   Chapter 5, Problem 29RE ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# Applying the General Power Rule In Exercises 21–32, find the indefinite integral. Check your result by differentiating. ∫ x 2 ( 2 x 3 − 5 ) 3   d x

To determine

To calculate: The indefinite integral x2(2x35)3dx.

Explanation

Given Information:

The provided indefinite integral is x2(2x35)3dx.

Formula used:

The power rule of integrals:

undu=un+1n+1+C (n1)

The power rule of differentiation:

ddxun=nun1+C

Calculation:

Consider the indefinite integral:

x2(2x35)3dx

Let u=2x35, then derivative will be,

du=d(2x35)=6xdx

Rewrite integration as,

x2(2x35)3dx=16(2x35)36xdx

Substitute du for 6xdx and u for 2x35 in provided integration

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