To construct: the stem plot on the basis of given data.

Question

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Answer 1

Question

Chapter 2, Problem 2.67RE

(a)

To determine

To construct: the stem plot on the basis of given data.

(a)

Expert Solution

Explanation of Solution

Given:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 1

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 2

By seeing the stem-leaf plot minimum and maximum values are 46 and 93 respectively so the spread of the data will be 46 to 93. Median is at 69 and 1^s^t quartile and 3^r^d quartile are 63 and 78.75 respectively. Inter quartile range is 15 and the mode which is 67 because of highest frequency of the number. There is no outlier and distribution is slightly positive skewed or right skewed.

(b)

To determine

To construct: the histogram on the basis of given data and explain the shape, centre and spread of the distribution and about the outlier.

(b)

Expert Solution

Explanation of Solution

Given:

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 3

The representing the histogram looks symmetric because of centre in the middle and median would be around 70 to 75 while the minimum and maximum values are 45 and 98 respectively so the spread of the data would be between 45 and 48.

(c)

To determine

To Explain: that which plot is better a stem plot or histogram.

(c)

Expert Solution

Answer to Problem 2.67RE

Histogram

Explanation of Solution

By seeing the both the plot, it is observed that pattern of both the plot is approximately similar but the pattern of histogram is better than stem plot because the stem plot lies in its favour compared to the histogram.

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Answer 2

Question

Chapter 2, Problem 2.67RE

(a)

To determine

To construct: the stem plot on the basis of given data.

(a)

Expert Solution

Explanation of Solution

Given:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 1

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 2

By seeing the stem-leaf plot minimum and maximum values are 46 and 93 respectively so the spread of the data will be 46 to 93. Median is at 69 and 1^s^t quartile and 3^r^d quartile are 63 and 78.75 respectively. Inter quartile range is 15 and the mode which is 67 because of highest frequency of the number. There is no outlier and distribution is slightly positive skewed or right skewed.

(b)

To determine

To construct: the histogram on the basis of given data and explain the shape, centre and spread of the distribution and about the outlier.

(b)

Expert Solution

Explanation of Solution

Given:

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 3

The representing the histogram looks symmetric because of centre in the middle and median would be around 70 to 75 while the minimum and maximum values are 45 and 98 respectively so the spread of the data would be between 45 and 48.

(c)

To determine

To Explain: that which plot is better a stem plot or histogram.

(c)

Expert Solution

Answer to Problem 2.67RE

Histogram

Explanation of Solution

By seeing the both the plot, it is observed that pattern of both the plot is approximately similar but the pattern of histogram is better than stem plot because the stem plot lies in its favour compared to the histogram.

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Answer 3

Question

Chapter 2, Problem 2.67RE

(a)

To determine

To construct: the stem plot on the basis of given data.

(a)

Expert Solution

Explanation of Solution

Given:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 1

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 2

By seeing the stem-leaf plot minimum and maximum values are 46 and 93 respectively so the spread of the data will be 46 to 93. Median is at 69 and 1^s^t quartile and 3^r^d quartile are 63 and 78.75 respectively. Inter quartile range is 15 and the mode which is 67 because of highest frequency of the number. There is no outlier and distribution is slightly positive skewed or right skewed.

(b)

To determine

To construct: the histogram on the basis of given data and explain the shape, centre and spread of the distribution and about the outlier.

(b)

Expert Solution

Explanation of Solution

Given:

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 3

The representing the histogram looks symmetric because of centre in the middle and median would be around 70 to 75 while the minimum and maximum values are 45 and 98 respectively so the spread of the data would be between 45 and 48.

(c)

To determine

To Explain: that which plot is better a stem plot or histogram.

(c)

Expert Solution

Answer to Problem 2.67RE

Histogram

Explanation of Solution

By seeing the both the plot, it is observed that pattern of both the plot is approximately similar but the pattern of histogram is better than stem plot because the stem plot lies in its favour compared to the histogram.

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Answer 4

Question

Chapter 2, Problem 2.67RE

(a)

To determine

To construct: the stem plot on the basis of given data.

(a)

Expert Solution

Explanation of Solution

Given:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 1

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 2

By seeing the stem-leaf plot minimum and maximum values are 46 and 93 respectively so the spread of the data will be 46 to 93. Median is at 69 and 1^s^t quartile and 3^r^d quartile are 63 and 78.75 respectively. Inter quartile range is 15 and the mode which is 67 because of highest frequency of the number. There is no outlier and distribution is slightly positive skewed or right skewed.

(b)

To determine

To construct: the histogram on the basis of given data and explain the shape, centre and spread of the distribution and about the outlier.

(b)

Expert Solution

Explanation of Solution

Given:

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 3

The representing the histogram looks symmetric because of centre in the middle and median would be around 70 to 75 while the minimum and maximum values are 45 and 98 respectively so the spread of the data would be between 45 and 48.

(c)

To determine

To Explain: that which plot is better a stem plot or histogram.

(c)

Expert Solution

Answer to Problem 2.67RE

Histogram

Explanation of Solution

By seeing the both the plot, it is observed that pattern of both the plot is approximately similar but the pattern of histogram is better than stem plot because the stem plot lies in its favour compared to the histogram.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 2, Problem 2.67RE

(a)

To determine

To construct: the stem plot on the basis of given data.

(a)

Expert Solution

Explanation of Solution

Given:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 1

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 2

By seeing the stem-leaf plot minimum and maximum values are 46 and 93 respectively so the spread of the data will be 46 to 93. Median is at 69 and 1^s^t quartile and 3^r^d quartile are 63 and 78.75 respectively. Inter quartile range is 15 and the mode which is 67 because of highest frequency of the number. There is no outlier and distribution is slightly positive skewed or right skewed.

(b)

To determine

To construct: the histogram on the basis of given data and explain the shape, centre and spread of the distribution and about the outlier.

(b)

Expert Solution

Explanation of Solution

Given:

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 3

The representing the histogram looks symmetric because of centre in the middle and median would be around 70 to 75 while the minimum and maximum values are 45 and 98 respectively so the spread of the data would be between 45 and 48.

(c)

To determine

To Explain: that which plot is better a stem plot or histogram.

(c)

Expert Solution

Answer to Problem 2.67RE

Histogram

Explanation of Solution

By seeing the both the plot, it is observed that pattern of both the plot is approximately similar but the pattern of histogram is better than stem plot because the stem plot lies in its favour compared to the histogram.

Answer 6

Chapter 2, Problem 2.67RE

(a)

To determine

To construct: the stem plot on the basis of given data.

(a)

Expert Solution

Explanation of Solution

Given:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 1

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 2

By seeing the stem-leaf plot minimum and maximum values are 46 and 93 respectively so the spread of the data will be 46 to 93. Median is at 69 and 1^s^t quartile and 3^r^d quartile are 63 and 78.75 respectively. Inter quartile range is 15 and the mode which is 67 because of highest frequency of the number. There is no outlier and distribution is slightly positive skewed or right skewed.

Answer 7

Chapter 2, Problem 2.67RE

(a)

To determine

To construct: the stem plot on the basis of given data.

Answer 8

(a)

Expert Solution

Explanation of Solution

Given:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 1

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 2

By seeing the stem-leaf plot minimum and maximum values are 46 and 93 respectively so the spread of the data will be 46 to 93. Median is at 69 and 1^s^t quartile and 3^r^d quartile are 63 and 78.75 respectively. Inter quartile range is 15 and the mode which is 67 because of highest frequency of the number. There is no outlier and distribution is slightly positive skewed or right skewed.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

(b)

To determine

To construct: the histogram on the basis of given data and explain the shape, centre and spread of the distribution and about the outlier.

(b)

Expert Solution

Explanation of Solution

Given:

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 3

The representing the histogram looks symmetric because of centre in the middle and median would be around 70 to 75 while the minimum and maximum values are 45 and 98 respectively so the spread of the data would be between 45 and 48.

Answer 13

(b)

To determine

To construct: the histogram on the basis of given data and explain the shape, centre and spread of the distribution and about the outlier.

Answer 14

(b)

Expert Solution

Explanation of Solution

Given:

Graph:

Statistics Through Applications, Chapter 2, Problem 2.67RE , additional homework tip 3

The representing the histogram looks symmetric because of centre in the middle and median would be around 70 to 75 while the minimum and maximum values are 45 and 98 respectively so the spread of the data would be between 45 and 48.

Answer 15

(b)

Expert Solution

Answer 16

(b)

Expert Solution

Answer 17

Expert Solution

Answer 18

(c)

To determine

To Explain: that which plot is better a stem plot or histogram.

(c)

Expert Solution

Answer to Problem 2.67RE

Histogram

Explanation of Solution

By seeing the both the plot, it is observed that pattern of both the plot is approximately similar but the pattern of histogram is better than stem plot because the stem plot lies in its favour compared to the histogram.

Answer 19

(c)

To determine

To Explain: that which plot is better a stem plot or histogram.

Answer 20

(c)

Expert Solution

Answer to Problem 2.67RE

Histogram

Answer 21

(c)

Expert Solution

Answer 22

(c)

Expert Solution

Answer 23

Expert Solution

Answer 24

Explanation of Solution

By seeing the both the plot, it is observed that pattern of both the plot is approximately similar but the pattern of histogram is better than stem plot because the stem plot lies in its favour compared to the histogram.