BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

Solutions

Chapter
Section
BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

For the following reaction at a certain temperature

H 2 ( g ) + F 2 ( g ) 2 HF ( g )

it is found that the equilibrium concentrations in a 5.00-L rigid container are [H2 = 0.0500 M, [F2] = 0.0100 M, and [HF] = 0.400 M. If 0.200 mole of F2 is added to this equilibrium mixture, calculate the concentrations of all gases once equilibrium is reestablished.

Interpretation Introduction

Interpretation: The equilibrium concentration of each species, volume of container and the reaction for the production of HF(g) is given. The concentration of all species of this reaction is to be calculated when given moles of Fe2 is added to this equilibrium mixture.

Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction.

For a reaction,

jA+kBlC+mD

The equilibrium constant is given by,

K=[C]l[D]m[A]j[B]k

To determine: The equilibrium concentration of [H2] , [F2] and [HF] when 0.200 moles of Fe2 is added to the given equilibrium reaction.

The equilibrium constant of the given reaction is 320_ .

Explanation

Explanation

Given

The given concentration of each species is,

[H2]=0.0500M[F2]=0.0100M[HF]=0.400M

The given reaction is,

H2(g)+F2(g)2HF(g)

Formula

The equilibrium constant for the given reaction is,

K=[HF]2[H2][F2]

Where,

  • K is the equilibrium constant.

Substitute the values of concentration of each species in the above expression.

K=[HF]2[H2][F2]=[0.400]2[0.0500][0.0100]=320_

The equilibrium concentration of [H2] is 0.025M_ .

Given

The volume of container is 5.00L .

As 0.200mole are added to the reaction mixture in container therefore, the concentration of [F2] increased by,

[F2]=0.200mole5L=0.04M

Now, the total concentration of F2 in the container is,

[F2]=(0.010+0.04)M=0.50M

It is assumed that the concentration of reactants changed by x .

Make the ICE table for the given reaction.

H2(g)F2(g)2HF(g)Initial(M):0.050.050.40Change(M):-x-x2xEquilibrium(M):0

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Chapter 13 Solutions

Show all chapter solutions add

Additional Science Solutions

Find more solutions based on key concepts

Show solutions add

Brown adipose tissue. develops during starvation is a well-known heat-generating tissue develops as fat cells d...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

What does the size of the star image in a photograph tell you?

Horizons: Exploring the Universe (MindTap Course List)

Determine the order of magnitude of the gravitational force that you exert on another person 2 m away. In your ...

Physics for Scientists and Engineers, Technology Update (No access codes included)