   Chapter 5, Problem 10RE ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Finding Indefinite Integrals In Exercises 1–14, find the indefinite integral. Check your result by differentiating. ∫ ( 4 − 7 x − 6 x 2 )   d x

To determine

To calculate: The indefinite integral (47x6x2)dx.

Explanation

Given Information:

The provided indefinite integral is (47x6x2)dx.

Formula used:

The power rule of integrals:

undu=xn+1n+1+C (for n1)

The power rule of differentiation:

dduun=nun1+C

Calculation:

Consider the indefinite integral:

(47x6x2)dx

Rewrite as,

(47x6x2)dx=(4)dx(7x)dx(6x2)dx

Now apply, the power rule of integrals:

(4x0)dx(7x)dx(6x

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