Fundamentals Of Engineering Thermodynamics
9th Edition
ISBN: 9781119391388
Author: MORAN, Michael J., SHAPIRO, Howard N., Boettner, Daisie D., Bailey, Margaret B.
Publisher: Wiley,
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Chapter 4, Problem 4.49CU
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Chapter 4 Solutions
Fundamentals Of Engineering Thermodynamics
Ch. 4 - Prob. 4.1ECh. 4 - Prob. 4.2ECh. 4 - Prob. 4.3ECh. 4 - Prob. 4.4ECh. 4 - Prob. 4.5ECh. 4 - Prob. 4.6ECh. 4 - Prob. 4.7ECh. 4 - Prob. 4.8ECh. 4 - Prob. 4.9ECh. 4 - Prob. 4.10E
Ch. 4 - Prob. 4.11ECh. 4 - Prob. 4.12ECh. 4 - Prob. 4.13ECh. 4 - Prob. 4.14ECh. 4 - Prob. 4.15ECh. 4 - Prob. 4.1CUCh. 4 - Prob. 4.2CUCh. 4 - Prob. 4.3CUCh. 4 - Prob. 4.4CUCh. 4 - Prob. 4.5CUCh. 4 - Prob. 4.6CUCh. 4 - Prob. 4.7CUCh. 4 - Prob. 4.8CUCh. 4 - Prob. 4.9CUCh. 4 - Prob. 4.10CUCh. 4 - Prob. 4.11CUCh. 4 - Prob. 4.12CUCh. 4 - Prob. 4.13CUCh. 4 - Prob. 4.14CUCh. 4 - Prob. 4.15CUCh. 4 - Prob. 4.16CUCh. 4 - Prob. 4.17CUCh. 4 - Prob. 4.18CUCh. 4 - Prob. 4.19CUCh. 4 - Prob. 4.20CUCh. 4 - Prob. 4.21CUCh. 4 - Prob. 4.22CUCh. 4 - Prob. 4.23CUCh. 4 - Prob. 4.24CUCh. 4 - Prob. 4.25CUCh. 4 - Prob. 4.26CUCh. 4 - Prob. 4.27CUCh. 4 - Prob. 4.28CUCh. 4 - Prob. 4.29CUCh. 4 - Prob. 4.30CUCh. 4 - Prob. 4.31CUCh. 4 - Prob. 4.32CUCh. 4 - Prob. 4.33CUCh. 4 - Prob. 4.34CUCh. 4 - Prob. 4.35CUCh. 4 - Prob. 4.36CUCh. 4 - Prob. 4.37CUCh. 4 - Prob. 4.38CUCh. 4 - Prob. 4.39CUCh. 4 - Prob. 4.40CUCh. 4 - Prob. 4.41CUCh. 4 - Prob. 4.42CUCh. 4 - Prob. 4.43CUCh. 4 - Prob. 4.44CUCh. 4 - Prob. 4.45CUCh. 4 - Prob. 4.46CUCh. 4 - Prob. 4.47CUCh. 4 - Prob. 4.48CUCh. 4 - Prob. 4.49CUCh. 4 - Prob. 4.50CUCh. 4 - Prob. 4.51CUCh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. 4.7PCh. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. 4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. 4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. 4.56PCh. 4 - Prob. 4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. 4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. 4.63PCh. 4 - Prob. 4.64PCh. 4 - Prob. 4.65PCh. 4 - Prob. 4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. 4.73PCh. 4 - Prob. 4.74PCh. 4 - Prob. 4.75PCh. 4 - Prob. 4.76PCh. 4 - Prob. 4.77PCh. 4 - Prob. 4.78PCh. 4 - Prob. 4.79PCh. 4 - Prob. 4.80PCh. 4 - Prob. 4.81PCh. 4 - Prob. 4.82PCh. 4 - Prob. 4.83PCh. 4 - Prob. 4.84PCh. 4 - Prob. 4.85PCh. 4 - Prob. 4.86PCh. 4 - Prob. 4.87PCh. 4 - Prob. 4.88P
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- energy of the water. 2.) A room air conditioner has a coefficient of performance of 2.9 on a hot day and uses 850 W of electrical power. (a) How many joules of heat does the air conditioner remove from the room in one minute? (b) How many joules of heat does the air conditioner deliver to the hot outside air in one minute? (c) Explain why your answers to parts (a) and (b) are not the same. 24 Carnot beat engine has a thermal efficiency of 0.600, and the temperature of its hot reservoir is 800arrow_forward6.107 Figure P6.107 provides the schematic of a heat pump using Refrigerant 134a as the working fluid, together with steady-state data at key points. The mass flow rate of the refrigerant is 7 kg/min, and the power input to the compressor is 5.17 kW. (a) Determine the co- efficient of performance for the heat pump. (b) If the valve were re- placed by a turbine, power could be produced, thereby reducing the power requirement of the heat pump system. Would you recommend this power-saving measure? Explain. She P2 = P3 = 9 bar Tz = 60°C Saturated liquid Condenser Expansion W = 5.17 kW Compressor valve Evaporator m= 7 kg/min P1 =P4 = 2.4 bar FIGURE P6.107arrow_forwardThe figure below shows a vapor power cycle that provides process heat and produces power. The steam generator produces vapor at 500 lbf/in.², 800°F, at a rate of 8 x 105 lb/h. Eighty-eight percent of the steam expands through the turbine to 10 lbf/in.² and the remainder is directed to the heat exchanger. Saturated liquid exits the heat exchanger at 500 lbf/in.2 and passes through a trap before entering the condenser at 10 lbf/in.² Saturated liquid exits the condenser at 10 lbf/in.2 and is pumped to 500 lbf/in.2 before entering the steam generator. The turbine and pump have isentropic efficiencies of 85% and 89%, respectively. For the process heat exchanger, assume the temperature at which heat transfer occurs is 465°F. Let To = 60°F, po = 14.7 lbf/in.² Determine: Steam generator 1₂=89% P-500lb/² 7₁ = 80XFF M₁ Heat exchanger Pamp B 1 (1-y) гибши 4-85% P= 500 lbfin? saturated liquid P=10 lbffin² saturated liquid Turbine W₁ Py=1002 me Condenser (a) the magnitude of the process heat…arrow_forward
- The figure below shows a vapor power cycle that provides process heat and produces power. The steam generator produces vapor at 500 lbf/in.², 800°F, at a rate of 8 x 105 lb/h. Eighty-eight percent of the steam expands through the turbine to 10 lbf/in.² and the remainder is directed to the heat exchanger. Saturated liquid exits the heat exchanger at 500 lbf/in.² and passes through a trap before entering the condenser at 10 lbf/in.² Saturated liquid exits the condenser at 10 lbf/in.² and is pumped to 500 lbf/in.² before entering the steam generator. The turbine and pump have isentropic efficiencies of 85% and 89%, respectively. For the process heat exchanger, assume the temperature at which heat transfer occurs is 465°F. Let To = 60°F. Po = 14.7 lbf/in.² Determine: Steam generator P₁=500 lbf/in.2 T₁ = 800°F 7p=89% Heat exchanger Pump (y) 1 minn (1-y) 77 = 85% Oprocess P4= 500 lbf/in.² saturated liquid P3= 10 lbf/in.² saturated liquid Turbine W₂ P₂=10 lbf/in.² 2 Condenser (a) the…arrow_forwardThe figure below shows a vapor power cycle that provides process heat and produces power. The steam generator produces vapor at 500 lbf/in.2, 800°F, at a rate of 8 x 104 lb/h. Fifty-two percent of the steam expands through the turbine to 10 lbf/in.2 and the remainder is directed to the heat exchanger. Saturated liquid exits the heat exchanger at 500 lbf/in.2 and passes through a trap before entering the condenser at 10 lbf/in.2Saturated liquid exits the condenser at 10 lbf/in.2 and is pumped to 500 lbf/in.2 before entering the steam generator. The turbine and pump have isentropic efficiencies of 85% and 89%, respectively. For the process heat exchanger, assume the temperature at which heat transfer occurs is 465°F. Let T0 = 60°F, p0 = 14.7 lbf/in.2 Determine:(a) the magnitude of the process heat production rate, in Btu/h.(b) the magnitude of the rate of exergy output, in Btu/h, as net work.(c) the rate of exergy transfer, in Btu/h, to the working fluid passing through the steam…arrow_forwardThe figure below shows a vapor power cycle that provides process heat and produces power. The steam generator produces vapor at 500 lbf/in.2, 800°F, at a rate of 8 x 104 lb/h. Eighty-eight percent of the steam expands through the turbine to 10 lbf/in.2 and the remainder is directed to the heat exchanger. Saturated liquid exits the heat exchanger at 500 lbf/in.2 and passes through a trap before entering the condenser at 10 lbf/in.2Saturated liquid exits the condenser at 10 lbf/in.2 and is pumped to 500 lbf/in.2 before entering the steam generator. The turbine and pump have isentropic efficiencies of 85% and 89%, respectively. For the process heat exchanger, assume the temperature at which heat transfer occurs is 465°F. Let T0 = 60°F, p0 = 14.7 lbf/in.2 Determine:(a) the magnitude of the process heat production rate, in Btu/h.(b) the magnitude of the rate of exergy output, in Btu/h, as net work.(c) the rate of exergy transfer, in Btu/h, to the working fluid passing through the steam…arrow_forward
- A well-insulated, thin-walled, counter-flow heat exchanger is to be used to cooloil (cp = 2.20 kJ/kg∙ oC) from 150 to 40oC at a rate of 2 kg/s by water (cp = 4.18kJ/kg∙oC) that enters at 22oC and leaves at 40oC. Assuming a steady flow system,determine (a) the required mass flow rate (kg/s) of cooling water necessary to meatthe desired cooling rate (b) heat transfer rate (kW).arrow_forwardChoose correct answer: Refrigerators and heat pumps operate on the same cycle but differ in their objectives. Select one: True Falsearrow_forward4.) Why must a room air conditioner be placed in a window rather than just set on the floor and plugged in? Why can a refrigerator be set on the floor and plugged in?arrow_forward
- Separate streams of steam and air flow through the turbine and heat exchanger arrangement shown in the figure below, where ins = 1500 kg/min and W;1 = 8,000 kW,. Steady-state operating data are provided on the figure. Heat transfer with the surroundings can be neglected, as can all kinetic and potential energy effects. Wn W2 = ? Turbine Turbine 2 P3 = 10 bar T3 =? T = 240°C T2 = 400°C P2= 10 bar P4=1 bar www Steam in 2 T = 600°C PI = 20 bar Ts = 1500 K -5 Ps = 1.35 bar 9. Heat exchanger V T6 = 1200 K P6 = 1 bar Air in Determine: (a) T3, in K. (b) the power output of the second turbine, in kW.arrow_forwardRefrigerant 134a is the working fluid in a vapor compression heat pump that provides 35 kW heat to a dwelling. Saturated vapor enters the compressor at 1.6 bar, and saturated liquid exits the condenser, which operates at 8 bars. Isentropic efficiency of the compressor is 75%. The pressure drops across the condenser and evaporator can be neglected. Kinetic and potential energy changes are negligible. a) Determine the compressor power, in kW b) Determine the coefficient of performance (COP) c) Draw the processes in a T-s diagramarrow_forwards) The device shown below is the one that extracts work from combustion. Combusted products can be regarded as ideal gases with constant specific heats, Cp= 1.4 kJ/kg-K, c₂= 1.0 kJ/kg.K. Every heat transfer occurs via a reversible process, and all work is produced via adiabatic reversible processes. Determine The heat transfer rate to the ambient that makes the engine reversible T = 540 °C P = 100 kPa m = 5 kg/s Combustion Gas Flow T = 40 °C P = 100 kPa QH Engine QL Ambient T = 21 °C, P = 100 kPa Warrow_forward
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