   Chapter 5.3, Problem 4QY ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# In Exercises 1-9, find the indefinite integral. Check your result by differentiating. ∫ ( x 2 − 2 x + 15 ) d x

To determine

To calculate: The value of indefinite integral (x22x+15)dx.

Explanation

Given information:

The indefinite integral (x22x+15)dx.

Formula used:

Sum and difference rule of integration is [f(x)±g(x)] dx=[f(x)]dx±[g(x)]dx

Where, f(x) and g(x) are any two functions.

Constant Multiplication Rule:

axdx=axdx

Where a is any constant.

Power rule of integral:

xndx=xn+1n+1+C

Simple Differentiation rule:

ddx(xn)=nxn1

Where C and n are constants.

Calculation:

Consider the provided integral,

(x22x+15)dx

Apply sum and difference rule of integration in (x22x+15)dx,

(x22x+15)dx=x2<

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 