   Chapter 29, Problem 17PE

Chapter
Section
Textbook Problem

(a) Calculate the number of photoelectrons per second ejected from a 1.00-mm2 area of sodium metal by 500-nm M radiation having an intensity of 1.30 kW/m2 (the intensity of sunlight above the Earth's atmosphere). (b) Given that the binding energy is 2.28 eV, what power is carried away by the electrons? (c) The electrons carry away less power than brought in by the photons. Where does the other power go? How can it be recovered?

To determine

(a)

The number of photoelectrons ejected per second.

Explanation

Given:

Wavelength of radiation =λ=500 nm = 500×109 m

Number of photons per sec = number of electrons ejected per sec =n

Intensity of radiation =I=1.30 kWm2 = 1300 Wm2

Area =A=1 mm2 = 1×106 m2                          (since 1 mm2=106 m2 )

Power of the radiation =P

Plank's constant =h=6.63×1034 Js

Speed of photon =c=3×108 ms

Formula Used:

(b)

To determine

Power carried away by the electrons.

(c)

To determine

Where does the other power go and how can it be recovered.

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