(a) Interpretation: The possible enol structures for the given structure are to be drawn. Concept introduction: The carbonyl compound contains a C = O group. They are of two types, aldehyde ( CHO ) and ketone ( RC = OR ) . Ketone also exist in two forms which are results of keto enol tautomerism. Tautomers are isomers which differ only in the position of the protons and electrons of double bond of the electronegative atom in the compound. There is no change in the carbon skeleton of the compound. This phenomenon which involves simple proton transfer in an intramolecular fashion is known as tautomerism. The very common example of tautomerism is keto-enol tautomerism. It can be acid or base catalysed.

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Answer 1

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Definition Definition Molecules that have multiple bonds between their carbon atoms. Alkenes are hydrocarbons with a double bond between two adjacent carbon atoms (R 2 C=CR 2 ), whereas alkynes are hydrocarbons with a triple bond between two adjacent carbon atoms R-C=C-R . These two groups are known as unsaturated hydrocarbons. They have fewer hydrogen atoms when compared with alkanes with same number of carbon atoms. The general molecular formula for an unsaturated hydrocarbon can be represented as C n H 2n +2 .

Chapter 14, Problem 14.35AP

Interpretation Introduction

(a)

Interpretation:

The possible enol structures for the given structure are to be drawn.

Concept introduction:

The carbonyl compound contains a C=O group. They are of two types, aldehyde (CHO) and ketone (RC=OR). Ketone also exist in two forms which are results of keto enol tautomerism. Tautomers are isomers which differ only in the position of the protons and electrons of double bond of the electronegative atom in the compound. There is no change in the carbon skeleton of the compound. This phenomenon which involves simple proton transfer in an intramolecular fashion is known as tautomerism.

The very common example of tautomerism is keto-enol tautomerism. It can be acid or base catalysed.

Interpretation Introduction

(b)

Interpretation:

Whether the alkyne hydration is a good method for the preparation of given compound or not is to be stated.

Concept introduction:

There are two classes of hydrocarbon compounds, Saturated and unsaturated hydrocarbons. Unsaturated hydrocarbon are of two types, alkenes and alkynes. The alkene contains a double bnd between two carbon atoms. The alkynes contains a triple bond between two carbon atoms and follow general formula CnH2n-2. The name of the alkyne compounds ends with suffix −yne.

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(a) Provide the structures of two possible organic products. (b) Circle the major organic product. NBS hv

Answer 2

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Definition Definition Molecules that have multiple bonds between their carbon atoms. Alkenes are hydrocarbons with a double bond between two adjacent carbon atoms (R 2 C=CR 2 ), whereas alkynes are hydrocarbons with a triple bond between two adjacent carbon atoms R-C=C-R . These two groups are known as unsaturated hydrocarbons. They have fewer hydrogen atoms when compared with alkanes with same number of carbon atoms. The general molecular formula for an unsaturated hydrocarbon can be represented as C n H 2n +2 .

Chapter 14, Problem 14.35AP

Interpretation Introduction

(a)

Interpretation:

The possible enol structures for the given structure are to be drawn.

Concept introduction:

The carbonyl compound contains a C=O group. They are of two types, aldehyde (CHO) and ketone (RC=OR). Ketone also exist in two forms which are results of keto enol tautomerism. Tautomers are isomers which differ only in the position of the protons and electrons of double bond of the electronegative atom in the compound. There is no change in the carbon skeleton of the compound. This phenomenon which involves simple proton transfer in an intramolecular fashion is known as tautomerism.

The very common example of tautomerism is keto-enol tautomerism. It can be acid or base catalysed.

Interpretation Introduction

(b)

Interpretation:

Whether the alkyne hydration is a good method for the preparation of given compound or not is to be stated.

Concept introduction:

There are two classes of hydrocarbon compounds, Saturated and unsaturated hydrocarbons. Unsaturated hydrocarbon are of two types, alkenes and alkynes. The alkene contains a double bnd between two carbon atoms. The alkynes contains a triple bond between two carbon atoms and follow general formula CnH2n-2. The name of the alkyne compounds ends with suffix −yne.

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Answer 3

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Definition Definition Molecules that have multiple bonds between their carbon atoms. Alkenes are hydrocarbons with a double bond between two adjacent carbon atoms (R 2 C=CR 2 ), whereas alkynes are hydrocarbons with a triple bond between two adjacent carbon atoms R-C=C-R . These two groups are known as unsaturated hydrocarbons. They have fewer hydrogen atoms when compared with alkanes with same number of carbon atoms. The general molecular formula for an unsaturated hydrocarbon can be represented as C n H 2n +2 .

Chapter 14, Problem 14.35AP

Interpretation Introduction

(a)

Interpretation:

The possible enol structures for the given structure are to be drawn.

Concept introduction:

The carbonyl compound contains a C=O group. They are of two types, aldehyde (CHO) and ketone (RC=OR). Ketone also exist in two forms which are results of keto enol tautomerism. Tautomers are isomers which differ only in the position of the protons and electrons of double bond of the electronegative atom in the compound. There is no change in the carbon skeleton of the compound. This phenomenon which involves simple proton transfer in an intramolecular fashion is known as tautomerism.

The very common example of tautomerism is keto-enol tautomerism. It can be acid or base catalysed.

Interpretation Introduction

(b)

Interpretation:

Whether the alkyne hydration is a good method for the preparation of given compound or not is to be stated.

Concept introduction:

There are two classes of hydrocarbon compounds, Saturated and unsaturated hydrocarbons. Unsaturated hydrocarbon are of two types, alkenes and alkynes. The alkene contains a double bnd between two carbon atoms. The alkynes contains a triple bond between two carbon atoms and follow general formula CnH2n-2. The name of the alkyne compounds ends with suffix −yne.

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Answer 4

Question

Definition Definition Molecules that have multiple bonds between their carbon atoms. Alkenes are hydrocarbons with a double bond between two adjacent carbon atoms (R 2 C=CR 2 ), whereas alkynes are hydrocarbons with a triple bond between two adjacent carbon atoms R-C=C-R . These two groups are known as unsaturated hydrocarbons. They have fewer hydrogen atoms when compared with alkanes with same number of carbon atoms. The general molecular formula for an unsaturated hydrocarbon can be represented as C n H 2n +2 .

Chapter 14, Problem 14.35AP

Interpretation Introduction

(a)

Interpretation:

The possible enol structures for the given structure are to be drawn.

Concept introduction:

The carbonyl compound contains a C=O group. They are of two types, aldehyde (CHO) and ketone (RC=OR). Ketone also exist in two forms which are results of keto enol tautomerism. Tautomers are isomers which differ only in the position of the protons and electrons of double bond of the electronegative atom in the compound. There is no change in the carbon skeleton of the compound. This phenomenon which involves simple proton transfer in an intramolecular fashion is known as tautomerism.

The very common example of tautomerism is keto-enol tautomerism. It can be acid or base catalysed.

Interpretation Introduction

(b)

Interpretation:

Whether the alkyne hydration is a good method for the preparation of given compound or not is to be stated.

Concept introduction:

There are two classes of hydrocarbon compounds, Saturated and unsaturated hydrocarbons. Unsaturated hydrocarbon are of two types, alkenes and alkynes. The alkene contains a double bnd between two carbon atoms. The alkynes contains a triple bond between two carbon atoms and follow general formula CnH2n-2. The name of the alkyne compounds ends with suffix −yne.

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Answer 5

Chapter 14, Problem 14.35AP

Interpretation Introduction

(a)

Interpretation:

The possible enol structures for the given structure are to be drawn.

Concept introduction:

The carbonyl compound contains a C=O group. They are of two types, aldehyde (CHO) and ketone (RC=OR). Ketone also exist in two forms which are results of keto enol tautomerism. Tautomers are isomers which differ only in the position of the protons and electrons of double bond of the electronegative atom in the compound. There is no change in the carbon skeleton of the compound. This phenomenon which involves simple proton transfer in an intramolecular fashion is known as tautomerism.

The very common example of tautomerism is keto-enol tautomerism. It can be acid or base catalysed.

Interpretation Introduction

(b)

Interpretation:

Whether the alkyne hydration is a good method for the preparation of given compound or not is to be stated.

Concept introduction:

There are two classes of hydrocarbon compounds, Saturated and unsaturated hydrocarbons. Unsaturated hydrocarbon are of two types, alkenes and alkynes. The alkene contains a double bnd between two carbon atoms. The alkynes contains a triple bond between two carbon atoms and follow general formula CnH2n-2. The name of the alkyne compounds ends with suffix −yne.

Answer 6

Chapter 14, Problem 14.35AP

Interpretation Introduction

(a)

Interpretation:

The possible enol structures for the given structure are to be drawn.

Concept introduction:

The carbonyl compound contains a C=O group. They are of two types, aldehyde (CHO) and ketone (RC=OR). Ketone also exist in two forms which are results of keto enol tautomerism. Tautomers are isomers which differ only in the position of the protons and electrons of double bond of the electronegative atom in the compound. There is no change in the carbon skeleton of the compound. This phenomenon which involves simple proton transfer in an intramolecular fashion is known as tautomerism.

The very common example of tautomerism is keto-enol tautomerism. It can be acid or base catalysed.

Answer 7

Chapter 14, Problem 14.35AP

Interpretation Introduction

(a)

Interpretation:

The possible enol structures for the given structure are to be drawn.

Concept introduction:

The carbonyl compound contains a C=O group. They are of two types, aldehyde (CHO) and ketone (RC=OR). Ketone also exist in two forms which are results of keto enol tautomerism. Tautomers are isomers which differ only in the position of the protons and electrons of double bond of the electronegative atom in the compound. There is no change in the carbon skeleton of the compound. This phenomenon which involves simple proton transfer in an intramolecular fashion is known as tautomerism.

The very common example of tautomerism is keto-enol tautomerism. It can be acid or base catalysed.

Answer 8

Interpretation Introduction

(b)

Interpretation:

Whether the alkyne hydration is a good method for the preparation of given compound or not is to be stated.

Concept introduction:

There are two classes of hydrocarbon compounds, Saturated and unsaturated hydrocarbons. Unsaturated hydrocarbon are of two types, alkenes and alkynes. The alkene contains a double bnd between two carbon atoms. The alkynes contains a triple bond between two carbon atoms and follow general formula CnH2n-2. The name of the alkyne compounds ends with suffix −yne.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Whether the alkyne hydration is a good method for the preparation of given compound or not is to be stated.

Concept introduction:

There are two classes of hydrocarbon compounds, Saturated and unsaturated hydrocarbons. Unsaturated hydrocarbon are of two types, alkenes and alkynes. The alkene contains a double bnd between two carbon atoms. The alkynes contains a triple bond between two carbon atoms and follow general formula CnH2n-2. The name of the alkyne compounds ends with suffix −yne.

Answer 10

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Answer 13

Ch. 14 - Prob. 14.1P Ch. 14 - Prob. 14.2P Ch. 14 - Prob. 14.3P Ch. 14 - Prob. 14.4P Ch. 14 - Prob. 14.5P Ch. 14 - Prob. 14.6P Ch. 14 - Prob. 14.7P Ch. 14 - Prob. 14.8P Ch. 14 - Prob. 14.9P Ch. 14 - Prob. 14.10P

Solution Summary: The author explains the possible enol structures for the given structure.

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