Living By Chemistry: First Edition Textbook
Living By Chemistry: First Edition Textbook
1st Edition
ISBN: 9781559539418
Author: Angelica Stacy
Publisher: MAC HIGHER
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Chapter U2.2, Problem 7E
Interpretation Introduction

(a)

Interpretation:

The isomer of given compound needs to be drawn.

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  1

Concept introduction:

Isomers can be defined as the organic molecules which have the same molecular formula and different structural formula.

Due to different structural formula, isomers have different physical and chemical properties.

Expert Solution
Check Mark

Answer to Problem 7E

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  2

Explanation of Solution

The formula of the given compound is CH3CH2COOH (propanoic acid). Propanoic acid is a carboxylic acid with two carbon atoms and a −COOH as a functional group. The functional isomer of propanoic acid will be methyl ethanoate which is an ester with general chemical formula as RCOOR.

The structure is represented as follows:

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  3

Interpretation Introduction

(b)

Interpretation:

The isomer of a given compound needs to be determined.

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  4

Concept introduction:

Isomers can be defined as the organic molecules which have the same molecular formula and different structural formula.

Due to different structural formula, isomers have different physical and chemical properties.

Expert Solution
Check Mark

Answer to Problem 7E

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  5

Explanation of Solution

The given structure is as follows:

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  6

There are 5 carbon atoms thus, it is 2-pentanone.

2-pentanone is an isomer of pentanal as it also contains 5 carbon atoms, 1 O atom and 10 H atoms.

The structure of pentanal is represented as follows:

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  7

Interpretation Introduction

(c)

Interpretation:

The isomer of a given compound needs to be determined.

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  8

Concept introduction:

Isomers can be defined as the organic molecules which have the same molecular formula and different structural formula.

Due to different structural formula, isomers have different physical and chemical properties.

Expert Solution
Check Mark

Answer to Problem 7E

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  9

Explanation of Solution

The given structure is as follows:

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  10

The formula of the given compound is CH3COCH(CH3)CH3 (3-methylbutanone).

3-methylbutanone must be an isomer of pentanal as both have the same molecular formula but different structural formulas.

The structure of pentanal is as follows:

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  11

Interpretation Introduction

(d)

Interpretation:

The isomer of a given compound needs to be determined.

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  12

Concept introduction:

Isomers can be defined as the organic molecules which have the same molecular formula and different structural formula.

Due to different structural formula, isomers have different physical and chemical properties.

Expert Solution
Check Mark

Answer to Problem 7E

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  13

Explanation of Solution

The given structure is as follows:

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  14

The formula of the given compound is CH3CH2COOCH3 (methylpropanoate).

Methylpropanoate is an ester as RCOOR is the general formula. Esters are isomers of carboxylic acid therefore it must be carboxylic acid with 4 C atoms that is butanoic acid.

The structure is represented as follows:

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  15

Interpretation Introduction

(e)

Interpretation:

The isomer of a given compound needs to be determined.

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  16

Concept introduction:

Isomers can be defined as the organic molecules which have the same molecular formula and different structural formula.

Due to different structural formula, isomers have different physical and chemical properties.

Expert Solution
Check Mark

Answer to Problem 7E

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  17

Explanation of Solution

The given structure is as follows:

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  18

The formula of the given compound is CH3CH2CH2NHCH3 (N-methylpropanamine). N-methypropanamine is a secondary amine as two alkyl groups are bonded with −NH- thus the isomer can have the same functional group with different alkyl groups as given. It will be N-ethylethanamine. The structure will be as follows:

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  19

Interpretation Introduction

(f)

Interpretation:

The isomer of given compound needs to be determined.

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  20

Concept introduction:

Isomers can be defined as the organic molecules which have the same molecular formula and different structural formula.

Due to different structural formula, isomers have different physical and chemical properties.

Expert Solution
Check Mark

Answer to Problem 7E

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  21

Explanation of Solution

The given structure is as follows:

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  22

The formula of the given compound is HCOOCH3. It is an ester as RCOOR is the general formula. Esters are isomers of carboxylic acid therefore it must be carboxylic acid with 2 C atoms that is ethanoic acid. The structure is as follows:

Living By Chemistry: First Edition Textbook, Chapter U2.2, Problem 7E , additional homework tip  23

Chapter U2 Solutions

Living By Chemistry: First Edition Textbook

Ch. U2.2 - Prob. 3ECh. U2.2 - Prob. 4ECh. U2.2 - Prob. 5ECh. U2.2 - Prob. 6ECh. U2.2 - Prob. 7ECh. U2.3 - Prob. 1TAICh. U2.3 - Prob. 1ECh. U2.3 - Prob. 2ECh. U2.3 - Prob. 3ECh. U2.3 - Prob. 4ECh. U2.3 - Prob. 5ECh. U2.4 - Prob. 1TAICh. U2.4 - Prob. 1ECh. U2.4 - Prob. 2ECh. U2.4 - Prob. 3ECh. U2.4 - Prob. 4ECh. U2.4 - Prob. 5ECh. U2.4 - Prob. 6ECh. U2.4 - Prob. 7ECh. U2.4 - Prob. 8ECh. U2.5 - Prob. 1TAICh. U2.5 - Prob. 1ECh. U2.5 - Prob. 2ECh. U2.5 - Prob. 3ECh. U2.5 - Prob. 4ECh. U2.5 - Prob. 5ECh. U2.5 - Prob. 6ECh. U2.5 - Prob. 7ECh. U2.5 - Prob. 8ECh. U2.5 - Prob. 9ECh. U2.6 - Prob. 1TAICh. U2.6 - Prob. 1ECh. U2.6 - Prob. 2ECh. U2.6 - Prob. 3ECh. U2.6 - Prob. 4ECh. U2.6 - Prob. 5ECh. U2.6 - Prob. 6ECh. U2.6 - Prob. 7ECh. U2.6 - Prob. 8ECh. U2.6 - Prob. 9ECh. U2.6 - Prob. 10ECh. U2.6 - Prob. 11ECh. U2.7 - Prob. 1TAICh. U2.7 - Prob. 1ECh. U2.7 - Prob. 2ECh. U2.7 - Prob. 3ECh. U2.7 - Prob. 4ECh. U2.7 - Prob. 5ECh. U2.8 - Prob. 1TAICh. U2.8 - Prob. 1ECh. U2.8 - Prob. 2ECh. U2.8 - Prob. 3ECh. U2.8 - Prob. 4ECh. U2.8 - Prob. 5ECh. U2.8 - Prob. 6ECh. U2.9 - Prob. 1TAICh. U2.9 - Prob. 1ECh. U2.9 - Prob. 2ECh. U2.9 - Prob. 3ECh. U2.9 - Prob. 4ECh. U2.9 - Prob. 5ECh. U2.9 - Prob. 6ECh. U2.9 - Prob. 7ECh. U2.10 - Prob. 1TAICh. U2.10 - Prob. 1ECh. U2.10 - Prob. 2ECh. U2.10 - Prob. 3ECh. U2.10 - Prob. 4ECh. U2.10 - Prob. 5ECh. U2.10 - Prob. 6ECh. U2.10 - Prob. 7ECh. U2.10 - Prob. 8ECh. U2.10 - Prob. 9ECh. U2.11 - Prob. 1TAICh. U2.11 - Prob. 1ECh. U2.11 - Prob. 2ECh. U2.11 - Prob. 3ECh. U2.11 - Prob. 4ECh. U2.11 - Prob. 5ECh. U2.11 - Prob. 6ECh. U2.11 - Prob. 7ECh. U2.12 - Prob. 1TAICh. U2.12 - Prob. 1ECh. U2.12 - Prob. 2ECh. U2.12 - Prob. 3ECh. U2.12 - Prob. 4ECh. U2.12 - Prob. 5ECh. U2.12 - Prob. 6ECh. U2.12 - Prob. 7ECh. U2.13 - Prob. 1TAICh. U2.13 - Prob. 1ECh. U2.13 - Prob. 2ECh. U2.13 - Prob. 3ECh. U2.13 - Prob. 4ECh. U2.13 - Prob. 5ECh. U2.14 - Prob. 1TAICh. U2.14 - Prob. 1ECh. U2.14 - Prob. 2ECh. U2.14 - Prob. 3ECh. U2.14 - Prob. 4ECh. U2.14 - Prob. 5ECh. U2.14 - Prob. 6ECh. U2.14 - Prob. 7ECh. U2.14 - Prob. 8ECh. U2.15 - Prob. 1TAICh. U2.15 - Prob. 1ECh. U2.15 - Prob. 2ECh. U2.15 - Prob. 4ECh. U2.15 - Prob. 5ECh. U2.15 - Prob. 6ECh. U2.16 - Prob. 1TAICh. U2.16 - Prob. 1ECh. U2.16 - Prob. 2ECh. U2.16 - Prob. 3ECh. U2.16 - Prob. 4ECh. U2.16 - Prob. 6ECh. U2.16 - Prob. 7ECh. U2.17 - Prob. 1TAICh. U2.17 - Prob. 1ECh. U2.17 - Prob. 2ECh. U2.17 - Prob. 3ECh. U2.17 - Prob. 4ECh. U2.17 - Prob. 5ECh. U2.17 - Prob. 6ECh. U2.17 - Prob. 7ECh. U2.17 - Prob. 8ECh. U2.17 - Prob. 9ECh. U2.18 - Prob. 1TAICh. U2.18 - Prob. 1ECh. U2.18 - Prob. 2ECh. U2.18 - Prob. 3ECh. U2.18 - Prob. 4ECh. U2.18 - Prob. 5ECh. U2.18 - Prob. 6ECh. U2.18 - Prob. 7ECh. U2.19 - Prob. 1TAICh. U2.19 - Prob. 1ECh. U2.19 - Prob. 2ECh. U2.19 - Prob. 3ECh. U2.19 - Prob. 4ECh. U2.19 - Prob. 5ECh. U2.19 - Prob. 6ECh. U2.19 - Prob. 7ECh. U2.19 - Prob. 8ECh. U2.19 - Prob. 9ECh. U2.20 - Prob. 1TAICh. U2.20 - Prob. 1ECh. U2.20 - Prob. 2ECh. U2.20 - Prob. 3ECh. U2.20 - Prob. 4ECh. U2.20 - Prob. 5ECh. U2.20 - Prob. 6ECh. U2.20 - Prob. 7ECh. U2.20 - Prob. 8ECh. U2.20 - Prob. 9ECh. U2.21 - Prob. 1TAICh. U2.21 - Prob. 1ECh. U2.21 - Prob. 2ECh. U2.21 - Prob. 3ECh. U2.21 - Prob. 4ECh. U2.21 - Prob. 6ECh. U2 - Prob. SI1RECh. U2 - Prob. SI2RECh. U2 - Prob. SI3RECh. U2 - Prob. SI4RECh. U2 - Prob. SI5RECh. U2 - Prob. SII1RECh. U2 - Prob. SII2RECh. U2 - Prob. SII3RECh. U2 - Prob. SII4RECh. U2 - Prob. SII5RECh. U2 - Prob. SIII1RECh. U2 - Prob. SIII2RECh. U2 - Prob. SIII3RECh. U2 - Prob. SIII4RECh. U2 - Prob. SIII5RECh. U2 - Prob. SIII6RECh. U2 - Prob. SIV1ECh. U2 - Prob. SIV2ECh. U2 - Prob. SIV3ECh. U2 - Prob. SIV4ECh. U2 - Prob. SIV5ECh. U2 - Prob. 1RECh. U2 - Prob. 2RECh. U2 - Prob. 3RECh. U2 - Prob. 4RECh. U2 - Prob. 5RECh. U2 - Prob. 6RECh. U2 - Prob. 7RECh. U2 - Prob. 8RE
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