EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 14, Problem 14.42AP
Interpretation Introduction
(a)
Interpretation:
The compound is to be identified from its IR and proton NMR spectra.
Concept introduction:
The NMR stands for nuclear magnetic resonance. NMR spectroscopy deals with the interaction between
Interpretation Introduction
(b)
Interpretation:
The compound is to be identified from their IR and proton NMR spectra.
Concept introduction:
The NMR stands for nuclear magnetic resonance. NMR spectroscopy deals with the interaction between electromagnetic radiation and the nucleus of an atom. NMR spectroscopy is used to determine the structural information about compounds.
Interpretation Introduction
(c)
Interpretation:
The compound is to be identified from their IR and proton NMR spectra.
Concept introduction:
The NMR stands for nuclear magnetic resonance. NMR spectroscopy deals with the interaction between electromagnetic radiation and the nucleus of an atom. NMR spectroscopy is used to determine the structural information about compounds.
Interpretation Introduction
(d)
Interpretation:
The compound is to be identified from their IR and proton NMR spectra.
Concept introduction:
The NMR stands for nuclear magnetic resonance. NMR spectroscopy deals with the interaction between electromagnetic radiation and the nucleus of an atom. NMR spectroscopy is used to determine the structural information about compounds.
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There are several isomeric alcohols and ethers of molecular formula C5H12O. Two of these exhibit the following 1H-NMR spectra. Propose a structure for each of the isomers.
Isomer A: δ = 0.92 (t, 7.8 Hz, 3 H), 1.20 (s, 6H), 1.49 (q, 7.8 Hz, 2H), 1.85 (s, 1H) ppm
Isomer B: δ = 1.19 (s, 9 H), 3.21 (s, 3H) ppm
The 1H-NMR spectrum of Compound D of molecular formula C10H12O shows three singlets – δ 2.20 (6H, s), 4.86 (4H), 7.10 (2H) ppm. Its 13C-NMR spectrum has five signals – 20, 74, 127, 135, 146 ppm. Suggest a structure for this compound.
Compounds A and B are isomers having the molecular formula C4H8O3. Identify A and B on the basis of their 1H NMR spectra.Compound A: δ 1.3 (3H, triplet); 3.6 (2H, quartet); 4.1 (2H, singlet); 11.1 (1H, broad singlet)Compound B: δ 2.6 (2H, triplet); 3.4 (3H, singlet); 3.7 (2H triplet); 11.3 (1H, broad singlet)
Chapter 14 Solutions
EBK ORGANIC CHEMISTRY
Ch. 14 - Prob. 14.1PCh. 14 - Prob. 14.2PCh. 14 - Prob. 14.3PCh. 14 - Prob. 14.4PCh. 14 - Prob. 14.5PCh. 14 - Prob. 14.6PCh. 14 - Prob. 14.7PCh. 14 - Prob. 14.8PCh. 14 - Prob. 14.9PCh. 14 - Prob. 14.10P
Ch. 14 - Prob. 14.11PCh. 14 - Prob. 14.12PCh. 14 - Prob. 14.13PCh. 14 - Prob. 14.14PCh. 14 - Prob. 14.15PCh. 14 - Prob. 14.16PCh. 14 - Prob. 14.17PCh. 14 - Prob. 14.18PCh. 14 - Prob. 14.19PCh. 14 - Prob. 14.20PCh. 14 - Prob. 14.21PCh. 14 - Prob. 14.22PCh. 14 - Prob. 14.23PCh. 14 - Prob. 14.24PCh. 14 - Prob. 14.25PCh. 14 - Prob. 14.26APCh. 14 - Prob. 14.27APCh. 14 - Prob. 14.28APCh. 14 - Prob. 14.29APCh. 14 - Prob. 14.30APCh. 14 - Prob. 14.31APCh. 14 - Prob. 14.32APCh. 14 - Prob. 14.33APCh. 14 - Prob. 14.34APCh. 14 - Prob. 14.35APCh. 14 - Prob. 14.36APCh. 14 - Prob. 14.37APCh. 14 - Prob. 14.38APCh. 14 - Prob. 14.39APCh. 14 - Prob. 14.40APCh. 14 - Prob. 14.41APCh. 14 - Prob. 14.42APCh. 14 - Prob. 14.43APCh. 14 - Prob. 14.44APCh. 14 - Prob. 14.45APCh. 14 - Prob. 14.46APCh. 14 - Prob. 14.47AP
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