(a)
Interpretation:
The curved arrow notation for the elimination of
Concept introduction:
Curved arrows are used to represent the movement of electrons in a reaction mechanism. The arrow starts on an electron-rich atom or an electron-rich region such as a pi bond. It ends on an electron poor atom when the movement results in the formation of a new sigma bond. If the result is the formation of a pi bond, the arrow ends in the region between the two atoms that form the bond.
A carbocation is a positively charged carbon atom that is electron-poor, two electrons short of an octet. A nearby bond or a lone pair on a nearby atom acts as an electron-rich region and can transfer the pair of electrons to the electron-poor atom. This can result in the formation of a more stable neutral species, accompanied by the loss of an electrophile. The electrophile may be a proton or another cationic species and is extracted by any base that may be present.
(b)
Interpretation:
The curved arrow notation for the elimination of
Concept introduction:
Curved arrows are used to represent the movement of electrons in a reaction mechanism. The arrow starts on an electron-rich atom or an electron-rich region such as a pi bond. It ends on an electron poor atom when the movement results in the formation of a new sigma bond. If the result is the formation of a pi bond, the arrow ends in the region between the two atoms that form the bond.
A carbocation is a positively charged carbon atom that is electron-poor, two electrons short of an octet. A nearby bond or a lone pair on a nearby atom acts as an electron-rich region and can transfer the pair of electrons to the electron-poor atom. This can result in the formation of a more stable neutral species, accompanied by the loss of an electrophile. The electrophile may be a proton or another cationic species and is extracted by any base that may be present.
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Chapter 7 Solutions
ORGANIC CHEMISTRY SMARTWORK5 - ACCESS
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- Draw out the structure of product (s). If no reaction, write No Reactionarrow_forwardFollow the curved arrows and draw the hydrocarbon product of the following reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts.arrow_forwardConsider the following reactants: CI H₂O Would substitution take place at a significant rate between these reactants? Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. If you said substitution would take place, draw all the major products in the upper drawing area below. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. If you said substitution would take place, also draw the complete mechanism for one of the major products in the lower drawing area below. If there is more than one major product, you may draw the mechanism for the production of any one of them. Note: be sure you show all the steps in your mechanism. A good check is to make sure the final product of your mechanism is a stable molecule that could be isolated and purified. Oyes Ono 금 Ararrow_forward
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