Living by Chemistry
Living by Chemistry
2nd Edition
ISBN: 9781464142314
Author: Angelica M. Stacy
Publisher: W. H. Freeman
Question
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Chapter U4.76, Problem 8E
Interpretation Introduction

Interpretation: The given table needs to be completed.

Concept Introduction: The number of atoms in 1 mol of any substance is equal to 6.023×1023 atoms. This is known as Avogadro’s number.

Expert Solution & Answer
Check Mark

Explanation of Solution

Mass of 1 mol of carbon =12 g.

Number of moles of 24 g of C will be:

24 g C 2412 mol=2 mol.

Since, 1 mol C contains 6.02×1023 atoms.

So, 2 mol C contains 2×6.02×1023atoms=1.20×1024atoms .

Similarly,

Mass of 1 mol of Ca=40 g.

Number of moles in 40 g of Ca will be:

So, 40 g Ca 4040 mol=1 mol

Here,

1 mol Ca contains =6.02×1023 atoms.

Now,

20 g Ca 2040 mol=0.5 mol

Also,

0.5 mol Ca contains =0.5×6.02×1023atoms=3.01×1023atoms .

The complete table will be as follows:

Living by Chemistry, Chapter U4.76, Problem 8E

Chapter U4 Solutions

Living by Chemistry

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