The equilibrium constant of the given reaction: Glucose − 1 − phosphate → Glucose − 6 − phosphate , Δ G ° = − 7.2 kJ / mol Introduction: The basis for free energy calculation is provided by the standard state. Standard free energy is defined for the reactions taking place at 298 K (Kelvin), 1 atm (atmospheric pressure), and all the solutes at a concentration of 1.0 M (molar).

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Chapter 4, Problem 19RQ

Summary Introduction

To review:

The equilibrium constant of the given reaction:

Glucose−1−phosphate→ Glucose−6−phosphate, ΔG°=−7.2 kJ/mol

Introduction:

The basis for free energy calculation is provided by the standard state. Standard free energy is defined for the reactions taking place at 298 K (Kelvin), 1 atm (atmospheric pressure), and all the solutes at a concentration of 1.0 M (molar).

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