   Chapter 13, Problem 87AE

Chapter
Section
Textbook Problem

# Many sugars undergo a process called mutarotation, in which the sugar molecules interconvert between two isomeric forms, finally reaching an equilibrium between them. This is true for the simple sugar glucose, C6H12O6, which exists in solution in isomeric forms called alpha-glucose and beta-glucose. If a solution of glucose at a certain temperature is analyzed, and it is found that the concentration of alpha-glucose is twice the concentration of beta-glucose, what is the value of K for the interconversion reaction?

Interpretation Introduction

Interpretation: It is given that the sugars undergo a process called mutarotation, in which the sugar molecules interconvert between two isomeric forms, finally reaching equilibrium between them. The value of the equilibrium constant (K) for the given reaction, where the concentration of alpha-glucose is twice the concentration of beta-glucose, is to be calculated.

Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction.

When the equilibrium constant is expressed in terms of concentration, it is represented as K .

To determine: The equilibrium constant (K) for the given reaction.

Explanation

Explanation

The reaction that occurs is,

Alpha-glucoseBeta-glucose

Given

The concentration of alpha-glucose is twice the concentration of beta-glucose.

At equilibrium, the equilibrium ratio is expressed by the formula,

K=ConcentrationofproductConcentrationofreactant

Where,

• K is the equilibrium constant.

The equilibrium constant expression for the given reaction is,

K=[Beta-glucose][Alpha-glucose] (1)

The equilibrium constant (K) for the given reaction is 0

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