Living By Chemistry: First Edition Textbook
Living By Chemistry: First Edition Textbook
1st Edition
ISBN: 9781559539418
Author: Angelica Stacy
Publisher: MAC HIGHER
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Chapter U2, Problem SII2RE

(a)

Interpretation Introduction

Interpretation :

Shape of ammonia molecule must be predicted.

Concept Introduction :

Shape of a molecule is determined by the total number of electron pairs in the valence shell of the central atom.

Ammonia molecule has total 4 atoms in which N is the central atom.

(a)

Expert Solution
Check Mark

Answer to Problem SII2RE

Shape of ammonia molecule is trigonal pyramidal.

Explanation of Solution

The structure of ammonia molecule is represented as follows:

Living By Chemistry: First Edition Textbook, Chapter U2, Problem SII2RE , additional homework tip  1

N has total 4 pairs of electrons in the valence shell.

There are three bond pairs and lone pairs of electrons. N atom is sp3 hybridized and thus NH3 has trigonal pyramidal shape due to presence of one lone pair electrons.

b)

Interpretation Introduction

Interpretation :

Shape of silicon tetrachloride must be predicted.

Concept Introduction :

Shape of a molecule is determined by the total number of electron pairs in the valence shell of the central atom.

Silicon tetrachloride molecule has total 5 atoms in which Si is the central atom.

b)

Expert Solution
Check Mark

Answer to Problem SII2RE

Shape of silicon tetrachloride molecule is tetrahedral.

Explanation of Solution

The structure is represented as follows:

Living By Chemistry: First Edition Textbook, Chapter U2, Problem SII2RE , additional homework tip  2

Si has total 4 pairs of electrons in the valence shell.

There are four bond pairs and no lone pairs of electrons. Si atom is sp3 hybridized and thus SiCl4 has tetrahedral shape.

c)

Interpretation Introduction

Interpretation :

Shape of hydrogen sulfide must be predicted.

Concept Introduction :

Shape of a molecule is determined by the total number of electron pairs in the valence shell of the central atom.

Hydrogen sulfide molecule has total 3 atoms in which S is the central atom.

c)

Expert Solution
Check Mark

Answer to Problem SII2RE

Shape of hydrogen molecule is angular.

Explanation of Solution

The structure of H2S is represented as follows:

Living By Chemistry: First Edition Textbook, Chapter U2, Problem SII2RE , additional homework tip  3

S has total 4 pairs of electrons in the valence shell.

There are two bond pairs and two lone pairs of electrons. S atom is sp3 hybridized and thus H2S has angular shape.

d)

Interpretation Introduction

Interpretation :

Shape of hydrogen cyanide must be predicted.

Concept Introduction :

Shape of a molecule is determined by the total number of electron pairs in the valence shell of the central atom.

Hydrogen cyanide molecule has total 3 atoms in which C is the central atom.

d)

Expert Solution
Check Mark

Answer to Problem SII2RE

Shape of hydrogen cyanide is linear.

Explanation of Solution

The structure is represented as follows:

Living By Chemistry: First Edition Textbook, Chapter U2, Problem SII2RE , additional homework tip  4

C has total 4 pairs of electrons in the valence shell.

There are four bond pairs and no lone pairs of electrons. C atom is triple bonded with N and carbon is sp hybridized and thus HCN has linear shape.

e)

Interpretation Introduction

Interpretation :

Shape of formaldehyde must be predicted.

Concept Introduction :

Shape of a molecule is determined by the total number of electron pairs in the valence shell of the central atom.

Formaldehyde molecule has total 4 atoms in which C is the central atom.

e)

Expert Solution
Check Mark

Answer to Problem SII2RE

Shape of formaldehyde is trigonal planar.

Explanation of Solution

The structure of formaldehyde is represented as follows:

Living By Chemistry: First Edition Textbook, Chapter U2, Problem SII2RE , additional homework tip  5

C has total 4 pairs of electrons in the valence shell.

There are four bond pairs and no lone pairs of electrons. C atom is double bonded with O and single bonded with two hydrogen atoms. Carbon is sp2 hybridized and thus CH2N has trigonal planar shape.

Chapter U2 Solutions

Living By Chemistry: First Edition Textbook

Ch. U2.2 - Prob. 3ECh. U2.2 - Prob. 4ECh. U2.2 - Prob. 5ECh. U2.2 - Prob. 6ECh. U2.2 - Prob. 7ECh. U2.3 - Prob. 1TAICh. U2.3 - Prob. 1ECh. U2.3 - Prob. 2ECh. U2.3 - Prob. 3ECh. U2.3 - Prob. 4ECh. U2.3 - Prob. 5ECh. U2.4 - Prob. 1TAICh. U2.4 - Prob. 1ECh. U2.4 - Prob. 2ECh. U2.4 - Prob. 3ECh. U2.4 - Prob. 4ECh. U2.4 - Prob. 5ECh. U2.4 - Prob. 6ECh. U2.4 - Prob. 7ECh. U2.4 - Prob. 8ECh. U2.5 - Prob. 1TAICh. U2.5 - Prob. 1ECh. U2.5 - Prob. 2ECh. U2.5 - Prob. 3ECh. U2.5 - Prob. 4ECh. U2.5 - Prob. 5ECh. U2.5 - Prob. 6ECh. U2.5 - Prob. 7ECh. U2.5 - Prob. 8ECh. U2.5 - Prob. 9ECh. U2.6 - Prob. 1TAICh. U2.6 - Prob. 1ECh. U2.6 - Prob. 2ECh. U2.6 - Prob. 3ECh. U2.6 - Prob. 4ECh. U2.6 - Prob. 5ECh. U2.6 - Prob. 6ECh. U2.6 - Prob. 7ECh. U2.6 - Prob. 8ECh. U2.6 - Prob. 9ECh. U2.6 - Prob. 10ECh. U2.6 - Prob. 11ECh. U2.7 - Prob. 1TAICh. U2.7 - Prob. 1ECh. U2.7 - Prob. 2ECh. U2.7 - Prob. 3ECh. U2.7 - Prob. 4ECh. U2.7 - Prob. 5ECh. U2.8 - Prob. 1TAICh. U2.8 - Prob. 1ECh. U2.8 - Prob. 2ECh. U2.8 - Prob. 3ECh. U2.8 - Prob. 4ECh. U2.8 - Prob. 5ECh. U2.8 - Prob. 6ECh. U2.9 - Prob. 1TAICh. U2.9 - Prob. 1ECh. U2.9 - Prob. 2ECh. U2.9 - Prob. 3ECh. U2.9 - Prob. 4ECh. U2.9 - Prob. 5ECh. U2.9 - Prob. 6ECh. U2.9 - Prob. 7ECh. U2.10 - Prob. 1TAICh. U2.10 - Prob. 1ECh. U2.10 - Prob. 2ECh. U2.10 - Prob. 3ECh. U2.10 - Prob. 4ECh. U2.10 - Prob. 5ECh. U2.10 - Prob. 6ECh. U2.10 - Prob. 7ECh. U2.10 - Prob. 8ECh. U2.10 - Prob. 9ECh. U2.11 - Prob. 1TAICh. U2.11 - Prob. 1ECh. U2.11 - Prob. 2ECh. U2.11 - Prob. 3ECh. U2.11 - Prob. 4ECh. U2.11 - Prob. 5ECh. U2.11 - Prob. 6ECh. U2.11 - Prob. 7ECh. U2.12 - Prob. 1TAICh. U2.12 - Prob. 1ECh. U2.12 - Prob. 2ECh. U2.12 - Prob. 3ECh. U2.12 - Prob. 4ECh. U2.12 - Prob. 5ECh. U2.12 - Prob. 6ECh. U2.12 - Prob. 7ECh. U2.13 - Prob. 1TAICh. U2.13 - Prob. 1ECh. U2.13 - Prob. 2ECh. U2.13 - Prob. 3ECh. U2.13 - Prob. 4ECh. U2.13 - Prob. 5ECh. U2.14 - Prob. 1TAICh. U2.14 - Prob. 1ECh. U2.14 - Prob. 2ECh. U2.14 - Prob. 3ECh. U2.14 - Prob. 4ECh. U2.14 - Prob. 5ECh. U2.14 - Prob. 6ECh. U2.14 - Prob. 7ECh. U2.14 - Prob. 8ECh. U2.15 - Prob. 1TAICh. U2.15 - Prob. 1ECh. U2.15 - Prob. 2ECh. U2.15 - Prob. 4ECh. U2.15 - Prob. 5ECh. U2.15 - Prob. 6ECh. U2.16 - Prob. 1TAICh. U2.16 - Prob. 1ECh. U2.16 - Prob. 2ECh. U2.16 - Prob. 3ECh. U2.16 - Prob. 4ECh. U2.16 - Prob. 6ECh. U2.16 - Prob. 7ECh. U2.17 - Prob. 1TAICh. U2.17 - Prob. 1ECh. U2.17 - Prob. 2ECh. U2.17 - Prob. 3ECh. U2.17 - Prob. 4ECh. U2.17 - Prob. 5ECh. U2.17 - Prob. 6ECh. U2.17 - Prob. 7ECh. U2.17 - Prob. 8ECh. U2.17 - Prob. 9ECh. U2.18 - Prob. 1TAICh. U2.18 - Prob. 1ECh. U2.18 - Prob. 2ECh. U2.18 - Prob. 3ECh. U2.18 - Prob. 4ECh. U2.18 - Prob. 5ECh. U2.18 - Prob. 6ECh. U2.18 - Prob. 7ECh. U2.19 - Prob. 1TAICh. U2.19 - Prob. 1ECh. U2.19 - Prob. 2ECh. U2.19 - Prob. 3ECh. U2.19 - Prob. 4ECh. U2.19 - Prob. 5ECh. U2.19 - Prob. 6ECh. U2.19 - Prob. 7ECh. U2.19 - Prob. 8ECh. U2.19 - Prob. 9ECh. U2.20 - Prob. 1TAICh. U2.20 - Prob. 1ECh. U2.20 - Prob. 2ECh. U2.20 - Prob. 3ECh. U2.20 - Prob. 4ECh. U2.20 - Prob. 5ECh. U2.20 - Prob. 6ECh. U2.20 - Prob. 7ECh. U2.20 - Prob. 8ECh. U2.20 - Prob. 9ECh. U2.21 - Prob. 1TAICh. U2.21 - Prob. 1ECh. U2.21 - Prob. 2ECh. U2.21 - Prob. 3ECh. U2.21 - Prob. 4ECh. U2.21 - Prob. 6ECh. U2 - Prob. SI1RECh. U2 - Prob. SI2RECh. U2 - Prob. SI3RECh. U2 - Prob. SI4RECh. U2 - Prob. SI5RECh. U2 - Prob. SII1RECh. U2 - Prob. SII2RECh. U2 - Prob. SII3RECh. U2 - Prob. SII4RECh. U2 - Prob. SII5RECh. U2 - Prob. SIII1RECh. U2 - Prob. SIII2RECh. U2 - Prob. SIII3RECh. U2 - Prob. SIII4RECh. U2 - Prob. SIII5RECh. U2 - Prob. SIII6RECh. U2 - Prob. SIV1ECh. U2 - Prob. SIV2ECh. U2 - Prob. SIV3ECh. U2 - Prob. SIV4ECh. U2 - Prob. SIV5ECh. U2 - Prob. 1RECh. U2 - Prob. 2RECh. U2 - Prob. 3RECh. U2 - Prob. 4RECh. U2 - Prob. 5RECh. U2 - Prob. 6RECh. U2 - Prob. 7RECh. U2 - Prob. 8RE
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