Living by Chemistry
Living by Chemistry
2nd Edition
ISBN: 9781464142314
Author: Angelica M. Stacy
Publisher: W. H. Freeman
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Chapter U4, Problem C13.4RE

(a)

Interpretation Introduction

Interpretation: The balanced chemical equation for the given chemical reaction of nitrogen gas and hydrogen gas needs to be determined.

Concept Introduction:

The chemical reaction must be balanced such that it agrees with the law of mass conservation. A balanced chemical equation arises when the number of atoms or ions of the reactant side equals the number of atoms or ions of the product side.

(a)

Expert Solution
Check Mark

Answer to Problem C13.4RE

The balanced chemical equation is:

  N2(g)  +  2H2(g)    N2H4(g)

Explanation of Solution

The unbalanced chemical reaction is as follows:

  N2(g)  +  H2(g)    N2H4(g)

To balance the above reaction, give coefficient 2 to H2 thus, the balanced chemical reaction will be as follows:

  N2(g)  +  2H2(g)    N2H4(g)

(b)

Interpretation Introduction

Interpretation: The balanced chemical equation for the given chemical reaction of potassium nitrate and potassium metal needs to be determined.

Concept Introduction:

The chemical reaction must be balanced such that it agrees with the law of mass conservation. A balanced chemical equation arises when the number of atoms or ions of the reactant side equals the number of atoms or ions of the product side.

(b)

Expert Solution
Check Mark

Answer to Problem C13.4RE

The balanced chemical equation is:

  2KNO3(s)  +  10K(s)    6K2O(s)  +  N2(g)

Explanation of Solution

The unbalanced chemical reaction is as follows:

  KNO3(s)  +  K(s)    K2O(s)  +  N2(g)

To balance the above reaction, give coefficient 2 to KNO3, 10 to K and 6 to K2O, balanced chemical reaction will be as follows:

  2KNO3(s)  +  10K(s)    6K2O(s)  +  N2(g)

(c)

Interpretation Introduction

Interpretation: The balanced chemical equation for the given chemical reaction of aqueous sulfuric acid and aqueous sodium cyanide needs to be determined.

Concept Introduction:

The chemical reaction must be balanced such that it agrees with the law of mass conservation. A balanced chemical equation arises when the number of atoms or ions of the reactant side equals the number of atoms or ions of the product side.

(c)

Expert Solution
Check Mark

Answer to Problem C13.4RE

The balanced chemical equation is:

  H2SO4(aq)  +  2NaCN(aq)    2HCN(g)  +  Na2SO4(aq)

Explanation of Solution

The unbalanced chemical reaction is as follows:

  H2SO4(aq)  +  NaCN(aq)    HCN(g)  +  Na2SO4(aq)

To balance the above reaction, give coefficient 2 to NaCN and 2 to HCN, balanced chemical reaction will be as follows:

  H2SO4(aq)  +  2NaCN(aq)    2HCN(g)  +  Na2SO4(aq)

(d)

Interpretation Introduction

Interpretation: The balanced chemical equation for the given chemical reaction of phosphoric acid and calcium hydroxide needs to be determined.

Concept Introduction:

The chemical reaction must be balanced such that it agrees with the law of mass conservation. A balanced chemical equation arises when the number of atoms or ions of the reactant side equals the number of atoms or ions of the product side.

(d)

Expert Solution
Check Mark

Answer to Problem C13.4RE

The balanced chemical equation is:

  2H3PO4(aq)  +  3Ca(OH)2(aq)    Ca3(PO4)2(aq)  +  6H2O(l)

Explanation of Solution

The unbalanced chemical reaction is as follows:

  H3PO4(aq)  +  Ca(OH)2(aq)    Ca3(PO4)2(aq)  +  H2O(l)

To balance the above reaction, give coefficient 2 to H3PO4, 3 to Ca(OH)2 and 6 to H2O, thus, the balanced chemical reaction will be as follows:

  2H3PO4(aq)  +  3Ca(OH)2(aq)    Ca3(PO4)2(aq)  +  6H2O(l)

(e)

Interpretation Introduction

Interpretation: The balanced chemical equation for the given chemical reaction of propane and oxygen gas needs to be determined.

Concept Introduction:

The chemical reaction must be balanced such that it agrees with the law of mass conservation. A balanced chemical equation arises when the number of atoms or ions of the reactant side equals the number of atoms or ions of the product side.

(e)

Expert Solution
Check Mark

Answer to Problem C13.4RE

The balanced chemical equation is:

  C3H8(g)  +  5O2(g)    3CO2(g)  +   4H2O(l)

Explanation of Solution

The unbalanced chemical reaction is as follows:

  C3H8(g)  +  O2(g)    CO2(g)  +   H2O(l)

To balance the above reaction, give coefficient 5 to O2, 3to CO2 and 4 to H2O thus, the balanced chemical equation will be:

  C3H8(g)  +  5O2(g)    3CO2(g)  +   4H2O(l)

(f)

Interpretation Introduction

Interpretation: The balanced chemical equation for the given chemical reaction of hydrogen sulfide and oxygen gas needs to be determined

Concept Introduction:

The chemical reaction must be balanced such that it agrees with the law of mass conservation. A balanced chemical equation arises when the number of atoms or ions of the reactant side equals the number of atoms or ions of the product side.

(f)

Expert Solution
Check Mark

Answer to Problem C13.4RE

The balanced chemical equation is:

  2H2S(g)  +  3O2(g)    2SO2(g)  +   2H2O(l)

Explanation of Solution

The unbalanced chemical reaction is as follows:

  H2S(g)  +  O2(g)    SO2(g)  +   H2O(l)

To balance the above reaction, give coefficient 2 to H2S, 3to O2, 2 to SO2 and 2 to H2O thus, the balanced chemical equation will be:

  2H2S(g)  +  3O2(g)    2SO2(g)  +   2H2O(l)

(g)

Interpretation Introduction

Interpretation: The balanced chemical equation for the given chemical reaction of hydrogen and oxygen gas needs to be determined.

Concept Introduction:

The chemical reaction must be balanced such that it agrees with the law of mass conservation. A balanced chemical equation arises when the number of atoms or ions of the reactant side equals the number of atoms or ions of the product side.

(g)

Expert Solution
Check Mark

Answer to Problem C13.4RE

The balanced chemical equation is:

  2H2(g)  +  O2(g)      2H2O(l)

Explanation of Solution

The unbalanced chemical reaction is as follows:

  H2(g)  +  O2(g)      H2O(l)

To balance the above reaction, give coefficient 2 to H2and 2 to H2O thus, the balanced chemical equation will be:

  2H2(g)  +  O2(g)      2H2O(l)

Chapter U4 Solutions

Living by Chemistry

Ch. U4.69 - Prob. 3ECh. U4.69 - Prob. 4ECh. U4.69 - Prob. 5ECh. U4.70 - Prob. 1TAICh. U4.70 - Prob. 1ECh. U4.70 - Prob. 2ECh. U4.70 - Prob. 3ECh. U4.70 - Prob. 4ECh. U4.70 - Prob. 6ECh. U4.71 - Prob. 1TAICh. U4.71 - Prob. 1ECh. U4.71 - Prob. 2ECh. U4.71 - Prob. 3ECh. U4.71 - Prob. 4ECh. U4.71 - Prob. 5ECh. U4.71 - Prob. 6ECh. U4.71 - Prob. 7ECh. U4.72 - Prob. 1TAICh. U4.72 - Prob. 1ECh. U4.72 - Prob. 2ECh. U4.72 - Prob. 3ECh. U4.72 - Prob. 4ECh. U4.73 - Prob. 1TAICh. U4.73 - Prob. 1ECh. U4.73 - Prob. 2ECh. U4.73 - Prob. 3ECh. U4.73 - Prob. 5ECh. U4.73 - Prob. 6ECh. U4.73 - Prob. 7ECh. U4.74 - Prob. 1TAICh. U4.74 - Prob. 1ECh. U4.74 - Prob. 2ECh. U4.74 - Prob. 4ECh. U4.74 - Prob. 5ECh. U4.75 - Prob. 1TAICh. U4.75 - Prob. 1ECh. U4.75 - Prob. 2ECh. U4.75 - Prob. 4ECh. U4.75 - Prob. 5ECh. U4.75 - Prob. 6ECh. U4.75 - Prob. 7ECh. U4.75 - Prob. 8ECh. U4.75 - Prob. 9ECh. U4.75 - Prob. 10ECh. U4.75 - Prob. 11ECh. U4.76 - Prob. 1TAICh. U4.76 - Prob. 1ECh. U4.76 - Prob. 2ECh. U4.76 - Prob. 3ECh. U4.76 - Prob. 4ECh. U4.76 - Prob. 5ECh. U4.76 - Prob. 6ECh. U4.76 - Prob. 7ECh. U4.76 - Prob. 8ECh. U4.77 - Prob. 1TAICh. U4.77 - Prob. 1ECh. U4.77 - Prob. 2ECh. U4.77 - Prob. 3ECh. U4.77 - Prob. 4ECh. U4.77 - Prob. 5ECh. U4.77 - Prob. 6ECh. U4.77 - Prob. 7ECh. U4.77 - Prob. 8ECh. U4.78 - Prob. 1TAICh. U4.78 - Prob. 1ECh. U4.78 - Prob. 2ECh. U4.78 - Prob. 3ECh. U4.78 - Prob. 4ECh. U4.78 - Prob. 5ECh. U4.78 - Prob. 6ECh. U4.78 - Prob. 7ECh. U4.78 - Prob. 8ECh. U4.79 - Prob. 1TAICh. U4.79 - Prob. 1ECh. U4.79 - Prob. 2ECh. U4.79 - Prob. 3ECh. U4.79 - Prob. 4ECh. U4.80 - Prob. 1TAICh. U4.80 - Prob. 1ECh. U4.80 - Prob. 2ECh. U4.80 - Prob. 3ECh. U4.80 - Prob. 4ECh. U4.80 - Prob. 5ECh. U4.80 - Prob. 6ECh. U4.80 - Prob. 7ECh. U4.80 - Prob. 8ECh. U4.80 - Prob. 9ECh. U4.80 - Prob. 10ECh. U4.81 - Prob. 1TAICh. U4.81 - Prob. 1ECh. U4.81 - Prob. 2ECh. U4.81 - Prob. 3ECh. U4.81 - Prob. 4ECh. U4.81 - Prob. 5ECh. U4.81 - Prob. 6ECh. U4.81 - Prob. 7ECh. U4.81 - Prob. 8ECh. U4.81 - Prob. 9ECh. U4.82 - Prob. 1TAICh. U4.82 - Prob. 1ECh. U4.82 - Prob. 2ECh. U4.82 - Prob. 3ECh. U4.82 - Prob. 4ECh. U4.82 - Prob. 5ECh. U4.82 - Prob. 6ECh. U4.82 - Prob. 7ECh. U4.82 - Prob. 8ECh. U4.83 - Prob. 1TAICh. U4.83 - Prob. 1ECh. U4.83 - Prob. 2ECh. U4.83 - Prob. 3ECh. U4.83 - Prob. 4ECh. U4.83 - Prob. 5ECh. U4.83 - Prob. 6ECh. U4.83 - Prob. 7ECh. U4.84 - Prob. 1TAICh. U4.84 - Prob. 1ECh. U4.84 - Prob. 2ECh. U4.84 - Prob. 3ECh. U4.84 - Prob. 5ECh. U4.84 - Prob. 6ECh. U4.84 - Prob. 7ECh. U4.85 - Prob. 1TAICh. U4.85 - Prob. 1ECh. U4.85 - Prob. 2ECh. U4.85 - Prob. 3ECh. U4.85 - Prob. 4ECh. U4.85 - Prob. 5ECh. U4.85 - Prob. 6ECh. U4.85 - Prob. 7ECh. U4.85 - Prob. 8ECh. U4.86 - Prob. 1TAICh. U4.86 - Prob. 1ECh. U4.86 - Prob. 2ECh. U4.86 - Prob. 3ECh. U4.86 - Prob. 4ECh. U4.86 - Prob. 6ECh. U4.86 - Prob. 7ECh. U4.86 - Prob. 8ECh. U4.87 - Prob. 1TAICh. U4.87 - Prob. 1ECh. U4.87 - Prob. 2ECh. U4.87 - Prob. 3ECh. U4.87 - Prob. 4ECh. U4.87 - Prob. 5ECh. U4.87 - Prob. 6ECh. U4.87 - Prob. 7ECh. U4.87 - Prob. 8ECh. U4.88 - Prob. 1TAICh. U4.88 - Prob. 1ECh. U4.88 - Prob. 2ECh. U4.88 - Prob. 4ECh. U4.88 - Prob. 5ECh. U4.88 - Prob. 6ECh. U4.88 - Prob. 7ECh. U4.88 - Prob. 8ECh. U4.89 - Prob. 1TAICh. U4.89 - Prob. 1ECh. U4.89 - Prob. 2ECh. U4.89 - Prob. 3ECh. U4.89 - Prob. 4ECh. U4.89 - Prob. 5ECh. U4.89 - Prob. 6ECh. U4.90 - Prob. 1ECh. U4.90 - Prob. 2ECh. U4.90 - Prob. 3ECh. U4.90 - Prob. 4ECh. U4.90 - Prob. 5ECh. U4.90 - Prob. 6ECh. U4.90 - Prob. 7ECh. U4.91 - Prob. 1ECh. U4.91 - Prob. 2ECh. U4.91 - Prob. 3ECh. U4.91 - Prob. 5ECh. U4.91 - Prob. 6ECh. U4.92 - Prob. 1TAICh. U4.92 - Prob. 1ECh. U4.92 - Prob. 2ECh. U4.92 - Prob. 3ECh. U4.92 - Prob. 4ECh. U4.93 - Prob. 1TAICh. U4.93 - Prob. 1ECh. U4.93 - Prob. 2ECh. U4.93 - Prob. 4ECh. U4.93 - Prob. 5ECh. U4.93 - Prob. 6ECh. U4 - Prob. C13.3RECh. U4 - Prob. C13.4RECh. U4 - Prob. C14.1RECh. U4 - Prob. C14.2RECh. U4 - Prob. C14.3RECh. U4 - Prob. C14.5RECh. U4 - Prob. C14.6RECh. U4 - Prob. C15.1RECh. U4 - Prob. C15.2RECh. U4 - Prob. C15.3RECh. U4 - Prob. C15.4RECh. U4 - Prob. C15.5RECh. U4 - Prob. C15.6RECh. U4 - Prob. C15.7RECh. U4 - Prob. C15.8RECh. U4 - Prob. C16.1RECh. U4 - Prob. C16.2RECh. U4 - Prob. C16.3RECh. U4 - Prob. C16.4RECh. U4 - Prob. C17.1RECh. U4 - Prob. C17.2RECh. U4 - Prob. C17.3RECh. U4 - Prob. 1RECh. U4 - Prob. 4RECh. U4 - Prob. 5RECh. U4 - Prob. 6RECh. U4 - Prob. 7RECh. U4 - Prob. 8RECh. U4 - Prob. 9RECh. U4 - Prob. 10RECh. U4 - Prob. 11RECh. U4 - Prob. 12RECh. U4 - Prob. 1STPCh. U4 - Prob. 2STPCh. U4 - Prob. 3STPCh. U4 - Prob. 4STPCh. U4 - Prob. 5STPCh. U4 - Prob. 6STPCh. U4 - Prob. 7STPCh. U4 - Prob. 8STPCh. U4 - Prob. 9STPCh. U4 - Prob. 10STPCh. U4 - Prob. 11STPCh. U4 - Prob. 12STPCh. U4 - Prob. 13STPCh. U4 - Prob. 14STPCh. U4 - Prob. 15STPCh. U4 - Prob. 16STPCh. U4 - Prob. 17STPCh. U4 - Prob. 18STPCh. U4 - Prob. 19STPCh. U4 - Prob. 20STP
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