Fundamentals Of Engineering Thermodynamics
9th Edition
ISBN: 9781119391388
Author: MORAN, Michael J., SHAPIRO, Howard N., Boettner, Daisie D., Bailey, Margaret B.
Publisher: Wiley,
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Chapter 4, Problem 4.29P
To determine
Power developed
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The system shown is at steady state, steady flow. At inlet 1, the rates of kinetic
energy, potential energy and enthalpy entering the system are: KE1 = 0.10 kW, PE1
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0.22 kW, and H1 = 27.0 kW. At inlet 2, the rates are: KE2 = 0.23 kW, PE2 = 0.18 kW,
and H2 = 18.0 kVW. At exit 3, the rates are: KE3 = 0.52 kW, PE3 = 0.28 kW, and H3 =
7.0 kW. If the system gives up 5.0 kW of heat to the surroundings, what is the rate of
work transfer of the system? Express the answer in kw.
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KE3
PE3
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Control volume
boundary
A pump is used to circulate hot water in a home heating system. Water enters the well-insulated pump operating at steady state at a
rate of 0.42 gal/min. The inlet pressure and temperature are 14.7 lbf/in.2, and 180°F, respectively; at the exit the pressure is 90 lbf/in.²
The pump requires 1/25 hp of power input. Water can be modeled as an incompressible substance with constant density of 60.58
lb/ft3 and constant specific heat of 1 Btu/lb. °R.
Neglecting kinetic and potential energy effects, determine the temperature change, in °R, as the water flows through the pump.
AT =
°R
A pump is used to circulate hot water in a home heating system. Water enters the well-insulated pump operating at steady state at a rate of 0.42 gal/min. The inlet pressure and temperature are 14.7 lbf/in.2, and 180°F, respectively; at the exit the pressure is 60 lbf/in.2 The pump requires 1/ 35 hp of power input. Water can be modeled as an incompressible substance with constant density of 60.58 lb/ft3 and constant specific heat of 1 Btu/lb · °R. Neglecting kinetic and potential energy effects, determine the temperature change, in °R, as the water flows through the pump.
Chapter 4 Solutions
Fundamentals Of Engineering Thermodynamics
Ch. 4 - Prob. 4.1ECh. 4 - Prob. 4.2ECh. 4 - Prob. 4.3ECh. 4 - Prob. 4.4ECh. 4 - Prob. 4.5ECh. 4 - Prob. 4.6ECh. 4 - Prob. 4.7ECh. 4 - Prob. 4.8ECh. 4 - Prob. 4.9ECh. 4 - Prob. 4.10E
Ch. 4 - Prob. 4.11ECh. 4 - Prob. 4.12ECh. 4 - Prob. 4.13ECh. 4 - Prob. 4.14ECh. 4 - Prob. 4.15ECh. 4 - Prob. 4.1CUCh. 4 - Prob. 4.2CUCh. 4 - Prob. 4.3CUCh. 4 - Prob. 4.4CUCh. 4 - Prob. 4.5CUCh. 4 - Prob. 4.6CUCh. 4 - Prob. 4.7CUCh. 4 - Prob. 4.8CUCh. 4 - Prob. 4.9CUCh. 4 - Prob. 4.10CUCh. 4 - Prob. 4.11CUCh. 4 - Prob. 4.12CUCh. 4 - Prob. 4.13CUCh. 4 - Prob. 4.14CUCh. 4 - Prob. 4.15CUCh. 4 - Prob. 4.16CUCh. 4 - Prob. 4.17CUCh. 4 - Prob. 4.18CUCh. 4 - Prob. 4.19CUCh. 4 - Prob. 4.20CUCh. 4 - Prob. 4.21CUCh. 4 - Prob. 4.22CUCh. 4 - Prob. 4.23CUCh. 4 - Prob. 4.24CUCh. 4 - Prob. 4.25CUCh. 4 - Prob. 4.26CUCh. 4 - Prob. 4.27CUCh. 4 - Prob. 4.28CUCh. 4 - Prob. 4.29CUCh. 4 - Prob. 4.30CUCh. 4 - Prob. 4.31CUCh. 4 - Prob. 4.32CUCh. 4 - Prob. 4.33CUCh. 4 - Prob. 4.34CUCh. 4 - Prob. 4.35CUCh. 4 - Prob. 4.36CUCh. 4 - Prob. 4.37CUCh. 4 - Prob. 4.38CUCh. 4 - Prob. 4.39CUCh. 4 - Prob. 4.40CUCh. 4 - Prob. 4.41CUCh. 4 - Prob. 4.42CUCh. 4 - Prob. 4.43CUCh. 4 - Prob. 4.44CUCh. 4 - Prob. 4.45CUCh. 4 - Prob. 4.46CUCh. 4 - Prob. 4.47CUCh. 4 - Prob. 4.48CUCh. 4 - Prob. 4.49CUCh. 4 - Prob. 4.50CUCh. 4 - Prob. 4.51CUCh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. 4.7PCh. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. 4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. 4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. 4.56PCh. 4 - Prob. 4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. 4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. 4.63PCh. 4 - Prob. 4.64PCh. 4 - Prob. 4.65PCh. 4 - Prob. 4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. 4.73PCh. 4 - Prob. 4.74PCh. 4 - Prob. 4.75PCh. 4 - Prob. 4.76PCh. 4 - Prob. 4.77PCh. 4 - Prob. 4.78PCh. 4 - Prob. 4.79PCh. 4 - Prob. 4.80PCh. 4 - Prob. 4.81PCh. 4 - Prob. 4.82PCh. 4 - Prob. 4.83PCh. 4 - Prob. 4.84PCh. 4 - Prob. 4.85PCh. 4 - Prob. 4.86PCh. 4 - Prob. 4.87PCh. 4 - Prob. 4.88P
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- A pump is used to circulate hot water in a home heating system. Water enters the well-insulated pump operating at steady state at a rate of 0.42 gal/min. The inlet pressure and temperature are 14.7 Ibf/in.², and 180°F, respectively; at the exit the pressure is 120 Ibf/in.2 The pump requires 1/ 15 hp of power input. Water can be modeled as an incompressible substance with constant density of 60.58 Ib/ft3 and constant specific heat of 1 Btu/lb · °R. Neglecting kinetic and potential energy effects, determine the temperature change, in °R, as the water flows through the pump. AT = i °Rarrow_forwardAn oil pump operating at steady state delivers oil at a rate of 10 Ib/s through a 1-in.-diameter exit pipe. The oil, which can be modeled as incompressible, has a density of 100 lb/ft and experiences a pressure rise from inlet to exit of 40 Ibf/in?. There is no significant elevation difference between inlet and exit, and the inlet kinetic energy is negligible. Heat transfer between the pump and its surroundings is negligible, and there is no significant change in temperature as the oil passes through the pump. Determine the velocity of the oil at the exit of the pump, in ft/s, and the power required for the pump, in hp.arrow_forwardA turbine operating under steady-flow conditions receives steam at the following state; pssure,100 bar; specific internal energy 2773 kJ/kg, velocity 30 m/s. the state of steam leaving the turbine is as follow: pressure 1 bar, specific internal energy 2450 kJ/kg, velocity 90 m/s. Heat is rejected to the surroundings at the rate of 0.25 kW and the rate of steam flow through the turbine is 0.4 kg/s calculate the power developed by the .turbinearrow_forward
- Liquid water flows isothermally at 20°C through a one-inlet, one-exit duct operating at steady state. The duct's inlet and exit P2 = 4.8 bar T = 320°C diameters are 0.02 m and 0.04 m, Water vapor (AV)2 = (AV)3 respectively. At the inlet, the velocity is 50 m/s and the pressure is 1 bar. At the exit, determine the mass flow rate, in kg/s, and V, T A1 = 0.2 m? P1 = 5 bar 3 velocity, in m/s. P3= 4.8 bar T3 = 320°Carrow_forwardSteam enters a turbine operating at steady state at 850oF and 450 lbf/in2 and leaves as a saturated vapor at 1.4 lbf/in2. The turbine develops 12,000 hp, and heat transfer from the turbine to the surroundings occurs at a rate of 2 x 106 Btu/h. Neglect kinetic and potential energy changes from inlet to exit. Determine the exit temperature, in oF, and the volumetric flow rate of the steam at the inlet, in ft3/s.arrow_forwardAir enters a nozzle operating at steady-state at 800°R, with a negligible velocity, and exits with a velocity of 1500 ft/s. Heat transfer occurs from the nozzle to the surroundings at a rate of 10 Btu per lbm of air flowing. Determine the temperature at the exit, °R. Assume: o air is an ideal gas, variable specific heats, and o potential energy effects are negligible.arrow_forward
- Refrigerant 134a enters an insulated diffuser as a saturated vapor at 80 deg F with a velocity of 800 ft/s. The inlet area is 1.4 in^2. At the exit, the pressure is 400 lbf/in2 and the velocity is negligible. The diffuser operates at steady state and potential energy effects can be neglected. Determine the mass flow rate, in lb/s, and the exit temperature, in deg F.arrow_forwardNo entropy accompanies work as it crosses the system boundary. But entropy may be generated within the system as work is dissipated into a less useful form of energy.arrow_forwardAir expands through a turbine operating at steady state. At the inlet, p1 = 150 lbf/in.?, T1 = 1400°R, and at the exit, p2 = 14.8 lbf/in.?, T2 = 900°R. The mass flow rate of air entering the turbine is 11 lb/s, and 65,000 Btu/h of energy is rejected by heat transfer. Neglecting kinetic and potential energy effects, determine the power developed, in hp. Wey = i hp cvarrow_forward
- The entropy change between two specified states is the same whether the process is reversible or irreversible.arrow_forwardAir flows through a nozzle. It enters at 20 bar and 1100°F and exits at 10 bar and 800°F. The inlet diameter ratio between outlet diameter is 3. Consider steady state, determine air inlet and outlet velocities, in ft/sarrow_forward5. Air enters a compressor at a rate of 0.5 Kgs¹ with a velocity of 6.4 ms', specific volume 0.85 m³Kg¹ and a pressure of 1 bar. It leaves the compressor at a pressure of 6.9 bar with a specific volume of 0.16 m³Kg¹ and a velocity of 4.7 ms¹. The internal energy of the air at exit is greater than that at entry by 85 KJKg'. The compressor is fitted with a cooling system which removes heat at a rate of 60 KJs¹. Calculate the power required to drive the compressor and the cross- sectional areas of the inlet and outlet pipes.arrow_forward
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