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EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Question
Chapter 14, Problem 14.36AP
Interpretation Introduction
Interpretation:
The compounds A, B, and C are to be identified from the given spectra data.
Concept introduction:
The compounds that contain carbon and hydrogen atoms are known as hydrocarbon compounds. These compounds originate from plants and animals. These are also known as organic compounds. There are two classes of hydrocarbon compounds, saturated and
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Students have asked these similar questions
Compound X, C,4H12Br2, is optically inactive. On treatment with strong base, X gives hydrocarbon Y, C14H10: Compound Y absorbs 2 equivalents of
hydrogen when reduced over a palladium catalyst to give z (C14H14) and reacts with ozone to give one product, benzoic acid (C,Hg02). Draw the
structure of compound Z.
• Use the wedge/hash bond tools to indicate stereochemistry where it exists.
• Ignore alkene stereochemistry.
• If more than one structure fits the description, draw them all.
• Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner.
• Separate structures with + signs from the drop-down menu.
ChemDoodle
Compounds B and C are isomers with molecular formula C5H9BrO2. The 1H NMR spectrum of compounds B and C are shown below. The IR spectrum corresponding to compound B showed strong absorption bands at 1739, 1225, and 1158 cm-1, while the spectrum corresponding to compound C have strong bands at 1735, 1237, and 1182 cm-1.
1.Based on the information provided, determine the structure of compounds B and C.
2.Assign all peaks in 1H NMR spectrum of compounds B and C.
The compound below is treated with chlorine in the presence of
light.
H3C,
CH3
H3C
`CH3
Draw the structure for the organic radical species produced by
reaction of the compound with a chlorine atom. Assume reaction
occurs at the weakest C-H bond.
You do not have to consider stereochemistry.
You do not have to explicitly draw H atoms.
Chapter 14 Solutions
EBK ORGANIC CHEMISTRY
Ch. 14 - Prob. 14.1PCh. 14 - Prob. 14.2PCh. 14 - Prob. 14.3PCh. 14 - Prob. 14.4PCh. 14 - Prob. 14.5PCh. 14 - Prob. 14.6PCh. 14 - Prob. 14.7PCh. 14 - Prob. 14.8PCh. 14 - Prob. 14.9PCh. 14 - Prob. 14.10P
Ch. 14 - Prob. 14.11PCh. 14 - Prob. 14.12PCh. 14 - Prob. 14.13PCh. 14 - Prob. 14.14PCh. 14 - Prob. 14.15PCh. 14 - Prob. 14.16PCh. 14 - Prob. 14.17PCh. 14 - Prob. 14.18PCh. 14 - Prob. 14.19PCh. 14 - Prob. 14.20PCh. 14 - Prob. 14.21PCh. 14 - Prob. 14.22PCh. 14 - Prob. 14.23PCh. 14 - Prob. 14.24PCh. 14 - Prob. 14.25PCh. 14 - Prob. 14.26APCh. 14 - Prob. 14.27APCh. 14 - Prob. 14.28APCh. 14 - Prob. 14.29APCh. 14 - Prob. 14.30APCh. 14 - Prob. 14.31APCh. 14 - Prob. 14.32APCh. 14 - Prob. 14.33APCh. 14 - Prob. 14.34APCh. 14 - Prob. 14.35APCh. 14 - Prob. 14.36APCh. 14 - Prob. 14.37APCh. 14 - Prob. 14.38APCh. 14 - Prob. 14.39APCh. 14 - Prob. 14.40APCh. 14 - Prob. 14.41APCh. 14 - Prob. 14.42APCh. 14 - Prob. 14.43APCh. 14 - Prob. 14.44APCh. 14 - Prob. 14.45APCh. 14 - Prob. 14.46APCh. 14 - Prob. 14.47AP
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