   Chapter 14, Problem 47E

Chapter
Section
Textbook Problem

# Values of Kw as a function of temperature are as follows: Temperature(°C) Kw 0 1.14 × 10−15 25 1.00 × 10−14 35 2.09 × 10−14 40. 2.92 × 10−14 50. 5.47 × 10−14 a. Is the autoionization of water exothermic or endothermic?b. Calculate [H+] and [OH−] in a neutral solution at 50.°C.

(a)

Interpretation Introduction

Interpretation: The values of Kw with respect to temperature are given. The classification of the autoionization of water into an exothermic or an endothermic reaction is to be done the [OH] and [H+] in a neutral solution at 50°C is to be calculated.

Concept introduction: The self-ionization of water is termed as autoionization. In this process, a water molecule undergoes dissociation to lead to a formation of a hydroxide (OH) ion.

The equilibrium constant for water is denoted by Kw and is expressed as,

Kw=[H+][OH]

At 25°C , [H+][OH]=1×1014

Explanation

Explanation

To determine: The classification of the autoionization of water into an exothermic or an endothermic reaction.

The autoionization of water is an endothermic reaction.

The reaction is,

2H2O(l)H3O+(aq)+O

(b)

Interpretation Introduction

Interpretation: The values of Kw with respect to temperature are given. The classification of the autoionization of water into an exothermic or an endothermic reaction is to be done the [OH] and [H+] in a neutral solution at 50°C is to be calculated.

Concept introduction: The self-ionization of water is termed as autoionization. In this process, a water molecule undergoes dissociation to lead to a formation of a hydroxide (OH) ion.

The equilibrium constant for water is denoted by Kw and is expressed as,

Kw=[H+][OH]

At 25°C , [H+][OH]=1×1014

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