   Chapter 5.3, Problem 7QY ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# In Exercises 1-9, find the indefinite integral. Check your result by differentiating. ∫ ( x 2 − 5 x ) ( 2 x − 5 ) d x

To determine

To calculate: The indefinite integral (x25x)(2x5)dx.

Explanation

Given Information:

The provided indefinite integral is (x25x)(2x5)dx.

Formula used:

The power rule of integrals:

undu=xn+1n+1+C (for n1)

The power rule of differentiation:

dduun=nun1+C

Calculation:

Consider the indefinite integral:

(x25x)(2x5)dx

Let u=x25x, then derivative will be,

du=d(x25x)=(2x5)dx

Substitute du for (2x5)dx and u for x25x in provided integration

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