   Chapter 13, Problem 146AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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# hat volume of CO 2 measured at STP is produced when 27 . 5 g of CaCO 3 is decomposed?msp;  CaCO 3 ( s )   CaO ( s ) + CO 2 ( g )

Interpretation Introduction

Interpretation:

To calculate the volume of CO2 gas evolved during the decomposition of CaCO3 solid.

Concept Introduction:

The balance equation of decomposition of CaCO3 provides idea about mole ratio of reactant and product. Moles can be calculated with the help of mass and molar mass with the given formula:

Number of moles = massmolar mass.

Explanation

Given information:

Mass of calcium carbonate = 27.5 g

The mass of calcium carbonate must be converted to moles which gives the moles of carbon dioxide released as the mole ratio is 1:1. The mole of carbon dioxide can be converted to volume with the help of ideal gas equation at STP conditions of temperature and pressure.

Molar mass of CaCO3 = 100.08 g/mol

Number of moles of CaCO3 = massmolar mass = 27.5 g100.08 g/mol=0.275 mol

According to given balance equation, 1 mole of CaCO3 form 1 moles of CO2 gas.

Therefore,

0.275 mol of CaCO3×1 mol of CO21 mol of CaCO3=0

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