   Chapter 19, Problem 35P

Chapter
Section
Textbook Problem

A wire is formed into a circle having a diameter of 10.0 cm and is placed in a uniform magnetic field of 3.00 mT. The wire carries a current of 5.00 A. Find the maximum torque on the wire.

To determine
The maximum torque on the wire.

Explanation

Given info: The diameter of the circular wire is 10.0cm . The magnitude of the uniform magnetic field is 3.00mT . The wire carries a current of 5.00A .

Explanation:

The torque applied on a circular loop is given by,

τ=nBIAsinθ

• n is the number of turns in the loop
• B is the magnetic field
• I is the current on the wire
• A is the area enclosed by the loop
• θ is the angle between the line normal to the plane of the loop and the magnetic field

For maximum torque the angle has to be 90° .

The area of the circular loop will be,

A=πd24

• d is the diameter of the circle

Hence the torque will become,

τ=nBI(πd24)sinθ

Substitute 1 for n , 10.0cm for d , 3.00mT for B , 5.00A for I , 90° for θ to determine the torque,

τ=(1)(3

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