   Chapter 29, Problem 16PE

Chapter
Section
Textbook Problem

A laser with a power output of 2.00 mW at a wavelength of 400 nm is projected onto calcium metal. (a) How many electrons per second are ejected? (b) What power is carried away by the electrons, given that the binding energy is 2.71 eV?

To determine

(a)

The number of electrons ejected per second.

Explanation

Given:

Wavelength of radiation =λ=400 nm = 400×109 m

Number of photons per sec = number of electrons ejected per sec =n

Power of the laser =P=2 mW = 2 ×103 W

Plank's constant =h=6.63×1034 Js

Speed of photon =c=3×108 ms

Formula Used:

Power of laser is given as

P=nhcλ

Calculation:

Power of laser is given as

(b)

To determine

Power carried away by the electrons.

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