Genetics: From Genes to Genomes, 5th edition
Genetics: From Genes to Genomes, 5th edition
5th Edition
ISBN: 9780073525310
Author: Leland H. Hartwell, Michael L. Goldberg, Janice A. Fischer, Leroy Hood, Charles F. Aquadro
Publisher: McGraw-Hill Education
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Chapter 21, Problem 10P
Summary Introduction

a.

To derive:

The formula to express the relationship in the given question.

Introduction:

It is given that two alleles at one locus express three distinct phenotypes. Two alleles of two genes give five distinct phenotypes. Two alleles of six genes produce 13 distinct phenotypes.

Summary Introduction

b.

To determine:

The number of genes that control kernel color in the given cross.

Introduction:

It is given that each of the most extreme phenotypes for a trait determined by two alleles at one locus is found in a proportion of 14 in the F2 generation. If two alleles of two genes determine the trait, each extreme phenotype will be present in the F2 as 116 of the population.

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Two alleles at one locus produce three distinctphenotypes. Two alleles of two genes lead tofive distinct phenotypes. Two alleles of six geneslead to 13 distinct phenotypes. (These statementsassume that the alleles at any one locus arecodominant or incompletely dominant andthat each gene makes an equal contributionto the phenotype.)a. Derive a formula to express this relationship. (Letn equal the number of genes.)b. Each of the most extreme phenotypes for a traitdetermined by two alleles at one locus are foundin a proportion of 1/4 in the F2 generation. If twoalleles of two genes determine the trait, each extreme phenotype will be present in the F2 as 1/16of the population.In common wheat (Triticum aestivum),kernel color varies from red to white andthe genes controlling the color act additively,that is, alleles for each gene are incompletelydominant and each gene contributes equallyto the color. A true-breeding red variety iscrossed to a true-breeding white variety, and1/256 of the F2…
A test cross between a plant of genotype PpSs and the tester white plant with wrinkled seed coat (ppss) gives the following numbers of progeny in four phenotypic types. 14:87:83:16 (purple flower + smooth seed coat: purple flower + wrinkled seed coat: white flower + smooth seed coat: white flower + wrinkled seed coat). a.  What is the expected ratio of progeny phenotypes assuming independent assortment of alleles?   b.  Explain how ratios of progeny show that the two genes are linked.    c.  How many map units separate the purple and smooth genes? Show your calculations.    d.  What is the “parental” genotype of the heterozygous parent? (i.e. Which alleles of the P and S loci are present on each of the two chromosomes of the doubly heterozygous parent of this test cross?)
A is dominant over a and B is dominant over b. Genes A/a and B/b assort independently. The parental cross (P) is between true- breeding (homozygous) strains (AA bb x aa BB). The resulting F1 offspring would be [Select ] A F1 x F1 cross gives the F2 generation. The ratio of phenotypes in the F2 generation can be described as [ Select ] In the phenotypic ratio, what number refers to individuals that are: dominant for both traits? [ Select ] recessive for both traits? [Select ] To what phenotypes do the "3"s in the ratio refer? [ Select ] > >
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