, and solve for t.

By using the quadratic formula,

t=-b±b2-4ac2a

=0

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