Fundamentals Of Engineering Thermodynamics
9th Edition
ISBN: 9781119391388
Author: MORAN, Michael J., SHAPIRO, Howard N., Boettner, Daisie D., Bailey, Margaret B.
Publisher: Wiley,
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Chapter 4, Problem 4.12CU
To determine
The correct statement for the time rate of change of the energy contained within a one-inlet, one-exit control volume at the time
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Air enters a compressor operating at steady state with a pressure of 14.7 Ibf/in.? and a
temperature of 70°F. The volumetric flow rate at the inlet is 16.6 ft'/s, and the flow area is
0.26 ft'. At the exit, the pressure is 35 Ibf'in.?, the temperature is 280°F, and the velocity is
50 fu's. Heat transfer from the compressor to its surroundings is 1.0 Btu per Ib of air flowing.
Potential energy effects are negligible, and the ideal gas model can be assumed for the air.
Determine the compressor power, in Btu/s and hp. Ans. W = -63.9 Btu/s and -90.38 hp
5. Air enters a compressor at a rate of 0.5 Kgs¹ with a velocity
of 6.4 ms', specific volume 0.85 m³Kg¹ and a pressure of 1
bar. It leaves the compressor at a pressure of 6.9 bar with a
specific volume of 0.16 m³Kg¹ and a velocity of 4.7 ms¹.
The internal energy of the air at exit is greater than that at
entry by 85 KJKg'. The compressor is fitted with a cooling
system which removes heat at a rate of 60 KJs¹. Calculate
the power required to drive the compressor and the cross-
sectional areas of the inlet and outlet pipes.
= 95°F and m3 = 1.5 lb/s. Refrigerant 134a
The figure belows shows three components of an air-conditioning system, where T3
flows through a throttling valve and a heat exchanger while air flows through a fan and the same heat exchanger. Data for steady-
state operation are given on the figure. There is no significant heat transfer between any of the components and the surroundings.
Kinetic and potential energy effects are negligible.
Air
Tj = 535°R
C,= 0.240 Btu/I6•°R
Saturated liquid R-134a
T3, ṁ3
Fan
Wey = -0.2 hp
Throttling
valve
4
Saturated vapor
P5=P4
P4 = 60 lbf/in.2
T = 528°R
-Heat exchanger
Modeling air as an ideal gas with constant c, = 0.240 Btu/lb· °R, determine the mass flow rate of the air, in Ib/s.
i
Ib/s
Chapter 4 Solutions
Fundamentals Of Engineering Thermodynamics
Ch. 4 - Prob. 4.1ECh. 4 - Prob. 4.2ECh. 4 - Prob. 4.3ECh. 4 - Prob. 4.4ECh. 4 - Prob. 4.5ECh. 4 - Prob. 4.6ECh. 4 - Prob. 4.7ECh. 4 - Prob. 4.8ECh. 4 - Prob. 4.9ECh. 4 - Prob. 4.10E
Ch. 4 - Prob. 4.11ECh. 4 - Prob. 4.12ECh. 4 - Prob. 4.13ECh. 4 - Prob. 4.14ECh. 4 - Prob. 4.15ECh. 4 - Prob. 4.1CUCh. 4 - Prob. 4.2CUCh. 4 - Prob. 4.3CUCh. 4 - Prob. 4.4CUCh. 4 - Prob. 4.5CUCh. 4 - Prob. 4.6CUCh. 4 - Prob. 4.7CUCh. 4 - Prob. 4.8CUCh. 4 - Prob. 4.9CUCh. 4 - Prob. 4.10CUCh. 4 - Prob. 4.11CUCh. 4 - Prob. 4.12CUCh. 4 - Prob. 4.13CUCh. 4 - Prob. 4.14CUCh. 4 - Prob. 4.15CUCh. 4 - Prob. 4.16CUCh. 4 - Prob. 4.17CUCh. 4 - Prob. 4.18CUCh. 4 - Prob. 4.19CUCh. 4 - Prob. 4.20CUCh. 4 - Prob. 4.21CUCh. 4 - Prob. 4.22CUCh. 4 - Prob. 4.23CUCh. 4 - Prob. 4.24CUCh. 4 - Prob. 4.25CUCh. 4 - Prob. 4.26CUCh. 4 - Prob. 4.27CUCh. 4 - Prob. 4.28CUCh. 4 - Prob. 4.29CUCh. 4 - Prob. 4.30CUCh. 4 - Prob. 4.31CUCh. 4 - Prob. 4.32CUCh. 4 - Prob. 4.33CUCh. 4 - Prob. 4.34CUCh. 4 - Prob. 4.35CUCh. 4 - Prob. 4.36CUCh. 4 - Prob. 4.37CUCh. 4 - Prob. 4.38CUCh. 4 - Prob. 4.39CUCh. 4 - Prob. 4.40CUCh. 4 - Prob. 4.41CUCh. 4 - Prob. 4.42CUCh. 4 - Prob. 4.43CUCh. 4 - Prob. 4.44CUCh. 4 - Prob. 4.45CUCh. 4 - Prob. 4.46CUCh. 4 - Prob. 4.47CUCh. 4 - Prob. 4.48CUCh. 4 - Prob. 4.49CUCh. 4 - Prob. 4.50CUCh. 4 - Prob. 4.51CUCh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. 4.7PCh. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. 4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. 4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. 4.56PCh. 4 - Prob. 4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. 4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. 4.63PCh. 4 - Prob. 4.64PCh. 4 - Prob. 4.65PCh. 4 - Prob. 4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. 4.73PCh. 4 - Prob. 4.74PCh. 4 - Prob. 4.75PCh. 4 - Prob. 4.76PCh. 4 - Prob. 4.77PCh. 4 - Prob. 4.78PCh. 4 - Prob. 4.79PCh. 4 - Prob. 4.80PCh. 4 - Prob. 4.81PCh. 4 - Prob. 4.82PCh. 4 - Prob. 4.83PCh. 4 - Prob. 4.84PCh. 4 - Prob. 4.85PCh. 4 - Prob. 4.86PCh. 4 - Prob. 4.87PCh. 4 - Prob. 4.88P
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- 2. A turbine operates under steady flow conditions receiving steam at the following state: pressure 1200 kilo pascal, temperature 188 degrees celsius, Enthalpy 2785 kilojoule per kilogram, speed 33.3 meter per second and elevation 3 m the steam leaves the turbine at the following state; pressure 20 kilo pascal, enthalpy 2512 kilojoule per kilogram, speed 100 m per second and elevation 0 m. Heat is lost to the surroundings at the rate of 0.29 kilojoule per second. if the rate of steam flow through the turbine is 0.42 kg per second. What is the work in kJ/kg and what is the power output of the turbine in kw?arrow_forwardTRUE OR FALSE 1. Heat flows from hot object to cold object and vice versa, as exhibited by heat pumps.2. It's impossible to have 100% efficient engines, however, it's possible to convert 100% of heat into useful work.3. Natural processes tend to be more ordered than disordered due to entropy.4. The efficiency e of a heat engine is defined as the ratio of the work W done by the engine to the high temperature heat input Qh.5. All heat engines give rise to thermal pollution.arrow_forward* Your answer is incorrect. A pump is used to circulate hot water in a home heating system. Water enters the well-insulated pump operating at steady state at a rate of 0.42 gal/min. The inlet pressure and temperature are 14.7 lbf/in.², and 180°F, respectively; at the exit the pressure is 90 lbf/in.² The pump requires 1/15 hp of power input. Water can be modeled as an incompressible substance with constant density of 60.58 lb/ft3 and constant specific heat of 1 Btu/lb. °R. Neglecting kinetic and potential energy effects, determine the temperature change, in °R, as the water flows through the pump. ΔΤ : = i 0.36 °Rarrow_forward
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