College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000



College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000
Textbook Problem

Photoelectrons from a material with a binding energy of 2.71 eV are ejected by 420-nm photons. Once ejected, how long does it take these electrons to travel 2.50 cm to a detection device?

To determine

The time taken by the electrons to reach the detection device.



Wavelength of radiation =λ=420 nm = 420×109 m

Speed of radiation =c=3×108 ms

Mass of electron =m=9.1×1031 kg

Distance traveled to reach the device =d=2.50 cm = 0.025 m

Time taken by electron to reach the device =t

Maximum velocity of ejected electron =vmax

Energy of the radiation =E=?

Binding Energy of electrons =Wo=2.71 eV

Plank's constant =h=4.14×1015 eV s

Kinetic energy of the electrons =KEmax

Formula Used:

Energy of radiation is given as


Kinetic energy of the ejected electron is given as


Kinetic energy is given as


Time taken by the electron is given as



Energy of radiation is given as


Inserting the values

  E=(4.14×1015 )(3×108)(420×109)E=2

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