   Chapter 14, Problem 28Q

Chapter
Section
Textbook Problem

# Derive an expression for the relationship between pKa and pKb for a conjugate acid–base pair. (pK = − log K.)

Interpretation Introduction

Interpretation: The relation between pKa and pKb is to be derived for a conjugate acid-base pair.

Concept introduction: A pair of substance that is related to each other by donating and accepting of a single proton is known as conjugate acid-base pair.

Explanation

Explanation

To derive: The relation between pKa and pKb for a conjugate acid-base pair.

The relation between pKa and pKb is,

pKa+pKb=14

The relation between pKa and Ka is,

pKa=logKa (1)

Where,

• Ka is acid dissociation constant
• pKa is a measure of acidic strength.

The relation between pKb and Kb is,

pKb=logKb (2)

Where,

• Kb is base dissociation constant
• pKb is a measure of basic strength.

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