   Chapter 13, Problem 110AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# hen ammonium carbonate is heated, three gases are produced by its decomposition.msp;  ( NH 4 ) 2 CO 3 ( s )   2NH 3 ( g ) + CO 2 ( g ) + H 2 O ( g ) at total volume of gas is produced, measured at 453  ° C and 1 .0 4 atm, if 52 .0  g of ammonium carbonate is heated?

Interpretation Introduction

Interpretation:

The total volume of gas produced should be calculated.

Concept Introduction:

According to ideal gas equation:

PV=nRT

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature.

The value of Universal gas constant can be taken as 0.082 L atm K1 mol1.

Mass of gas can be calculated from number of moles and molar mass as follows:

m=n×M

Here, n is number of moles, m is mass and M is molar mass.

Explanation

Calculation:

The balanced chemical reaction is as follows:

(NH4)2CO3(s)2NH3(g)+CO2(g)+H2O(g)

The number of moles of ammonium chloride can be calculated as follows:

n=mM

Molar mass of ammonium carbonate is 96.09 g/mol thus,

n=52.0 g96.09 g/mol=0.5412 mol

From the balanced chemical reaction, 1 mol of ammonium chloride produce 2 mol of ammonia gas, 1 mol of carbon dioxide gas and 1 mol of water vapour.

Thus, 0.5412 mol of ammonium chloride produces 1.0824 mol of ammonia gas, 0.5412 mol of carbon dioxide and 0.5412 mol of water vapour.

Total number of moles will be:

nT=nNH3+nCO2+nH2O

Putting the values,

nT=(1

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