Concept explainers
(a)
Interpretation:
The compound having a molecular formula
Concept introduction:
The NMR stands for nuclear magnetic resonance. NMR spectroscopy deals with the interaction between
(b)
Interpretation:
The way by which
Concept introduction:
The NMR stands for nuclear magnetic resonance. NMR spectroscopy deals with the interaction between electromagnetic radiation and the nucleus of an atom. NMR spectroscopy is used to determine the structural information about compounds.
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EBK ORGANIC CHEMISTRY
- Predict the ¹H NMR spectrum of diethoxymethane.arrow_forwardPropose a structural formula for the analgesic phenacetin, molecular formula C10H13NO2, based on its 1H-NMR spectrum.arrow_forwardFollowing are 1H-NMR spectra for compounds B (C6H12O2) and C (C6H10O). Upon warming in dilute acid, compound B is converted to compound C. Deduce the structural formulas for compounds B and C.arrow_forward
- Ciprofloxacin is a member of the fluoroquinolone class of antibiotics.(a) Which of its rings are aromatic?(b) Which nitrogen atoms are basic?(c) Which protons would you expect to appear between d 6 and d 8 in the proton NMR spectrum?arrow_forwardThe 1H-NMR spectrum of Compound C shows five signals – δ 2.38 (1H, dt), 2.72 (1H, dt), 5.34 (1H, t), 5.49 (2H, ddd), 6.27 (2H, dd) ppm. Its 13C-NMR spectrum has four signals – δ 26, 58, 127, 129 ppm. In the compound’s mass spectrum, the M+1 peak appears at m/z = 115. An M+2 peak, whose intensity is roughly one-third that of the M+1 peak, also appears. Suggest a structure for this compound.arrow_forwardAn unknown compound C3H2NCl shows moderately strong IR absorptions around 1650 cm-1 and 2200 cm-1. Its NMR spectrum consists of two doublets (J = 14 Hz) at δ 5.9 and δ 7.1. Propose a structure consistent with this data?arrow_forward
- Analyze the 1H AND 13C NMR spectrum of C8H9NO given below and draw the structure of the compound.arrow_forwardThe H1H1 NMR spectra corresponds to an alcohol with the molecular formula C5H12O. Deduce the structure from the spectraarrow_forwardA hydrocarbon, compound B, has molecular formula C6H6, and gave an NMR spectrum with two signals: delta 6.55 pm and delta 3.84 pm with peak ratio of 2:1. When warmed in pyridine for three hr, compound B quantitatively converts to benzene. Mild hydrogenation of B yielded another compound C with mass spectrum of m/z 82. Infrared spectrum showed no double bonds; NMR spectrum showed one broad peak at delta 2.34 ppm. With this information, address the following questions. a) How many rings are in compound C? b) How many rings are probably in B? How many double bonds are in B? c) Can you suggest a structure for compounds B and C? d) In the NMR spectrum of B, the up-field signal was a quintet, and the down field signal was a triplet. How must you account for these splitting patterns?arrow_forward
- The 13C NMR spectrum of 1-bromo-3-chloropropane contains peaks at δ 30, δ 35, and δ 43. Assign these signals to the appropriate carbons.arrow_forwardDraw the structure of C3H8O and indicate which sets of hydrogens correspond to which signal in the H NMR spectrum.arrow_forwardCompound X (molecular formula C10H12O) was treated with NH2NH2, −OH to yield compound Y (molecular formula C10H14). Based on the 1HNMR spectra of X and Y given below, what are the structures of X and Y?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning