Chapter 27, Problem 34E

Interpretation Introduction

(a)

Interpretation:

To draw the product formed when 1-ethylcyclohex-1-ene reacts with HI.

Concept introduction:

The reaction of hydrogen halide like HCl, HBr with an alkene or alkyne results formation of alkane. The hydrogen (H) atom of hydrogen halide bonded to that carbon of double bond or triple bond which has highest number of hydrogen atoms.

Interpretation Introduction

(b)

Interpretation:

To draw the product formed when 1-ethylcyclohex-1-ene reacts with ${\text{H}}_{\text{2}}$ in presence of platinum catalyst.

Concept introduction:

The process hydrogenation is the addition of hydrogen to a double bonded compound in presence of catalyst like Nickel, Platinum etc. The product of this reaction is a saturated compound that is, no single bond present. Therefore, ${\text{H}}_{\text{2}}$ /Pt can be used as reducing agent.

Interpretation Introduction

(c)

Interpretation:

To draw the product formed when 1-ethylcyclohex-1-ene reacts with ${\text{H}}_{\text{2}}\text{O}$ in presence of ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$.

Concept introduction:

The reaction of alkene with water in presence of acid gives alcohol. First step in the reaction is protonation and formation of carbocation, Second step is addition of nucelophile (water) to the carbocation and then alcohol forms and regeneration of catalyst takes place.

Interpretation Introduction

(d)

Interpretation:

To draw the product formed when 1-ethylcyclohex-1-ene reacts with ${\text{Br}}_{\text{2}}{\text{/CCl}}_{\text{4}}$.

Concept introduction:

Reaction of alkene with dihalide gives alkyl halide. Anti addition is the reaction in which the substituents are added from the opposite faces of double bond.