PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
7th Edition
ISBN: 9781119610526
Author: Mannering
Publisher: WILEY
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Chapter 7, Problem 4P
To determine
The estimated effective green time of the fourth timing stage.
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A fixed time two-phase signal is to be designed for a four-legged intersection, for which the design
hourly flow and saturation flow are given below:
Details of flow
Details hourly flow (veh/h)
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North South East
West
570 320 550 455
1750 1500 2210 2265
Time lost per phase due to starting delays is 2 seconds. Calculate the optimum cycle time and
allocate the green time for the two phases using Webster's method.
A pretimed four-phase signal has critical lane group flow rates for the first three phases of 200, 187, and 210 veh/h (saturation flow rates are 1800 veh/h/ln for all phases). The lost time is known to be 4 seconds for each phase. Assuming Xi = 0.9. If the cycle length is 60 seconds, what is the estimated effective green time of the fourth phase?
An intersection has a three-phase signal with the movements allowed in each phase and corresponding
analysis and saturation flow rates shown in the table below. Assume the lost time is 4 seconds per phase and a
critical intersection v/c of 0.90 is desired.
Phase
3
Allowed movements
NB L, SB L
NB T/R, SB T/R
EB L, WB L
ЕВ TR, WB TR
Analy sis flow rate
330, 365 veh/h
1125, 1075 veh/h
110, 80 veb/h
250, 285 veh/h
Saturation flow rate
1700, 1750 veh/h
3400, 3300 veh/h
650, 600 veh/h
1750, 1800 veh/h
Calculate the sum of the flow ratios for the critical lane groups.
0.787
O 0.857
O 0.709
O 0,829
Chapter 7 Solutions
PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
Ch. 7 - Prob. 1PCh. 7 - Prob. 2PCh. 7 - Prob. 3PCh. 7 - Prob. 4PCh. 7 - Prob. 5PCh. 7 - Prob. 6PCh. 7 - Prob. 7PCh. 7 - Prob. 8PCh. 7 - Prob. 9PCh. 7 - Prob. 10P
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- Exercise 6 A three phase signal design is given below. ● ● ● Hic Signal What is the sum of the flow ratios for the critical lane groups? What is the total lost time for a signal cycle assuming 2 seconds of clearance lost time and 2 seconds of startup lost time per phase? What is the cycle length using Webster Method? EB - Phase 1 2 3 -200 20 SB 30 100- Lane group SB NB EB WB 400 1000 NB 150 50 300 30 WB Saturation Flows 3400 veh/hr 3400 veh/hr 1400 veh/hr 1400 veh/hrarrow_forwardAn isolated three-phase signal is being designed for optimum cycle length of 90 s. The total lost time from all the three phases is 15-s. The critical flow ratios for phase I and II are 0.2 and 0.3 respectively. Determine the critical flow ratio for phase III as per Webster's method of traffic signal design. Given that saturation flow for volume in phase III is 500 pcu. SI C 20161arrow_forwardA signalized intersection has four phases. The yci are 0.15, 0.19, 0.21, and 0.17 for the four phases, respectively. If the cycle length is 108 seconds and the total lost time is 16 seconds, what is the effective green time for phase 2? Group of answer choices 23 sec 25 sec 21 sec 19 secarrow_forward
- The average normal flow on cross roads A and B during design period are 400 and 250 pcu per hour. The saturations flow values on these roads are estimated as 1200 and 1000 pcu per hour respectively. The all-red time required for pedestrian crossing is 12secs. Calculate cycle time for two phase signal system.arrow_forwardAn intersection has a three-phase signal with the movements allowed in each phase and corresponding analysis and saturation flow rates shown in the table below. Assume the lost time is 4 seconds per phase and a critical intersection v/c of 0.90 is desired. O 12.105 sec O 15.954 sec O 13.190 sec Phase O 14.127 sec Allowed movements Analysis flow rate Saturation flow rate 1 NB L, SB L 330, 365 veh/h 1700, 1750 veh/h Using v/c equalization ratio, calculate the effective green time for phase 1 2 NB T/R, SB T/R 1125, 1075 veh/h 3400, 3300 veh/h EBL, WBL 110, 80 veh/h 650, 600 veh/h 3 EB T/R, WB T/R 250, 285 veh/h 1750, 1800 veh/harrow_forwardAn intersection has a three-phase signal with the movements allowed in each phase and corresponding analysis and saturation flow rates shown in the table below. Assume the lost time is 4 seconds per phase and a critical intersection v/c of 0.90 is desired. Phase 3 Allowed movements NB L, SB L NB T/R, SB T/R EB L, WB L EB TR, WB TR Analysis flow rate 330, 365 veh/h 1125, 1075 veh/h 110, 80 veh/h 250, 285 veh/h Saturation flow rate 1700, 1750 veh/h 3400, 3300 vehh 650, 600 veh/h 1750, 1 800 veh/h Using v/c equalization ratio, calculate the effective green time for phase 3 14.825 sec 15.552 sec O 11.462 sec O 16.065 secarrow_forward
- An intersection has a four-phase signal with the movements allowed in each phase and corresponding analysis and saturation flow rates shown in the table below. Phase Allowed movements Analysis flow rate Saturation flow rate O 116.466 sec O 97.315 sec O 104.693 sec 1 EB L, WB L 245, 230 veh/h 1750, 1725 veh/h Calculate the optimum cycle length (Assume 4 seconds lost time per phase) O 101.399 sec 2 EB T/R, WB T/R 975, 1030 veh/h 3350, 3400 veh/h 3 SB L, SB T/R 255, 235 veh/h 1725, 1750 veh/h 4 NB L, NB T/R 225, 215 veh/h 1700, 1750 veh/harrow_forwardFor designing a 2-phase fixed type signal at an intersection having North-South and East-West road where only straight ahead traffic permitted, the following data are available. Parameter Design North Hour Flow (PCU/hr) 1000 2500 South 700 2500 East 900 3000 West 550 3000 Saturation Flow (PCU/hr) Total time lost per cycle is 12 seconds. The cycle length (seconds) as per Webster's approach isarrow_forwardAn intersection has a three-phase signal with the movements allowed in each phase and corresponding analysis and saturation flow rates shown in the table below. Assume the lost time is 4 seconds per phase and a critical intersection v/c of 0.90 is desired. Phase 2 3 Allowed movements NB L, SB L NB T/R, SB T/R EB L, WBL EB T/R, WB T/R Analysis flow rate 330, 365 veh/h 1125, 1075 veh/h 110, 80 veh/h 250, 285 veh/h Saturation flow rate 1700, 1750 veh/h 3400, 3300 veh/h 650, 600 veh/h 1750, 1800 veh/h Calculate minimum cycle length O 255 sec O 155 sec O 100 sec O 60 secarrow_forward
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