(a)
Interpretation:
For each step of the given unimolecular elimination
Concept introduction:
An atom with partial or full negative charge is called an electron-rich site whereas an atom with partial or full positive charge is called an electron-poor site. An electron-rich atom has a lone pair of electrons whereas an electron-poor atom lacks an octet. In an elementary step, electrons tend to flow from an electron-rich site to an electron-poor site.
(b)
Interpretation:
Appropriate curved arrows are to be drawn to show the bond formation and bond breaking that occur in each step of the given unimolecular elimination
Concept introduction:
In an elementary step, electrons tend to flow from an electron-rich site to an electron-poor site. In the first step of unimolecular elimination
(c)
Interpretation:
Each step of the given unimolecular elimination
Concept introduction:
An elementary step in which a proton is transferred from an electron-poor site to an electron-rich site and one bond is broken and another is formed simultaneously is called the proton transfer step. An elementary step in which only single bond is broken is called the heterolysis step.
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ORGANIC CHEMISTRY SMARTWORK5 - ACCESS
- The following reaction, which is discussed in Chapter 21, consists of the three elementary steps shown. For each step (i-iii), (a) identify all electron-rich sites and all electron-poor sites, (b) draw in the appropriate curved arrows to show the bond formation and bond breaking that occur, and (c) name the elementary step. (i) Br Br Br P HO. Br + BrO Br (ii) Br Br Br Br + BrO Br (ii) Br Br НО. Br Br Br Brarrow_forwardThere are three potential termination steps in this mechanism. Confused on how to write two of them, using fishhook arrows to show how the electrons move. And how to have a valid termination step involves the combination of any two radicals involved in the propagation part of the reaction mechanism.arrow_forwardStudy the following reaction energy diagram: products energy reactants Then answer the following questions about the chemical reaction. release ahsorh nhrorharrow_forward
- Although you may not have seen the reaction highlighted in green before, it uses similar chemical concepts you have seen in other reaction mechanisms. Draw the mechanism.arrow_forwardIn an SN2 mechanism, how does it work, what are all of the steps, transition state and all final products?arrow_forwardPredict the relative rates of these reactions. That is, select 1 next to the reaction with the fastest rate, 2 next to the reaction with the next fastest rate, and so on. Note for advanced students: you may assume these reactions all take place in a polar aprotic solvent, like DMSO. ( Choose one) Predict the relative rates of these reactions. That is, select 1 next to the reaction with the fastest rate, 2 next to the reaction with the next fastest rate, and so on. Note for advanced students: you may assume these reactions all take place in a polar aprotic solvent, like DMSO. u + H₂O Reaction - OH₂ Relative Rate (Choose one) OH₂ (Choose one) ▼ +CI ... + H₂O OH + OH + I (Choose one) (Choose one) ▼ + H₂S + CIarrow_forward
- The following reaction, which is discussed in Chapter 8, is an example of a unimolecular nucleophilic substitution (Sn1) reaction. It consists of the four elementary steps shown here. For each step (i-iv), (a) identify all electron-rich sites and all electron-poor sites, (b) draw in the appropriate curved arrows to show the bond formation and bond breaking that occur, and (c) name the elementary step. (i) H-OCH3 OH + H-OCH3 H. H (ii) ©CH2 + H,O (iii) ©CH2 CH3 + HO-CH3 (iv) CH3 CH3 + H2O-CH, + НО—СНЗ foarrow_forwardYour answer is incorrect. Predict the relative rates of these reactions. That is, select 1 next to the reaction with the fastest rate, 2 next to the reaction with the next fastest rate, and so on. Note for advanced students: you may assume these reactions all take place in a polar aprotic solvent, like DMSO. Incorrect Your answer is incorrect. Predict the relative rates of these reactions. That is, select I next to the reaction with the fastest rate, 2 next to the reaction with the next fastest rate, and so on. Note for advanced students: you may assume these reactions all take place in a polar aprotic solvent, like DMSO. Reaction Relative Rate G + H₂O - OH₂ 2 Br + H₂S - + Br 3 + H₂S SHI + ci I (fastest) Br + H₂O OM₂ + Br 4 (slowest)arrow_forwardDraw the mechanism for the equilibrium illustrated below. What is the process called? Is the Keq >1, <1, =1 for this reaction as illustrated. Is the equilibrium direction dictated by thermodynamics or kinetics? Explain your rationale in detail.arrow_forward
- Sketch the reaction mechanism (including the final product) corresponding to the following description of; 2-bromo-4-methylpentane is being reacted with sodium cyanide in diethyl ether (set up the reaction – next you will get a description of the mechanism to draw). A lone pair of electrons from the cyanide attacks the carbon bonded to bromine, forming a new carbon-carbon bond. At the same time, the carbon-bromine bond breaks with the electron pair from the carbon-bromine bond moving toward the bromine to form a bromide ion. This will form the product 2,4-dimethylpentanenitrile and sodium bromide.arrow_forwardWhere do the arrows for this are suppose to go? (Intermediate) Reactant Mechanism Explorer: Sketch and Submission (Intermediate) Reactant Tip: Only add curved arrows in this sketcher Mechanism Explorer: Sketch and Submission (Intermediate) Reactant CH H H₂O Tip: Only add curved arrows in this sketcher learrow_forward(e) On the incomplete reaction energy diagram below, draw a curve that shows the following two details. The relative activation energies of the two elementary steps The enthalpy change of the overall reactionarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning