Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
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Chapter 7, Problem 37P
The pathway for arginine biosynthesis in Neurospora crassa involves several enzymes that produce a series of intermediates.
| a. | If you did a cross between ARG-E and ARG-H Neurospora strains, what would be the distribution of Arg+ and Arg- spores within parental ditype and nonparental ditype asci? Give the spore types in the order in which they would appear in the ascus. |
| b. | For each of the spores in your answer to part (a), what nutrients could you supply in the media to get spore growth? |
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Students have asked these similar questions
The Neurospora octad shown came from a
cross between mt and m' strains.
a. Is this an MI or an MIl octad or neither?
Explain.
b. Diagram the production of this octad.
c. Is it possible to observe evidence of
heteroduplex formation in a Neurospora
ascus even if gene conversion did not occur
during formation of the octad? Explain.
Neurospora of genotype a + c are crossed withNeurospora of genotype + b +. (Here, + is shorthandfor the wild-type allele.) The following tetrads areobtained (note that the genotype of the four sporepairs in an ascus are listed, rather than listing alleight spores):a + c a b c + + c + b c a b + a + ca + c a b c a + c a b c a b + a b c+ b + + + + + b + + + + + + c + + ++ b + + + + a b + a + + + + c + b +137 141 26 25 2 3a. In how many cells has meiosis occurred to yieldthese data?b. Give the best genetic map to explain these results.Indicate all relevant genetic distances, both betweengenes and between each gene and the centromere.c. Diagram a meiosis that could give rise to oneof the three tetrads in the class at the far right inthe list
Consider a maize plant: Genotype C/cm ; Ac/Ac+ where cm is an unstable colorless allele caused by Ds insertion. What phenotypic ratios would be produced and in what proportions when this plant is crossed with a mutant c/c Ac+/Ac+? Assume that the Ac and c loci are unlinked, that the chromosome-breakage frequency is negligible, and the C allele encodes pigment production.
Chapter 7 Solutions
Genetics: From Genes to Genomes
Ch. 7 - The following is a list of mutational changes. For...Ch. 7 - What explanations can account for the following...Ch. 7 - The DNA sequence of one strand of a gene from...Ch. 7 - Among mammals, measurements of the rate of...Ch. 7 - Over a period of several years, a large hospital...Ch. 7 - Suppose you wanted to study genes controlling the...Ch. 7 - In a genetics lab, Kim and Maria infected a sample...Ch. 7 - The results of the fluctuation test Fig. 7.5 were...Ch. 7 - The following pedigree shows the inheritance of a...Ch. 7 - Autism is a neurological disorder thought to be...
Ch. 7 - Like the yellow Labrador retrievers featured in...Ch. 7 - Remember that Balancer chromosomes prevent the...Ch. 7 - Figure 7.14 shows examples of base substitutions...Ch. 7 - Figure 7.14a shows the mutagen 5-bromouracil 5-BU,...Ch. 7 - So-called two-way mutagens can induce both a...Ch. 7 - In 1967, J. B. Jenkins treated wild-type male...Ch. 7 - When a particular mutagen identified by the Ames...Ch. 7 - Prob. 18PCh. 7 - The Ames test uses the reversion rate His- to His...Ch. 7 - The mutant FMR-1 allele that causes fragile X...Ch. 7 - The physicist Stephen Hawking, famous for his...Ch. 7 - Aflatoxin B1 is a highly mutagenic and...Ch. 7 - In human DNA, 70 of cytosine residues that are...Ch. 7 - Bromodeoxyuridine BrdU is a synthetic nucleoside...Ch. 7 - Albinism in animals is caused by recessive...Ch. 7 - a. In Figure 7.22b, what can you say about the...Ch. 7 - Imagine that you caught a female albino mouse in...Ch. 7 - Plant breeders studying genes influencing leaf...Ch. 7 - In humans, albinism is normally inherited in an...Ch. 7 - a. Seymour Benzers fine structure analysis of the...Ch. 7 - a. You have a test tube containing 5 ml of a...Ch. 7 - Prob. 32PCh. 7 - The rosy ry gene of Drosophila encodes an enzyme...Ch. 7 - Nine rII- mutants of bacteriophage T4 were used in...Ch. 7 - In a haploid yeast strain, eight recessive...Ch. 7 - In Problem 24, you learned that Bloom syndrome is...Ch. 7 - The pathway for arginine biosynthesis in...Ch. 7 - In corn snakes, the wild-type color is brown. One...Ch. 7 - In a certain species of flowering plants with a...Ch. 7 - The intermediates A, B, C, D, E, and F all occur...Ch. 7 - In each of the following cross schemes, two...Ch. 7 - Prob. 42PCh. 7 - The following complementing E. coli mutants were...Ch. 7 - In 1952, an article in the British Medical Journal...Ch. 7 - Mutations in an autosomal gene in humans cause a...Ch. 7 - Antibodies were made that recognize six proteins...Ch. 7 - Prob. 47PCh. 7 - Prob. 48PCh. 7 - In addition to the predominant adult hemoglobin,...Ch. 7 - Most mammals, including New World primates such as...Ch. 7 - Humans are normally trichromats; we have three...
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- The synthesis of flower pigments is known to be dependent on enzymatically controlled biosynthetic pathways. For the crosses shown here, postulate the role of mutant genes and their products in producing the observed phenotypes: (a) P1: white strain A * white strain B F1: all purple F2: 9/16 purple: 7/16 white (b) P1: white * pink F1: all purple F2: 9/16 purple: 3/16 pink: 4/16 whitearrow_forwardConsider two maize plants:a. Genotype C/c m ; Ac/Ac+, where cm is an unstable allele caused by a Ds insertionb. Genotype C/c m, where cm is an unstable allele caused by Ac insertionWhat phenotypes would be produced and in what proportions when (1) each plant is crossed with a basepair-substitution mutant c/c and (2) the plant in part a is crossed with the plant in part b? Assume that Ac and c are unlinked, that the chromosome-breakage frequency is negligible, and that mutant c /C is Ac+.arrow_forwardIn sweet peas, the given enzymatic pathway result to pigment formation in the flowers: A dihybrid plant is crossed to a white one which is heterozygous at the “C” locus (provided in the image). What is the genotype of the dihybrid plant? What is the genotype of the white plant? What kinds of flowers, colored or white, are to be expected from the cross above? Include the ratio.arrow_forward
- From a cross between e+ f+ g+ and e− f − g− strains ofNeurospora, recombination between these linkedgenes resulted in a few octads containing the followingordered set of spores:e+ f+ g+e+ f+ g+e+ f − g+e+ f − g+e− f − g−e− f − g−e− f − g−e− f − g−a. Where was recombination initiated?b. Did crossing-over occur between genes e and g?Explain.c. Why do you end up with 2 f+ : 6 f − but 4 e+: 4 e−and 4g+: 4g−?d. Could you characterize these unusual octads as MIor MII for any of the three genes involved?Explain.arrow_forwardWild-type strains of the haploid fungus Neurospora canmake their own tryptophan. An abnormal allele td renders the fungus incapable of making its own tryptophan.An individual of genotype td grows only when its medium supplies tryptophan. The allele su assorts independently of td; its only known effect is to suppress the tdphenotype. Therefore, strains carrying both td and su donot require tryptophan for growth.a. If a td ; su strain is crossed with a genotypically wildtype strain, what genotypes are expected in the progenyand in what proportions?b. What will be the ratio of tryptophan-dependent totryptophan-independent progeny in the cross of part a?arrow_forwardConsidering Figure 2-13, if you had a homozygous double mutant m3/m3 m5/m5, would you expect it to be mutant in phenotype? (Note: This line would have two mutant sites in the same coding sequence.)arrow_forward
- The diploid that resulted from mating these two haploids would have which of the following auxotrophies? Select all that apply.Strain 1: MATa ura3-52 met15Δ0 leu2Δ0 Strain 2: MATalpha ura3-52 met15Δ0 trp1Δ63 a.) histidine b.) tryptophan c.) uracil d.) lysine e.) leucine f.) methioninearrow_forwardWe have chosen a human Rab protein with no direct yeast equivalent as an “outgroup” for this study. Explain why have we chosen a human Rab protein with no direct yeast equivalent as an “outgroup” for this study?arrow_forwardConsider the first category of test-cross offspring shown in figure 8.2 (+b, LS). Consider also that the parents of the heterozygous female flies in the test cross had the following genotypes: bb, SS, and +, LL. A. What would be the physical phenotype of these flies? B. If PC was conducted with the DNA of one of these flies using the primers for the molecular marker, what would be the appearance of the bands on an electrophoresis gel with the PC products? C. If the gene for black body and the locus for the molecular marker (L long or S short) were unlinked, what proportion of the test-cross progeny would be black flies that are heterozygous for the molecular marker? What proportion would be flies with normal body color, which are homozygous for one form of the molecular marker? D. If the gene for black body and the locus for the molecular marker were linked, how would the proportion of flies be different?arrow_forward
- After irradiating wild-type cells of Neurospora (a haploid fungus), a geneticist finds two leucine-requiringauxotrophic mutants. He combines the two mutants ina heterokaryon and discovers that the heterokaryon isprototrophic.a. Were the mutations in the two auxotrophs in the samegene in the pathway for synthesizing leucine or in twodifferent genes in that pathway? Explain.b. Write the genotype of the two strains according toyour model.c. What progeny and in what proportions would youpredict from crossing the two auxotrophic mutants?(Assume independent assortment.)arrow_forwardIn this gene order question, would the order be a/b -- kf -- nm since genes with shorter map unit distances are closely linked?arrow_forwardTo understand the genetic basis of locomotion in the diploid nematode Caenorhabditis elegans, recessive mutations were obtained, all making the worm “wiggle” ineffectually instead of moving with its usual smooth gliding motion. These mutations presumably affect the nervous or muscle systems. Twelve homozygous mutants were intercrossed, and the F1 hybrids were examined to see if they wiggled. The results were as follows, where a plus sign means that the F1 hybrid was wild type (gliding) and “w” means that the hybrid wiggled.a. Explain what this experiment was designed to test. b. Use this reasoning to assign genotypes to all 12 mutants. c. Explain why the phenotype of the F1 hybrids between mutants 1 and 2 differed from that of the hybrids between mutants 1 and 5arrow_forward
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