   Chapter 5.2, Problem 5CP ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Checkpoint 5 Worked-out solution available at LarsonAppliedCalculus.comFind ∫ 5 x x 2   −   1   d x .

To determine

To calculate: The value of the provided indefinite integral 5xx21dx.

Explanation

Given Information:

The provided indefinite integral is 5xx21dx.

Formula Used:

According to the general power rule for integration,

If u is a differentiable function of x, then

undu=un+1n+1+C,

where n1

Calculation:

Consider the indefinite integral say I,

I=5xx21dx

Multiply and divide by 2 in the right-hand side of above integral

I=(12)5xx21(2)dx

Take the factor 52 out of the integrand

I=52xx21(2)dx

Or

I=52x21(2x)dx

Let

x21=u … (1)

Differentiate the above equation with respect to x

ddx(x21)=

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